regex-negation

Notepad++ use both regular expressions and extended search

风流意气都作罢 提交于 2019-11-29 12:41:35
I need to find all \r\n that do not precede the letter M; Seems I can't do this: \r\n[^M] I can only do \r\n with extended search selected or [^M] with regular expressions selected; but not together. You should instead use this regex: \R(?!M) Explanation: \R Any Unicode newline sequence. (?!M) Negative Lookahead : Assert "M" cannot be matched. \r\n is valid with Regular expression checked in the Find tab too - i.e. not just with Extended checked: why not just use \r\n[^M] with Regular expression checked? Given the following test text... whatever M whatever G foo ..., \r\n[^M] yields the

Which would be better non-greedy regex or negated character class?

限于喜欢 提交于 2019-11-29 11:43:00
I need to match @anything_here@ from a string @anything_here@dhhhd@shdjhjs@ . So I'd used following regex. ^@.*?@ or ^@[^@]*@ Both way it's work but I would like to know which one would be a better solution. Regex with non-greedy repetition or regex with negated character class? Sebastian Proske Negated character classes should usually be prefered over lazy matching, if possible. If the regex is successful, ^@[^@]*@ can match the content between @ s in a single step, while ^@.*?@ needs to expand for each character between @ s. When failing (for the case of no ending @ ) most regex engines will

Regex Match Ampersand but not escaped xml characters

浪子不回头ぞ 提交于 2019-11-29 05:35:15
I would like to match ampersand (&) but not when it exists in following manner &apos; " > < & &# So in the following line & MY& NAME IS M&Hh. &apos; " > < & &# &&&&&& I want it to match all ampersands except those which exist in &apos; " > < & &# That looks like a job for negative lookahead assertions : &(?!(?:apos|quot|[gl]t|amp);|#) should work. Explanation: & # Match & (?! # only if it's not followed by (?: # either apos # apos |quot # or quot |[gl]t # or gt/lt |amp # or amp ); # and a semicolon | # or \# # a hash ) # End of lookahead assertion 来源: https://stackoverflow.com/questions

Regex - match anything except specific string

这一生的挚爱 提交于 2019-11-29 03:50:01
I need a regex (will be used in ZF2 routing, I believe it uses the preg_match of php) that matches anything except a specific string. For example: I need to match anything except "red", "green" or "blue". I currently have the regex: ^(?!red|green|blue).*$ test -> match (correct) testred -> match (correct) red -> doesn't match (correct) redtest -> doesn't match (incorrect) In the last case, the regex is not behaving like I want. It should match "redtest" because "redtest" is not ("red", "green" or "blue"). Any ideas of how to fix the regex? You can include the end of string anchor in the

R-regex: match strings not beginning with a pattern

时间秒杀一切 提交于 2019-11-29 03:02:40
问题 I'd like to use regex to see if a string does not begin with a certain pattern. While I can use: [^ to blacklist certain characters, I can't figure out how to blacklist a pattern. > grepl("^[^abc].+$", "foo") [1] TRUE > grepl("^[^abc].+$", "afoo") [1] FALSE I'd like to do something like grepl("^[^(abc)].+$", "afoo") and get TRUE , i.e. to match if the string does not start with abc sequence. Note that I'm aware of this post, and I also tried using perl = TRUE , but with no success: > grepl("^

How To Negate Regex [duplicate]

青春壹個敷衍的年華 提交于 2019-11-28 22:34:17
Possible Duplicate: Regular expression to match string not containing a word? How can I invert a regular expression in JavaScript? Say I have the regex foo123 . How do I match everything that is not foo123 ? Use negative lookahead for this. (?!foo123).+ matches any string except foo123 If you want to match empty string also, use (?!foo123).* In your case (according to the comment) the required regex is (?!P[0-9]{1,}).+ . It matches P and 123 , but not P123 . 来源: https://stackoverflow.com/questions/14682905/how-to-negate-regex

C# Regex to match a string that doesn't contain a certain string?

拜拜、爱过 提交于 2019-11-28 20:22:17
I want to match any string that does not contain the string "DontMatchThis". What's the regex? try this: ^(?!.*DontMatchThis).*$ Wiktor Stribiżew The regex to match a string that does not contain a certain pattern is (?s)^(?!.*DontMatchThis).*$ If you use the pattern without the (?s) (which is an inline version of the RegexOptions.Singleline flag that makes . match a newline LF symbol as well as all other characters), the DontMatchThis will only be searched for on the first line, and only a string without LF symbols will be matched with .* . Pattern details : (?s) - a DOTALL/Singleline

replace characters in notepad++ BUT exclude characters inside single quotation marks(2nd)

不想你离开。 提交于 2019-11-28 11:34:38
问题 replace characters in notepad++ BUT exclude characters inside single quotation marks Sorry to all users (especially to Avinash Raj) who answered already 1st similiar question - I did simply forget the 2nd kind of string. (And (that is the sad thing) - I'm not able to adjust the solution from 1st similiar question to the 2nd kind of string...) I have TWO different strings in this kind: SELECT column_name FROM table_name WHERE column_name IN ('A' , 'st9u' ,'Meyer', ....); WHERE a.object_type IN

regular expression - match word only once in line

别说谁变了你拦得住时间么 提交于 2019-11-28 07:37:17
问题 Case: ehello goodbye hellot hello goodbye ehello goodbye hello hello goodbye I want to match line 1 (only has 'hello' once!) DO NOT want to match line 2 (contains 'hello' more than once) Tried using negative look ahead look behind and what not... without any real success.. 回答1: A simple option is this (using the multiline flag and not dot-all): ^(?!.*\bhello\b.*\bhello\b).*\bhello\b.*$ First, check you don't have 'hello' twice, and then check you have it at least once. There are other ways to

Regex: match pattern as long as it's not in the beginning

血红的双手。 提交于 2019-11-28 07:25:35
Assume the following strings: aaa bbb ccc bbb aaa ccc I want to match aaa as long as it is not at the start of the string. I'm trying to negate it by doing something like this: [^^]aaa But I don't think this is right. Using preg_replace . You can use a look behind to make sure it is not at the beginning. (?<!^)aaa Since I came here via Google search, and was interested in a solution that is not using a lookbehind , here are my 2 cents. The [^^]aaa pattern matches a character other than ^ and then 3 a s anywhere inside a string. The [^...] is a negated character class where ^ is not considered