Why the RISC instruction sets usually do not contain register to register copy instruction?
问题 I had this question on my exam and i am confused because as far as i know that move $t0, $a0 # COPY $A0 TO $T0 in MIPS instruction provides that and MIPS is a RISC processor. Am I missing something? 回答1: Move is a pseudoinstruction, and when assembled will really be a different instruction. For instance move $t0, $zero gets implemented as addu $t0, $zero, $zero 来源: https://stackoverflow.com/questions/53286335/why-the-risc-instruction-sets-usually-do-not-contain-register-to-register-copy-i