throughput

问题 In the CUDA visual profiler, version 5, I know that the "gld/st_requested_throughput" are the requested memory throughput of application. However, when I try to find the actual throughput of hardware, I am confused because there are two pairs of metrics which seem to be qualified, and they are "gld/st_throughput" and "dram_read/write_throughput". Which pair is actually the hardware throughput? And what does the other serve as? 回答1: gld/st_throughput includes transactions served by the L1 and

问题 What is the key difference between IOPS and Throughput in large data storage? Does file size have an effect on IOPS? Why? 回答1: IOPS measures the number of read and write operations per second, while throughput measures the number of bits read or written per second. Although they measure different things, they generally follow each other as IO operations have about the same size. If you have large files, you simply need more IO operations to read the entire file. The file size has no effect on

问题 I'm implementing a protocol over serial ports on Linux. The protocol is based on a request answer scheme so the throughput is limited by the time it takes to send a packet to a device and get an answer. The devices are mostly arm based and run Linux >= 3.0. I'm having troubles reducing the round trip time below 10ms (115200 baud, 8 data bit, no parity, 7 byte per message). What IO interfaces will give me the lowest latency: select, poll, epoll or polling by hand with ioctl? Does blocking or

问题 Given a chain of instructions linked by true dependencies and repeated periodically (i.e. a loop), for example (a->b->c)->(a->b->c)->... Assuming that it can be split into several shorter and independent sub-dependency chains to benefit from out-of-order execution : (a0->b0->c0)->(a0->b0->c0)->... (a1->b1->c1)->(a1->b1->c1)->... The out-of-order engine schedules each instruction to the corresponding CPU unit which have a latency and a reciprocal throughput. What is the optimal number of sub

问题 I am observing a very strange problem in a java client server application. I am sending following Runnable objects to the server at 80 requests per second. The thread pool keeps pool size equal to the request rate i.e. approximately 80 threads in the pool. My laptop is intel Core i5-3230M dual core(Windows show me 4 processor). Strange thing is that the Throughput(jos completed per second) is also 80. I could not understand this. How 4 processors and 80 threads are completing 80 jobs of 100

问题 This question is for packed, single-prec floating ops with XMM/YMM registers on Haswell. So according to the awesome , awesome table put together by Agner Fog, I know that MUL can be done on either port p0 and p1 (with recp thruput of 0.5), while only ADD is done on only port p1 (with recp thruput of 1). I can except this limitation, BUT I also know that FMA can be done on either port p0 or p1 (with recp thruput of 0.5). So it is confusing to my as to why a plain ADD would be limited to only

问题 I expected that simple intermediate stream operations, such as limit() , have very little overhead. But the difference in throughput between these examples is actually significant: final long MAX = 5_000_000_000L; LongStream.rangeClosed(0, MAX) .count(); // throughput: 1.7 bn values/second LongStream.rangeClosed(0, MAX) .limit(MAX) .count(); // throughput: 780m values/second LongStream.rangeClosed(0, MAX) .limit(MAX) .limit(MAX) .count(); // throughput: 130m values/second LongStream

问题 My app creates a 2GB file and needs to select the fastest drive on the system with enough space. I am trying to calculate throughput by creating the file, setting the length, then writing data to it sequentially as follows: FileInfo file = null; var drives = DriveInfo.GetDrives(); var stats = new List<DriveInfoStatistics>(); foreach (var drive in drives) { do { file = new FileInfo(Path.Combine(drive.RootDirectory.FullName, Guid.NewGuid().ToString("D") + ".tmp")); } while (file.Exists); try {

问题 I have one observation and want to get knowledge on Throughput calculation ,Some time Throughput is displaying in seconds,some times in minutes and some times in Hours,please any one provide exact answer to calculate throughput and when it will display in Seconds,Minutes and Hours in Jmeter Summary Report 回答1: From JMeter Docs: Throughput is calculated as requests/unit of time. The time is calculated from the start of the first sample to the end of the last sample. This includes any intervals

问题 I ran a JMeter test for 193 samples where I could see my average response time as 5915ms and Throghput as 1.19832. I just want to know how are they exactly related 回答1: TL;DR No, but yes. Both aren't related directly, but when increasing Throughput, it will probably effect server response time due to load/stress on server. If there are timeout errors response time will probably increase. But for validation or firewall errors - response time will probably decrease. There's a long explanation