sorted

How to know if a binary tree is ordered scheme

由 左心房为你撑大大i 提交于 2019-12-13 04:59:29
问题 A binary tree is ordered if all its children are under the left branch that the data of the root and branch of the right age and, in turn, binary trees of the left and right branches are also sorted. Write the procedure (ordered-btree? btree) receiving a binary tree as argument and returns True if ordered and false if not. How can I do this? 回答1: There are several ways to solve this problem. I'll assume that there are no repeated elements in the tree and that you have written helper

Java: What is the best way to find elements in a sorted List?

由 橙三吉。 提交于 2019-12-12 12:00:33
问题 I have a List<Cat> sorted by the cats' birthdays. Is there an efficient Java Collections way of finding all the cats that were born on January 24th, 1983? Or, what is a good approach in general? 回答1: Collections.binarySearch(). Assuming the cats are sorted by birthday, this will give the index of one of the cats with the correct birthday. From there, you can iterate backwards and forwards until you hit one with a different birthday. If the list is long and/or not many cats share a birthday,

A data structure traversable by both order of insertion and order of magnitude

由 淺唱寂寞╮ 提交于 2019-12-11 16:28:17
问题 Is there a data structure that can be traversed in both order of insertion and order of magnitude in O(n) with at most O(log(n)) insertion and deletion? In other words given elements 5, 1, 4, 3, 2 (inserted in this order), it can be traversed either as 1,2,3,4,5 or as 5,1,4,3,2 in O(n) time. Of course I could use an array and simply sort it before traversing, but this would require an O(n*log(n)) pre-traversal step. Also, I could use a multi-linked list to achieve O(n) traversal, but in this

insert to sorted position linked list

由 懵懂的女人 提交于 2019-12-11 12:27:10
问题 I have question quite much related to this one I asked a while ago place a value in the sorted position immediately I wonder if you can use the same approach in that you step backward in a linked list to find the position it should be inserted into. If it is possible how do you loop a linked list backward? I can't figure it out because it seems not possible since it should be a double linked listed then if I'm not wrong? Anyway I'm working with singly linked list. EDIT I think I'm going for

C# alternative for the C++ STL set<T>

由 孤街浪徒 提交于 2019-12-10 21:52:39
问题 I'm looking for a sorted data structure, that will be similar to the STL set(T). I found SortedList, but it requires (key, val), I'm looking for something like List(string) - only sorted. I found on the web Spring.Collections, but my framework does not recognize it. Is there a simple SortedSet I could use in the regular basic framework? Thanks, Gal 回答1: You can do this with A System.Collections.Generic.Dictionary. Here's a good article: Dictionarys and sorting Edit: The SortedDictionary seems

Interpolation search on strings

由 牧云@^-^@ 提交于 2019-12-09 04:51:48
问题 For those of you not familiar with interpolation search, it is method to search for a value in a sorted array that is potentially faster than binary search. You look at the first and last element and (assuming that the contents of the array are uniformly distributed) linearly interpolate to predict the location. For example: we have an array of length 100 with array[0]=0 and array[99]=99. If we are looking for 80, it is intuitive to try array[80] over array[50], and if the array is close to

Convert Sorted Array to Binary Search Tree (Picturing the Recursion)

由 杀马特。学长 韩版系。学妹 提交于 2019-12-06 09:02:56
I want to convert a sorted integer array into a binary search tree. I believe I understand how to do this. I have posted my pseudo-code below. What I cannot picture is how the recursion actually works. So if my array is 1, 2, 3, 4, 5... I first make 3 the root of my BST. Then I make 2 the left-child node of 3. Then do I make 1 the left-child node of 2, and come back to 2? I don't get how the recursion steps through the whole process... Thanks in advance, and apologies if this question is poorly explained. I don't want explicit code, but I would really appreciate if someone could help me go

Data structure for efficiently returning the top-K entries of a hash table (map, dictionary)

由 ≯℡__Kan透↙ 提交于 2019-12-04 07:21:46
Here's a description: It operates like a regular map with get , put , and remove methods, but has a getTopKEntries(int k) method to get the top-K elements, sorted by the key: For my specific use case, I'm adding, removing, and adjusting a lot of values in the structure, but at any one time there's approximately 500-1000 elements; I want to return the entries for the top 10 keys efficiently. I call the put and remove methods many times. I call the getTopKEntries method. I call the put and remove methods some more times. I call the getTopKEntries method. ... I'm hoping for O(1) get , put , and

[LeetCode] 252. Meeting Rooms

由 ▼魔方 西西 提交于 2019-12-03 02:47:10
会议室。给的input是一个二维数组，二维数组里面的每一个元素记录了每个会议的开始时间和结束时间。问同一个人是否有可能参加所有的会议。 Example 1: Input: [[0,30],[5,10],[15,20]] Output: false Example 2: Input: [[7,10],[2,4]] Output: true 思路很简单，但是这是LC上算是一种比较特别的题型 - 扫描线。这题的思路是按照会议开始时间给input排序，如果有任何一个会议的结束时间 > 下一个会议的开始时间，就return false。 时间O(nlogn) 空间O(1) 1 /** 2 * @param {number[][]} intervals 3 * @return {boolean} 4 */ 5 var canAttendMeetings = function(intervals) { 6 let sorted = intervals.sort((a, b) => a[0] - b[0]); 7 for (let i = 1; i < intervals.length; i++) { 8 if (sorted[i - 1][1] > sorted[i][0]) { 9 return false; 10 } 11 } 12 return true; 13 }; 来源： https:
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