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How to slide pages in Corona SDK

由 天涯浪子 提交于 2020-01-05 07:45:09
问题 I'm using CORONA SDK. I have a set of pages and I would like to slide between them using swipe left -right. The page contains a set of controls (mostly text) What is the best way to do this slide/swipe in Corona? 回答1: Using touch events. When the phase of event is "began" (The user just touched the screen), allow the three pages to move (the actual, the forwards and the backwards). if event.phase == "began" then page1.canMove = true page2.canMove = true page3.canMove = true initial = {}

How to slide pages in Corona SDK

由 笑着哭i 提交于 2020-01-05 07:45:08
问题 I'm using CORONA SDK. I have a set of pages and I would like to slide between them using swipe left -right. The page contains a set of controls (mostly text) What is the best way to do this slide/swipe in Corona? 回答1: Using touch events. When the phase of event is "began" (The user just touched the screen), allow the three pages to move (the actual, the forwards and the backwards). if event.phase == "began" then page1.canMove = true page2.canMove = true page3.canMove = true initial = {}

Prevent map from repositioning when clicking a marker (Google Map v3)

由 此生再无相见时 提交于 2020-01-05 06:19:45
问题 Markers open a window containing a couple paragraphs of text. When users click a marker, the map repositions itself (typically shifting the map north) to display the pop-up. Is there a method for preventing this repositioning action? 回答1: Set the disableAutoPan option: infowindow.setOptions({disableAutoPan: true}); Documentation here 来源： https://stackoverflow.com/questions/14596635/prevent-map-from-repositioning-when-clicking-a-marker-google-map-v3

Delay page change on Submit - jQuery

由 |▌冷眼眸甩不掉的悲伤 提交于 2020-01-05 05:26:12
问题 Header $(document).ready(function() { $('#user_box').animate({width: "263px"}, "slow"); $('#submit').click(function(){ $('#user_box').animate({width: "0px"}, "slow"); }); }); Content <div id="user_box"> <form name="login_form" id="login_form" method="post" action="index.php"> Username:<br /> <input type="text" name="username"><br /> <input type="submit" value="Submit" id="submit" /> </form> </div> As you can see, I've made it do when submit is clicked, the user_box animates back to 0pxs

jquery slideToggle call once

由 邮差的信 提交于 2020-01-05 03:43:27
问题 That just could be very simple, but it's about 2AM and getting quite sleepy :) I have short script which "slideToggle" div from being non-displayed. $('#cmnt_add').click(function () { $('.dark_div_add').slideToggle(1100); }); Is there a chance to make it workout once, so if non-displayed DIV is opened, clicking same link won't do a thing? Thank you in advance! 回答1: Use .one() : $('#cmnt_add').one("click", function () { $('.dark_div_add').slideToggle(1100); }); From jQuery's documentation:

reversing the jquery fade slide panel

由 与世无争的帅哥 提交于 2020-01-04 18:20:10
问题 Regarding the post about the jquery fade slide panel (http://stackoverflow.com/q/10061847/1688202). I was wondering if the method could be reserved? So that the content panel will be standard visible and when clicked on disappear. It tried to change some variable in the JQuery code, but I did not manage to successfully do this. The code below has been written by Shef (http://stackoverflow.com/users/645186/shef) SOLVED BY BATMAN .panel.default { display:block; } .panel.default .content{

jquery轮播（自动+下标）

由 穿精又带淫゛_ 提交于 2020-01-04 11:19:24
主要是 要元旦了 事情多 所以就先发了 有不足的地方 请多指出。 1、HTML <div class="slideBox" id="slideBox"> 　　<div class="btn"> 　　　　<span class="left"><</span> 　　　　<span class="right">></span> 　　</div> 　　<div class="slide slide01"> 　　　　<a href="javascript:" class="pic"><img src="images/01.jpg"></a> 　　　　<span class="txt"><a href="#">图片1</a></span> 　　</div> 　　<div class="slide slide02"> 　　　　<a href="javascript:" class="pic"><img src="images/02.jpg"></a> 　　　　<span class="txt"><a href="#">图片2</a></span> 　　</div> 　　<div class="slide slide03"> 　　　　<a href="javascript:" class="pic"><img src="images/03.jpg"></a> 　　　　<span class=

Custom JQuery Slider (auto-slide)

由 岁酱吖の 提交于 2020-01-03 04:51:15
问题 I'm trying to make image slider with my own without using plugins. 1st question : How to make the animation horizontally 2nd question : Whatever the size of the image, it must cover the height and width of its container, but keeping the proportionalities original image. The image can be rendered partially. How to make this? 3rd question : About the code of the slide, if anyone finds any improvement to make it lighter and more elegant, would be welcome. $(function(){ setInterval(function(){

jquery - how do i make a div slide left 100px everytime i click a link

由 纵饮孤独 提交于 2020-01-02 20:09:50
问题 What i have so far is this $(function(){ $("#click").click(function(){ $("#slide").animate({marginLeft:'100px'},'slow'); }); }); Heres a link to a demo Which works only once, but if i try to click the link again, Nothing happens how do I make it so it works more like a slideshow? so everytime I click, it slides left 回答1: Something like this. You use += expression: $(function(){ $("#click").click(function(){ $("#slide").animate({left:'+=100px'},'slow'); }); }); 来源： https://stackoverflow.com

jQuery: Slidetoggle from bottom to top

由 荒凉一梦 提交于 2020-01-02 04:20:06
问题 I am using jQuery's slidetoggle, and I am wondering if there is a way I can make it slide up from the bottom, everywhere I look I cant seem to find the answer, here is the code I am using: jQuery(document).ready(function(){ jQuery(".product-pic").hover(function(){ jQuery(this).find('.grid-add-cart').slideToggle('2000', "easeOutBack", function() { // Animation complete. }); }); }); 回答1: Do you want to achieve something like this? HTML <div id="box"> <div id="panel"> </div> </div>​ CSS #box {
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