sat

Why do already popped scopes affect the check-sat time in subsequent scopes?

不想你离开。 提交于 2021-01-28 00:09:58
问题 General problem I've noticed several times that push-pop scopes that have already been popped appear to affect the time that a check-sat in a subsequent scope needs. That is, assume a program with multiple (potentially arbitrarily nested) push-pop scopes, each of which contain a check-sat command. Furthermore, assume that the second check-sat takes 10s, whereas the first one takes only 0.1s. ... (push) (assert (not P)) (check-sat) ; Could be sat, unsat or unknown (pop) ... (push) (assert (not

CNF by truth table [closed]

霸气de小男生 提交于 2021-01-04 05:33:31
问题 Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 months ago . Improve this question I have a boolean function that is presented by truth table. In total it is 10 variables and I'd like to get CNF with a reasonable length (not necessary the shortest, but short enough). How can I do it? Python script or any public available software such as

CNF by truth table [closed]

你离开我真会死。 提交于 2021-01-04 05:32:46
问题 Closed. This question does not meet Stack Overflow guidelines. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 months ago . Improve this question I have a boolean function that is presented by truth table. In total it is 10 variables and I'd like to get CNF with a reasonable length (not necessary the shortest, but short enough). How can I do it? Python script or any public available software such as

Rounding LinearExpr with google or-tools SAT solver

好久不见. 提交于 2020-07-21 07:08:53
问题 I'm creating a constraint (in Java) using or-tools SAT solver: IntVar x, y, z; IntVar[] variables = new IntVar{x, y, z}; int[] multiplier = new int{2, 3, 3}; LinearExpr expression = LinearExpr.scalProd(variables, multiplier); //2x + 3y + 3z model.addLessThan(expression, q); Where q is some given integer. The thing is that I need to round the expression result. Something like: if(expression < 25) { expression = 0; } else if(expression < 75) { expression = 50; } else if(expression < 125) {

Rounding LinearExpr with google or-tools SAT solver

南楼画角 提交于 2020-07-21 07:08:12
问题 I'm creating a constraint (in Java) using or-tools SAT solver: IntVar x, y, z; IntVar[] variables = new IntVar{x, y, z}; int[] multiplier = new int{2, 3, 3}; LinearExpr expression = LinearExpr.scalProd(variables, multiplier); //2x + 3y + 3z model.addLessThan(expression, q); Where q is some given integer. The thing is that I need to round the expression result. Something like: if(expression < 25) { expression = 0; } else if(expression < 75) { expression = 50; } else if(expression < 125) {

Rounding Non-LinearExpr with google or-tools SAT solver

与世无争的帅哥 提交于 2020-07-10 10:27:07
问题 Using CP-SAT of google or-tools I'm trying to write this constraint: q >= (50x + 100y + 150z + 200k + 250p + 300v) / (x + y + z + k + p + v) Where q is a simple integer. The thing is I need to round the right side of the equation (let's call it expression ) as follows: if(expression < 75) { expression = 50; } else if(expression < 125) { expression = 100; } else if(expression < 175) { expression = 150; } else if(expression < 225) { expression = 200; } else if(expression < 275) { expression =

How does the SCIP code treat SAT problems?

流过昼夜 提交于 2020-03-23 12:32:43
问题 I am trying to find out how SCIP treats SAT problems. In the SCIP website, it is recommended to type 'set emphasis cpsolver' in the command line for SAT problems after reading the cnf file. The SCIP solver would then do its own thing after typing 'optimize'. I am not particularly skilled in code tracing and would like to know the pathway the SCIP solver takes after typing the 'set emphasis cpsolver' command. Does this command take the SAT problem and simply call a SAT solver from elsewhere?

netty权威指南学习笔记四——TCP粘包/拆包之粘包问题解决

筅森魡賤 提交于 2020-02-07 00:25:52
  发生了粘包,我们需要将其清晰的进行拆包处理,这里采用LineBasedFrameDecoder来解决 LineBasedFrameDecoder的工作原理是它依次遍历ByteBuf中的可读字节,判断看是否有“\n”或“\r\n”,如果有,就以此为结束位置,从可读索引到结束位置区间的字节就组成一行,它是以换行为结束标志的编码器,支持携带结束符或者不携带结束符两种方式,同时支持配置单行最大长度,如果连续读取到的最大长度后仍没有发现换行符,就会抛出异常,同时忽略掉之前读到的异常码流。 StringDecoder的功能非常简单,就是将接收到的对象转换为字符串,然后继续调用后面的Handler. LineBasedFrameDecoder+StringDecoder组合就是按行切换的文本解码器。 主要思路是改造客户端和服务端的处理IO的类之前添加相应解码器,解码器之后才去调用IO处理类的Handler。 客户端改造的代码部分 TheClientServer 在处理IO的类 initChannel()方法中调用处理IO类前添加相关解码的方法 1 public class ClientChildHandler extends ChannelInitializer<SocketChannel>{ 2 @Override 3 protected void initChannel

Flow/Job Shop to Boolean satisfiability [Polynomial-time reduction] part 2

徘徊边缘 提交于 2020-01-15 12:37:36
问题 here is the continuity of my first question (Flow Shop to Boolean satisfiability [Polynomial-time reduction]). Because something is wrong and I didn't success to know where exactly. I ask for the help of StackOverFlow's masters once again :) For the sum-up of what I have for now : I have input file who look like this : 3 2 1 1 1 1 1 1 Who represents : 3 jobs, 2 shops (machines), and the duration of each job on each shop (machine). And I want for theses problems, to find the optimum C_max

Tool to solve propositional logic / boolean expressions (SAT Solver?)

戏子无情 提交于 2020-01-02 05:16:20
问题 I am new to the topic of propositional logic and boolean expressions. So this is why I need help. Here is my problem: In the car industry you have thousand of different variants of components available to choose from when you buy a car. Not every component is combinable, so for each car there exist a lot of rules that are expressed in propositional logic. In my case each car has between 2000 and 4000 rules. They look like this: A → B ∨ C ∨ D C → ¬F F ∧ G → D ... where "∧" = "and" / "∨" = "or"