take

问题 Friends, please I need help with this explanation: In the Ruby code below, what condition termites the loop do? It's supposed to be an infinite loop, but, how does it terminate? # Ruby code fib = Enumerator.new do |y| a = b = 1 loop do y << a a, b = b, a + b end end p fib.take(10) # => [1, 1, 2, 3, 5, 8, 13, 21, 34, 55] Your contributions will be highly appreciated. 回答1: (Source: https://rossta.net/blog/infinite-sequences-in-ruby.html) The way you have implemented the function fib allows it

问题 I am using Spark 1.5. I have a column of 30 ids which I am loading as integers from a database: val numsRDD = sqlContext .table(constants.SOURCE_DB + "." + IDS) .select("id") .distinct .map(row=>row.getInt(0)) This is the output of numsRDD : numsRDD.collect.foreach(println(_)) 643761 30673603 30736590 30773400 30832624 31104189 31598495 31723487 32776244 32801792 32879386 32981901 33469224 34213505 34709608 37136455 37260344 37471301 37573190 37578690 37582274 37600896 37608984 37616677

问题 With the following code shows a preview of the camera vertically and it's works.. BUT!! I get a photo in landscape! :( How I can build it vertically? I've the preview view in vertical, but I can't save the picture vertically. greetings and thanks, Fran ONCLICK public void onClick(View arg0) { camera.takePicture(myShutterCallback, myPictureCallback_RAW, myPictureCallback_JPG); } PREVIEW @Override public void surfaceChanged(SurfaceHolder holder, int format, int width, int height) { if

问题 With the following code shows a preview of the camera vertically and it's works.. BUT!! I get a photo in landscape! :( How I can build it vertically? I've the preview view in vertical, but I can't save the picture vertically. greetings and thanks, Fran ONCLICK public void onClick(View arg0) { camera.takePicture(myShutterCallback, myPictureCallback_RAW, myPictureCallback_JPG); } PREVIEW @Override public void surfaceChanged(SurfaceHolder holder, int format, int width, int height) { if

问题 This query was working for me until recently. I now have 135 InstallationSummary documents in my RavenDB. Instead of getting the most recent by start time, it's mostly working, but the last couple, most recent documents aren't showing up from this query. Am I querying incorrectly? Is there a different way to do OrderByDescending and Take with RavenDB that I should be aware of? Is there a document number limit to what I can query correctly? Note: I have debugged this, and the query indeed

问题 This query was working for me until recently. I now have 135 InstallationSummary documents in my RavenDB. Instead of getting the most recent by start time, it's mostly working, but the last couple, most recent documents aren't showing up from this query. Am I querying incorrectly? Is there a different way to do OrderByDescending and Take with RavenDB that I should be aware of? Is there a document number limit to what I can query correctly? Note: I have debugged this, and the query indeed

问题 I was browsing this question and some similar ones: Getting a sub-array from an existing array Many places I read answers like this: Getting a sub-array from an existing array What I am wondering is why Skip and Take are not constant time operations for arrays? In turn, if they were constant time operations, won't the Skip and Take method (without calling ToArray() at the end) have the same running time without the overhead of doing an Array.Copy, but also more space efficient? 回答1: You have

问题 How to take cassandra snapshot without nodetool but by java api only? I need to take snapshot of keyspace in cassandra by not using nodetool utility. I have to do it by java api If any one know how to do it kindly answer it . I have to implement.. 回答1: You can't take a snapshot using the thrift API, but you can take a snapshot using JMX, which is how the nodetool command works. Look at the node tool source here, in particular look at the handleSnapshot method. 来源： https://stackoverflow.com

问题 numpy.take can be applied in 2 dimensions with np.take(np.take(T,ix,axis=0), iy,axis=1 ) I tested the stencil of the discret 2-dimensional Laplacian ΔT = T[ix-1,iy] + T[ix+1, iy] + T[ix,iy-1] + T[ix,iy+1] - 4 * T[ix,iy] with 2 take-schemes and the usual numpy.array scheme. The functions p and q are introduced for a leaner code writing and adress the axis 0 and 1 in different order. This is the code: nx = 300; ny= 300 T = np.arange(nx*ny).reshape(nx, ny) ix = np.linspace(1,nx-2,nx-2,dtype=int)

问题 This question already has answers here : Split List into Sublists with LINQ (29 answers) Closed 6 years ago . How would one take a List (using LINQ) and break it into a List of Lists partitioning the original list on every 8th entry? I imagine something like this would involve Skip and/or Take, but I'm still pretty new to LINQ. Edit: Using C# / .Net 3.5 Edit2: This question is phrased differently than the other "duplicate" question. Although the problems are similar, the answers in this