set

问题 This question already has answers here : How to get Case Insensitive Python SET (6 answers) How do I do a case-insensitive string comparison? (9 answers) Closed 2 years ago . I have the following script to import and export random TXT/CSV files from CLI, everything that passes has to be unique and case insensitive output in UTF-8, can I accomplish this with a set variable? I'm quite new to Python so every comment or suggestion is welcome! This is my current script; import hashlib import sys

问题 Starting with an odd list of students, let’s say 21 total: cohort = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20] I want use Python to write a function that assign pairs for group projects every day with different pairings. Since we have an odd number of students, I don’t want anyone to be working alone, so we would need to have 9 groups of 2 people and 1 group of 3 people . Every day they would change partners. For example, on day 1 and day 2, the groups would

问题 Starting with an odd list of students, let’s say 21 total: cohort = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20] I want use Python to write a function that assign pairs for group projects every day with different pairings. Since we have an odd number of students, I don’t want anyone to be working alone, so we would need to have 9 groups of 2 people and 1 group of 3 people . Every day they would change partners. For example, on day 1 and day 2, the groups would

问题 Is there a Kotlin stdlib function to find the symmetric difference between two sets? So given two sets [1, 2, 3] and [1, 3, 5] the symmetric difference would be [2, 5] . I've written this extension function which works fine, but it feels like an operation that should already exist within the collections framework. fun <T> Set<T>.symmetricDifference(other: Set<T>): Set<T> { val mine = this subtract other val theirs = other subtract this return mine union theirs } EDIT: What is the best way get

问题 Is there a Kotlin stdlib function to find the symmetric difference between two sets? So given two sets [1, 2, 3] and [1, 3, 5] the symmetric difference would be [2, 5] . I've written this extension function which works fine, but it feels like an operation that should already exist within the collections framework. fun <T> Set<T>.symmetricDifference(other: Set<T>): Set<T> { val mine = this subtract other val theirs = other subtract this return mine union theirs } EDIT: What is the best way get

问题 Q1 - Is the following a set() of a generator expression or a set comprehension ? (Or are they same? If so, are list & dict comprehensions also corresponding type-cast on generators?) my_set = {x for x in range(10)} Q2 - Does the evaluation consider duplicate values & then remove them by applying set() ? dup_set = {x for x in [0, 1, 2, 0, 1, 2]} Does the comprehension perform (speed-wise) better than regular for loops? Update - I tried using timeit for speed comparisons. Am not sure if I am

问题 I know how to pass a regular comparison class or function to set::set<>. I am writing some test code and I want to emulate some C libraries using STL's std::set and I want to be able to pass a C callback to the comparison object so a different comparison takes place. I have the following theoretical code: struct MyClass { int a; }; typedef bool (*user_callback_t)(void *, void *); class MyComparison { private: user_callback_t cb = nullptr; public: MyComparison(user_callback_t cb): cb(cb) { }

问题 I am trying to create a function that takes a list as input and returns all possible selections of a particular number of elements from a list without using the inbuilt combination() function in itertools . For example, if we pass the list [1,2,3,4] and the number 3 to such a function, the function should return [[1,2,3],[1,2,4],[1,3,4],[2,3,4]] I have created a version of this function if the number of elements to be selected is 3 but I do not know how to deal with a generic number of nested

问题 I have an array let arr = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]; I want to group it into a set of n arrays such that first n elements in result[0] next n elements in result[1] and if any element is remaining it is discarded. let sampleOutput = [[0, 1, 2, 3, 4, 5, 6], [7, 8, 9, 10, 11, 12, 13]] for n = 7; Here is my code: function group5(arr, len) { let result = []; let loop=parseInt(arr.length/len) for (let i=0; i<arr.length; i+=len) { let x = []; let limitReached = false; for

问题 I have an array let arr = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14]; I want to group it into a set of n arrays such that first n elements in result[0] next n elements in result[1] and if any element is remaining it is discarded. let sampleOutput = [[0, 1, 2, 3, 4, 5, 6], [7, 8, 9, 10, 11, 12, 13]] for n = 7; Here is my code: function group5(arr, len) { let result = []; let loop=parseInt(arr.length/len) for (let i=0; i<arr.length; i+=len) { let x = []; let limitReached = false; for