reverse

问题 I have a content directory to be returned in descending natural order. I'm using scandir() and natsort() , but the addition of array_reverse() yields no results. I've been researching using a combination of opendir() and readdir() as well what ever else to affect this outcome. The items to be sorted are numbered image files. They are to be returned as: 10 9 8 7 and so on, but like from like 1000 999 998 997 ... until 0 Here's my current code: $dir = 'dead_dir/dead_content/'; $launcher =

问题 I have a content directory to be returned in descending natural order. I'm using scandir() and natsort() , but the addition of array_reverse() yields no results. I've been researching using a combination of opendir() and readdir() as well what ever else to affect this outcome. The items to be sorted are numbered image files. They are to be returned as: 10 9 8 7 and so on, but like from like 1000 999 998 997 ... until 0 Here's my current code: $dir = 'dead_dir/dead_content/'; $launcher =

问题 Here is my function that suppose to reverse and return giver integer: public static int reverse(int x) { List<Integer> digits = new ArrayList<>(); int result = 0, count = 0; while(x != 0) { digits.add(x % 10); x /= 10; count++; } System.out.println(digits); int i = 0; while(count != 0) { result += digits.get(i) * (int) Math.pow(10, count - 1); System.out.printf("result: %d i: %d, count: %d - ", result, i, count); System.out.printf("%d * %d\n", digits.get(i), (int) Math.pow(10, count - 1));

问题 How to convert a python dictionary d = {1:10, 2:20, 3:30, 4:30} to {10: [1], 20: [2], 30: [3, 4]} ? I need to reverse a dictionary the values should become the keys of another dictionary and the values should be key in a list i.e. also in the sorted matter. 回答1: d = {1:10, 2:20, 3:30, 4:30} inv = {} for key, val in d.iteritems(): inv[val] = inv.get(val, []) + [key] Try this! 回答2: Reversing keys and values in a python dict is a bit tricky. You should have in mind that a python dict must have a

问题 How to convert a python dictionary d = {1:10, 2:20, 3:30, 4:30} to {10: [1], 20: [2], 30: [3, 4]} ? I need to reverse a dictionary the values should become the keys of another dictionary and the values should be key in a list i.e. also in the sorted matter. 回答1: d = {1:10, 2:20, 3:30, 4:30} inv = {} for key, val in d.iteritems(): inv[val] = inv.get(val, []) + [key] Try this! 回答2: Reversing keys and values in a python dict is a bit tricky. You should have in mind that a python dict must have a

问题 How to convert a python dictionary d = {1:10, 2:20, 3:30, 4:30} to {10: [1], 20: [2], 30: [3, 4]} ? I need to reverse a dictionary the values should become the keys of another dictionary and the values should be key in a list i.e. also in the sorted matter. 回答1: d = {1:10, 2:20, 3:30, 4:30} inv = {} for key, val in d.iteritems(): inv[val] = inv.get(val, []) + [key] Try this! 回答2: Reversing keys and values in a python dict is a bit tricky. You should have in mind that a python dict must have a

问题 This question already has answers here : Iterating C++ vector from the end to the begin (11 answers) Closed 5 hours ago . Suppose I'm a newbie C++ programmer. I have a C++ container; say, a vector: std::vector<int> vec { 12, 34, 56, 78 }; I know I can iterate over all of the elements with a simple loop: for(std::vector<int>::size_type i = 0; i < vec.size(); i++) { std::cout << vec[i] << '\n'; } and maybe I've even learned a little about Modern C++, so I know I can use a ranged-for loop: for

问题 This question already has answers here : Iterating C++ vector from the end to the begin (11 answers) Closed 5 hours ago . Suppose I'm a newbie C++ programmer. I have a C++ container; say, a vector: std::vector<int> vec { 12, 34, 56, 78 }; I know I can iterate over all of the elements with a simple loop: for(std::vector<int>::size_type i = 0; i < vec.size(); i++) { std::cout << vec[i] << '\n'; } and maybe I've even learned a little about Modern C++, so I know I can use a ranged-for loop: for

问题 I'm doing birthday paradox, and want to know how many people can meet 0.5 probability that two people have same birthday by using python. I have tried no using mathematical formula to find probability with given the number of people by using random and randint in python import random def random_birthdays(): bdays = [] bdays = [random.randint(1, 365) for i in range(23)] bdays.sort() for x in range(len(bdays)): while x < len(bdays)-1: print x if bdays[x] == bdays[x+1]: #print(bdays[x]) return

问题 lets say im given a txt file with lines of strings, where i have to take the first 50 lines and print them in reverse order(to clarify: the line does not change, but the order changes...50th line becomes 1st, 49th becomes 2nd, etc...) and then again for the next 50 lines until all lines are reversed. So far i have multiple for loops going through 50 lines at a time and reversing them. But is there a more efficient way to do this? i was thinking of stacks, however i dont know how to manipulate