rgba

问题 Exactly like the title. I take a single-band image of mode "1" and open it using image = Image.open("picture.tif") I then try to convert it to RGBA with image.convert("RGBA") And then whenever I check the mode of it using print(image.mode) I get that it's still "1". I've even tried this using "L" (which is another single-band image mode) and still no luck. No matter what I do, it won't convert. Searching the web only seems to reveal converting from "RGBA" to "1" but I haven't been able to

问题 I want to achieve the same linear gradient look defined by CSS on a canvas. Used a method that works great until no transparency setting is used. When there are rgba color values defined with the same linear gradient color settings the results doesn't look the same, please see the following link: JSFiddle: Example var canvas = document.getElementById("myCanvas"); var ctx = document.getElementById("myCanvas").getContext("2d"); var w = canvas.width; var h = canvas.height; var cssAng = Math.PI;

问题 I have a function which downloads an image, and saves the image data. Based on user preference, it can save the image data in one of two ways - as an ImageData Uint8ClampedArray, or as an ImageBitmap. I'm using an image loading function to wait until the image is loaded before running my save function: function loadImage(src) { return new Promise((resolve, reject) => { const img = new Image(); img.crossOrigin = '*'; img.addEventListener('load', () => resolve(img)); img.src = src; }); } The

问题 If I have a function which takes color as an input to be edited first (by RGB numbers), and then used in matplotlib.pyplot . How can I convert color name to RGB? For example: def function(color): color[3] = 0.5 plt.plot([1,2],[2,4], color = color) then function((0,0,1,1)) works, but function('blue') will only work on the plt.plot . How can I convert color name to RGB, (such as blue to (0,0,1,1) )? Thanks. 回答1: You can use with matplotlib.colors from matplotlib import colors print(colors.to

问题 If I have a function which takes color as an input to be edited first (by RGB numbers), and then used in matplotlib.pyplot . How can I convert color name to RGB? For example: def function(color): color[3] = 0.5 plt.plot([1,2],[2,4], color = color) then function((0,0,1,1)) works, but function('blue') will only work on the plt.plot . How can I convert color name to RGB, (such as blue to (0,0,1,1) )? Thanks. 回答1: You can use with matplotlib.colors from matplotlib import colors print(colors.to

问题 If I have a function which takes color as an input to be edited first (by RGB numbers), and then used in matplotlib.pyplot . How can I convert color name to RGB? For example: def function(color): color[3] = 0.5 plt.plot([1,2],[2,4], color = color) then function((0,0,1,1)) works, but function('blue') will only work on the plt.plot . How can I convert color name to RGB, (such as blue to (0,0,1,1) )? Thanks. 回答1: You can use with matplotlib.colors from matplotlib import colors print(colors.to

问题 I'm wondering how to convert rgba into hex in a way that translates the visible rgba-color (including transparency) into a hex value. Say I have this: rgba(0,129,255,.4) Which is sort of a "light blue"... I would like to know if there is a way to get the same light blue "visible" color in hex, so I don't want the converted #0081ff but something close to the color visible on screen. Question: How to convert rgba to a transparency-adjusted-hex? 回答1: It depends on the background to which your

问题 I'm wondering how to convert rgba into hex in a way that translates the visible rgba-color (including transparency) into a hex value. Say I have this: rgba(0,129,255,.4) Which is sort of a "light blue"... I would like to know if there is a way to get the same light blue "visible" color in hex, so I don't want the converted #0081ff but something close to the color visible on screen. Question: How to convert rgba to a transparency-adjusted-hex? 回答1: It depends on the background to which your

问题 I am following a tutorial (https://opentk.net/learn/chapter1/4-textures.html) using ImageSharp. How do I convert the type 'ImageSharp.Image' to 'ImageSharp.PixelFormats.Rgba32'? To load the Image, I am using Image<Rgba32> image = Image.Load(path); but I keep getting the error: Cannot implicitly convert type 'SixLabors.ImageSharp.Image' to 'SixLabors.ImageSharp.Image<SixLabors.ImageSharp.PixelFormats.Rgba32>'. An explicit conversion exists (are you missing a cast?). 回答1: The API change in the

问题 Let's say I have this: .example { background-color: rgba(0, 0, 0, 0.5); border-color: rgba(0, 0, 0, 0.5); } The background-color and border-color have the same rgba value, but are different colors because the border-color is calculated on top of the background-color. (simple example: http://jsfiddle.net/BBdB3/) What transparency value for the border-color would make it match the background-color? What's the math here? Edit: thanks guys, using rgba(0, 0, 0, 0) or transparency is sufficient for