sorted

Is it possible to use CUDA in order to compute the frequency of elements inside a sorted array efficiently?

六眼飞鱼酱① 提交于 2021-02-16 20:54:26
问题 I'm very new to Cuda, I've read a few chapters from books and read a lot of tutorials online. I have made my own implementations on vector addition and multiplication. I would like to move a little further, so let's say we want to implement a function that takes as an input a sorted array of integers. Our goal is to find the frequencies of each integer that is in the array. Sequentially we could scan the array one time in order to produce the output. The time complexity would be O(n) . Since

Why does python think my array is 0-d? (TypeError: iteration over a 0-d array) [duplicate]

时间秒杀一切 提交于 2021-01-28 04:52:45
问题 This question already has answers here : how to read array of numbers from text file in python (2 answers) Closed 4 years ago . I'm aware that this may have been answered before but please check that other answers are relevant to this instance! I'm writing an array to a file as a string so that it can be stored when my script isn't running and be accessed again easily when run. When I then read this string out of the file again it is automatically read as a string. I can fix this with a for

LeetCode: Median of Two Sorted Arrays

纵然是瞬间 提交于 2020-03-27 17:10:32
https://leetcode.com/problems/median-of-two-sorted-arrays/solution/ http://www.cnblogs.com/yuzhangcmu/p/4138184.html http://blog.csdn.net/gao1440156051/article/details/51725845 http://blog.csdn.net/linhuanmars/article/details/19905515 class Solution { public: double findMedianSortedArrays(int A[], int m, int B[], int n) { int size = m + n; if (size & 0x1){ return findKth(A,m,B,n,size/2+1); }else{ double a = findKth(A,m,B,n,size/2); double b = findKth(A,m,B,n,size/2+1); //cout<<a<<" "<<b<<endl; return (a + b)/2; } //return mergeSort(A,m,B,n); } double findKth(int A[], int m, int B[],int n, int

LeetCode 21 链表 Merge Two Sorted Lists

放肆的年华 提交于 2020-03-04 00:21:20
LeetCode 21 链表 Merge Two Sorted Lists LeetCode Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists. Example: Input: 1->2->4, 1->3->4 Output: 1->1->2->3->4->4 代码: 递归 class Solution { public ListNode mergeTwoLists(ListNode l1, ListNode l2) { if(l1 == null) return l2; if(l2 == null) return l1; if(l1.val < l2.val){ l1.next = mergeTwoLists(l1.next, l2); return l1; }else{ l2.next = mergeTwoLists(l1, l2.next); return l2; } } } 迭代 class Solution { public ListNode mergeTwoLists(ListNode l1, ListNode l2) { ListNode

JDK1.8常用语法

倖福魔咒の 提交于 2020-03-03 08:27:50
stream 部分用法 https://mp.weixin.qq.com/s/yS61Bbvlj5eOfEGpJR4gQA Max和Min // 求对象某属性的最小值 Ab ab = list.stream().min(Comparator.comparing(Ab::getCount)).get(); // 直接求最小值 Integer integer = Stream.of(8, 2, 3).min(Comparator.comparing(Integer::intValue)).get(); Map(T -> R) 替换list中的某个值,将流中的每一个元素T映射为R(类似类型转换) # map用法, 将 list中的值都减1 lists.stream().map(aa -> aa - 1).collect(Collectors.toList()); #至取出对象中的某个属性 asList(new Ae("张三"), new Ae("李四"), new Ae("高五")).stream().map(Ae::getName).forEach(System.out::println); flatMap 将list合并。将流中的每一个元素 T 映射为一个流,再把每一个流连接成为一个流 Stream.of(int1, int2).flatMap(as -> as.stream())

Why insertion sort is best algorithm for sorted or nearly sorted array?

时光总嘲笑我的痴心妄想 提交于 2020-02-29 04:28:09
问题 So i guess its because it just compares A[k] and A[k-1], and does the implementation in one sweep but its still not clear. Can someone explain better. Thanks 回答1: This link shows a graphical representation of sorting algorithm with different types of data set . As you can see, when the data is sorted the algorithm complexity is reduced to N. Which is equivalent to the number of elements as inputs. The link provided gives a clear picture of how its more efficient. 回答2: You answered your own

sorting distance in MySQL PHP [duplicate]

こ雲淡風輕ζ 提交于 2020-02-08 10:18:05
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: mysql_fetch_array() expects parameter 1 to be resource, boolean given in select My Code: <?php $Sql="SELECT *, (3959 * acos(cos(radians(37)) * cos(radians(44)) * cos(radians(55) - radians(-122)) + sin(radians(37)) * sin(radians(44))) as distance FROM TableName HAVING distance < 25 ORDER BY distance LIMIT 0 , 20"; $result=mysql_query($Sql); while ($row = mysql_fetch_array($result)){ echo $row['Id']; } Error:

Python中sort 和 sorted函数

天大地大妈咪最大 提交于 2020-02-06 01:01:14
一、介绍 sort函数是list列表中的函数,而sorted可以对list或者iterator进行排序 二、sort和sorted的比较 1、用sort函数对列表排序时会影响列表本身,而sorted不会 举例: >>> a = [1,2,1,4,3,5] >>> a.sort() >>> a [1, 1, 2, 3, 4, 5]    >>> a = [1,2,1,4,3,5] >>> sorted(a) [1, 1, 2, 3, 4, 5] >>> a[1, 2, 1, 4, 3, 5]    2、 sorted ( iterable,cmp,key,reverse) 参数:iterable可以是list或者iterator; cmp是带两个参数的比较函数; key 是带一个参数的函数; reverse为False或者True; 举例说明 (1)用cmp函数排序 >>> list1 = [('david', 90), ('mary',90), ('sara',80),('lily',95)] >>> sorted(list1,cmp = lambda x,y: cmp(x[0],y[0])) [('david', 90), ('lily', 95), ('mary', 90), ('sara', 80)] >>> sorted(list1,cmp = lambda x,y:

java8 stream多字段排序

对着背影说爱祢 提交于 2020-01-27 05:45:59
转载自: https://www.cnblogs.com/kuanglongblogs/p/11230250.html List<类> list; 代表某集合 //返回 对象集合以类属性一升序排序 list.stream().sorted(Comparator.comparing(类::属性一)); //返回 对象集合以类属性一降序排序 注意两种写法 list.stream().sorted(Comparator.comparing(类::属性一).reversed());//先以属性一升序,结果进行属性一降序 list.stream().sorted(Comparator.comparing(类::属性一,Comparator.reverseOrder()));//以属性一降序 //返回 对象集合以类属性一升序 属性二升序 list.stream().sorted(Comparator.comparing(类::属性一).thenComparing(类::属性二)); //返回 对象集合以类属性一降序 属性二升序 注意两种写法 list.stream().sorted(Comparator.comparing(类::属性一).reversed().thenComparing(类::属性二));//先以属性一升序,升序结果进行属性一降序,再进行属性二升序 list.stream()

Insert into an already-sorted list

China☆狼群 提交于 2020-01-14 09:48:08
问题 With Java, I have a class, known as TestClass, which has a member named Name, which is a string. I also have an ArrayList of this type, which is already sorted alphabetically by Name. What I want to do is find the best index in which to put a new instance of TestClass. The best approach I could come up with so far is this: public static int findBestIndex(char entry, ArrayList<TestClass> list){ int desiredIndex = -1; int oldPivot = list.size(); int pivot = list.size()/2; do { char test = list