subset-sum

Find all numbers that sum closest to a given number python

我只是一个虾纸丫 提交于 2021-02-20 05:13:37
问题 I have a script below that gives the closest 2 values to a given sum. It also iterates through a list of given sums and after each iteration removes the numbers that have already been used. I need to modify this script so that it produces a necessary amount of values closest to each sum, rather than 2. The script needs to accept float values and cannot re-use values. Effectively it needs to pick the most efficient set closest to target, update the set to remove values used, then move on to

Find all numbers that sum closest to a given number python

陌路散爱 提交于 2021-02-20 05:13:06
问题 I have a script below that gives the closest 2 values to a given sum. It also iterates through a list of given sums and after each iteration removes the numbers that have already been used. I need to modify this script so that it produces a necessary amount of values closest to each sum, rather than 2. The script needs to accept float values and cannot re-use values. Effectively it needs to pick the most efficient set closest to target, update the set to remove values used, then move on to

Finding the maximum sum that can be formed from a set, by partitioning it into two subset

一世执手 提交于 2021-02-17 02:55:08
问题 Decription Given a set of numbers S. Find maximum sum such that Sum(A 1 ) = Sum(A 2 ) Where, A 1 ⊂S and A 2 ⊂S and A 1 ⋂A 2 =∅ And Sum(X), is the sum of all elements within the set X. Approach Brute Force The easiest approach is: print maximumSum(0,0,0) def maximumSum(index,sum1,sum2): ans=0 if sum1 == sum2: ans=sum1 if index >= len(S): return ans m1=maximumSum(index+1,sum1+S[index],sum2) m2=maximumSum(index+1,sum1,sum2+S[index]) m3=maximumSum(index+1,sum1,sum2) return max(m,m1,m2,m3) Time

Finding the maximum sum that can be formed from a set, by partitioning it into two subset

那年仲夏 提交于 2021-02-17 02:54:07
问题 Decription Given a set of numbers S. Find maximum sum such that Sum(A 1 ) = Sum(A 2 ) Where, A 1 ⊂S and A 2 ⊂S and A 1 ⋂A 2 =∅ And Sum(X), is the sum of all elements within the set X. Approach Brute Force The easiest approach is: print maximumSum(0,0,0) def maximumSum(index,sum1,sum2): ans=0 if sum1 == sum2: ans=sum1 if index >= len(S): return ans m1=maximumSum(index+1,sum1+S[index],sum2) m2=maximumSum(index+1,sum1,sum2+S[index]) m3=maximumSum(index+1,sum1,sum2) return max(m,m1,m2,m3) Time

Find all k-size subsets with sum s of an n-size bag of duplicate unsorted positive integers

痴心易碎 提交于 2021-02-04 18:11:10
问题 Please note that this is required for a C# .NET 2.0 project ( Linq not allowed ). I know very similar questions have been asked here and I have already produce some working code (see below) but still would like an advice as to how to make the algorithm faster given k and s conditions. This is what I've learnt so far: Dynamic programming is the most efficient way to finding ONE (not all) subsets. Please correct me if I am wrong. And is there a way of repeatedly calling the DP code to produce

Subset sum recursively in Python

时光怂恿深爱的人放手 提交于 2020-01-30 05:11:47
问题 I will be happy to get some help. I have the following problem: I'm given a list of numbers seq and a target number and I need to write 2 things: A recursive solution that returns True if there is a sum of a subsequence that equals the target number and False otherwise. example: subset_sum([-1,1,5,4],0) # True subset_sum([-1,1,5,4],-3) # False Secondly, I need to write a solution using what I wrote in the previous solution but now with memoization that uses a dictionary in which the keys are

Subset sum recursively in Python

这一生的挚爱 提交于 2020-01-30 05:11:09
问题 I will be happy to get some help. I have the following problem: I'm given a list of numbers seq and a target number and I need to write 2 things: A recursive solution that returns True if there is a sum of a subsequence that equals the target number and False otherwise. example: subset_sum([-1,1,5,4],0) # True subset_sum([-1,1,5,4],-3) # False Secondly, I need to write a solution using what I wrote in the previous solution but now with memoization that uses a dictionary in which the keys are