row

Changing color of a row of listview according to item

穿精又带淫゛_ 提交于 2020-01-13 06:01:13
问题 I want to change the color of my Listview according to its status. I have two status, the "PENDING" that I want to change in Red Color and "COMPLETE" to Blue. How is it possible? I have no Idea since this is my first time to do it in a list view. 回答1: Something like this perhaps: Dim ListView1 As ListView = New ListView ListView1.BackColor = if(status.tolower = "pending",Color.Red, Color.Blue) Or you can colour indiviual items: Dim lvi As ListViewItem = New ListViewItem lvi.Text = "Test" lvi

R multiple conditions in row selection of matrix [duplicate]

此生再无相见时 提交于 2020-01-13 05:39:07
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: R: subset() logical-and operator for combining conditions should be & not && I have a simple question, but I don't know how to solve this... I want to select all rows where value_1 > 0 and value_2 > 0. Now I have this code: dataOnBoth<-data[data$value_1 > 0,][data$value_2 > 0,] When I head this data, ordering on log2_fold_change, I have This output: gene_id sample_1 sample_2 status value_1 value_2 log2_fold

alternate row colors using jquery

坚强是说给别人听的谎言 提交于 2020-01-12 04:35:22
问题 Using jQuery and not CSS, is it possible to alternate row colors between records? If so can anyone provide a short code script on how to accomplish this? 回答1: Try this: $("tr:even").css("background-color", "#eeeeee"); $("tr:odd").css("background-color", "#ffffff"); 回答2: Do you just not want to use CSS for cross-browser (i.e., IE) support? If so, you could keep the styling in the CSS and just use jQuery to set the class. For example: <style> /* tr:nth-child(even) */ tr.even { background-color:

Remove duplicate and count them in row

╄→гoц情女王★ 提交于 2020-01-11 14:09:30
问题 I would like to delete duplicate entries and then count them to display them next to my entries in my php ROW I've already tried this: <?php foreach (array_unique($events) as $eventorga) { $eventorgan = $eventorga['organizer']; echo $eventorga['organizer'].'</br>'; } ?> But an error: Array to string conversion is returned to me <?php foreach ($events as $eventorga) { echo $eventorga['organisateur'].'</br>'; } ?> Currently, my code returns this result: Holyblood Nessy Pokégaia Sorrow JOHN

Find the most repeated row in a matrix

我的梦境 提交于 2020-01-11 09:11:31
问题 I have about 10000 replicates of a sample in a matrix. My matrix has 1000 rows and 6 columns. Numbers in the columns range from 0:58 depending on the sample. actual.prob <- c(.14, .14, .16, .13, .19, .24) million.rep <- replicate(10000, sample(1:6, 58, replace= T, actual.prob)) new.matrix <- matrix(nrow= 10000, ncol=6) for(i in 1:10000){ new.matrix[i,] <- as.vector(table(factor(million.rep[,i], levels=1:6))) } new.matrix[1:10,] [,1] [,2] [,3] [,4] [,5] [,6] [1,] 3 7 11 11 11 15 [2,] 7 6 12 5

Find the most repeated row in a matrix

爷,独闯天下 提交于 2020-01-11 09:11:28
问题 I have about 10000 replicates of a sample in a matrix. My matrix has 1000 rows and 6 columns. Numbers in the columns range from 0:58 depending on the sample. actual.prob <- c(.14, .14, .16, .13, .19, .24) million.rep <- replicate(10000, sample(1:6, 58, replace= T, actual.prob)) new.matrix <- matrix(nrow= 10000, ncol=6) for(i in 1:10000){ new.matrix[i,] <- as.vector(table(factor(million.rep[,i], levels=1:6))) } new.matrix[1:10,] [,1] [,2] [,3] [,4] [,5] [,6] [1,] 3 7 11 11 11 15 [2,] 7 6 12 5

Find the most repeated row in a matrix

自作多情 提交于 2020-01-11 09:11:26
问题 I have about 10000 replicates of a sample in a matrix. My matrix has 1000 rows and 6 columns. Numbers in the columns range from 0:58 depending on the sample. actual.prob <- c(.14, .14, .16, .13, .19, .24) million.rep <- replicate(10000, sample(1:6, 58, replace= T, actual.prob)) new.matrix <- matrix(nrow= 10000, ncol=6) for(i in 1:10000){ new.matrix[i,] <- as.vector(table(factor(million.rep[,i], levels=1:6))) } new.matrix[1:10,] [,1] [,2] [,3] [,4] [,5] [,6] [1,] 3 7 11 11 11 15 [2,] 7 6 12 5

Find the most repeated row in a matrix

前提是你 提交于 2020-01-11 09:11:10
问题 I have about 10000 replicates of a sample in a matrix. My matrix has 1000 rows and 6 columns. Numbers in the columns range from 0:58 depending on the sample. actual.prob <- c(.14, .14, .16, .13, .19, .24) million.rep <- replicate(10000, sample(1:6, 58, replace= T, actual.prob)) new.matrix <- matrix(nrow= 10000, ncol=6) for(i in 1:10000){ new.matrix[i,] <- as.vector(table(factor(million.rep[,i], levels=1:6))) } new.matrix[1:10,] [,1] [,2] [,3] [,4] [,5] [,6] [1,] 3 7 11 11 11 15 [2,] 7 6 12 5

Remove Duplicate Cells in a Row

我的梦境 提交于 2020-01-11 07:31:29
问题 Just to clarify : I don't want to remove duplicates rows, I want to remove Duplicate Cells within a row So here's a classic address table, and in some row there's duplicate entries I need to remove those entries. Most of what I've seen in VBA is used to remove duplicates values within a column, but I can't find a way to remove duplicate values within a row. Name | Address1 | Address2 | City | Country Peter | 2 foobar street |2 foobar street | Boston | USA And I want it to be like : Name |

How to add a row dynamically in a tableLayout in Android

半腔热情 提交于 2020-01-11 03:05:07
问题 I have a function who gets a list of products from a webpage, and I want to add a row in a tableLayout for each element of the list. public void getProductsOfCategory() throws IOException{ new Thread(){ public void run(){ //background code... try { Bundle extras = getIntent().getExtras(); String categoryName = extras.getString("categoryName"); HttpGet httpget = new HttpGet("http://romal.hopto.org/foodadvisor/users/getProductsOfCategory.json?category="+categoryName); HttpResponse httpresp =