templates

问题 I am editing a Woocommerce email template but am a little stuck - I need to add a few columns to the order summary table so that it contains: Quantity Product Product code Price VAT I have added the table headers that I need into 'email-order-details.php' (copied to my theme's email folder) to but not sure how to get the actual content into the table. The code from the file is below: <?php /** * Order details table shown in emails. * * This template can be overridden by copying it to

问题 I am editing a Woocommerce email template but am a little stuck - I need to add a few columns to the order summary table so that it contains: Quantity Product Product code Price VAT I have added the table headers that I need into 'email-order-details.php' (copied to my theme's email folder) to but not sure how to get the actual content into the table. The code from the file is below: <?php /** * Order details table shown in emails. * * This template can be overridden by copying it to

问题 In dll A I have a template singleton: template <class T> class Singleton { public: static T &instance() { static T _instance; return _instance; } private: //All constructors are here }; In Dll B I define a class Logger. Dlls C,D and E use the Logger and it is accessed like this: Singleton<Logger>::instance(); The problem is that each dll instantiates its own copy of Singleton<Logger>. instead of using the same singleton instance. I understand that the solution to this problem is using extern

问题 In dll A I have a template singleton: template <class T> class Singleton { public: static T &instance() { static T _instance; return _instance; } private: //All constructors are here }; In Dll B I define a class Logger. Dlls C,D and E use the Logger and it is accessed like this: Singleton<Logger>::instance(); The problem is that each dll instantiates its own copy of Singleton<Logger>. instead of using the same singleton instance. I understand that the solution to this problem is using extern

问题 Here's the definition of copy constructor, [class.copy.ctor/1]: A non-template constructor for class X is a copy constructor if its first parameter is of type X&, const X&, volatile X& or const volatile X&, and either there are no other parameters or else all other parameters have default arguments ([dcl.fct.default]). Why does the standard exclude templates as copy constructors? In this simple example, both constructors are copy constructors: struct Foo { Foo(const Foo &); // copy

问题 I am trying to customise the default query which is put in place when you click New Stored Procedure... from the Object Explorer on SQL Server Management Studio 2008. I have found how to change the 'Create Stored Procedure (New Menu)' template from the Template Explorer , however this means I will have to keep opening the template explorer rather than clicking on new stored procedure like i usually would. How can I edit the template which appears when you click New Stored Procedure... ? 回答1:

问题 I have an integer N which I know at compile time. I also have an std::array holding integers describing the shape of an N -dimensional array. I want to generate nested loops, as described bellow, at compile time, using metaprogramming techniques. constexpr int N {4}; constexpr std::array<int, N> shape {{1,3,5,2}}; auto f = [/* accept object which uses coords */] (auto... coords) { // do sth with coords }; // This is what I want to generate. for(int i = 0; i < shape[0]; i++) { for(int j = 0; j

问题 What's wrong with this code? enum LogLevel { LogLevel_Error = 1, LogLevel_Warning = 2, LogLevel_Info = 3, LogLevel_Debug = 4 }; LogLevel GetLogLevel() {return LogLevel_Debug;}; void Write(const std::string& message) {}; void Write(LogLevel level, std::stringstream& ss) { if (level > GetLogLevel()) return; Write(ss.str()); } template<typename Arg> void Write(LogLevel level, std::stringstream& ss, Arg arg) { if (level > GetLogLevel()) return; ss << arg; Write(ss.str()); } template<typename

问题 What's wrong with this code? enum LogLevel { LogLevel_Error = 1, LogLevel_Warning = 2, LogLevel_Info = 3, LogLevel_Debug = 4 }; LogLevel GetLogLevel() {return LogLevel_Debug;}; void Write(const std::string& message) {}; void Write(LogLevel level, std::stringstream& ss) { if (level > GetLogLevel()) return; Write(ss.str()); } template<typename Arg> void Write(LogLevel level, std::stringstream& ss, Arg arg) { if (level > GetLogLevel()) return; ss << arg; Write(ss.str()); } template<typename

问题 Is there a good way to get perfect forwarding for functions inside of a templated class? Specifically, in the code #include <iostream> // Forward declare a Bar struct Bar; // Two different functions that vary based on the kind of argument void printme(Bar const & bar) { std::cout << "printme: constant reference bar" << std::endl; } void printme(Bar && bar) { std::cout << "printme: r-value reference bar" << std::endl; } void printme2(Bar const & bar) { std::cout << "printme2: constant