recursion

问题 I'm writing a quicksort algorithm to sort numbers with random pivot. How can I change my quicksort methods from recursive to iterative? I have one sort method which is recursive, but I need the iterative method. Is it possible to change from recursive to iterative in just the sort method or do I have to change the whole code? here is all my code public class Main { public static void main(String[] args) { long start = System.currentTimeMillis(); ArrayList time = new ArrayList(); for (int k =

问题 I'm writing a quicksort algorithm to sort numbers with random pivot. How can I change my quicksort methods from recursive to iterative? I have one sort method which is recursive, but I need the iterative method. Is it possible to change from recursive to iterative in just the sort method or do I have to change the whole code? here is all my code public class Main { public static void main(String[] args) { long start = System.currentTimeMillis(); ArrayList time = new ArrayList(); for (int k =

问题 I have a trenary tree every node got id and name how can I return true when root->id=id and break the recursion BOOLEAN isIdUsed(Trin_Ari *root,int idNumber) { if (root==NULL) return FALSE; if (root->id==idNumber) return TRUE; isIdUsed(root->left,idNumber); isIdUsed(root->middle,idNumber); isIdUsed(root->right,idNumber); return FALSE; } 回答1: You're ignoring the return values from the recursive calls to isIdUsed . Once you encounter a TRUE there, you need to propagate it upwards: BOOLEAN

问题 This question already has answers here : How does this recursion work? (11 answers) Closed 4 days ago . So there is this recursion example in chap 3 of Eloquent JavaScript, it goes like this: Consider this puzzle: by starting from the number 1 and repeatedly either adding 5 or multiplying by 3, an infinite set of numbers can be produced. How would you write a function that, given a number, tries to find a sequence of such additions and multiplications that produces that number? And the given

问题 I have a trenary tree every node got id and name how can I return true when root->id=id and break the recursion BOOLEAN isIdUsed(Trin_Ari *root,int idNumber) { if (root==NULL) return FALSE; if (root->id==idNumber) return TRUE; isIdUsed(root->left,idNumber); isIdUsed(root->middle,idNumber); isIdUsed(root->right,idNumber); return FALSE; } 回答1: You're ignoring the return values from the recursive calls to isIdUsed . Once you encounter a TRUE there, you need to propagate it upwards: BOOLEAN

问题 This question already has answers here : How does this recursion work? (11 answers) Closed 4 days ago . So there is this recursion example in chap 3 of Eloquent JavaScript, it goes like this: Consider this puzzle: by starting from the number 1 and repeatedly either adding 5 or multiplying by 3, an infinite set of numbers can be produced. How would you write a function that, given a number, tries to find a sequence of such additions and multiplications that produces that number? And the given

问题 I am trying to find the GCD of two numbers using Euclid's algorithm in C (recursively) and I do know that mathematically it's not completely perfect yet as it neglects negative number conditions, but I just want this one to work for positive numbers for now. #include <stdio.h> int gcd(int m, int n); int main() { return gcd(60, 24); } int gcd(int m, int n) { if (m < n) { //swapping both a and b m = m + n; n = m - n; m = m - n; } if (m == n) { return m; } else { return gcd(n, m % n); } } 回答1:

问题 I currently have a code which counts the palindromes in a given string and it was working fine till I tested it with "appal" the function returned 0 when it should return 2 (appa and pp) I would really appreciate it if someone can edit my current code so that it meets that requirement, thank you! Here's my code: function countPalindromes(string, count) { if (string.length <= 1) { return count; } let [ firstLetter ] = string; let lastLetter = string[string.length - 1]; if (firstLetter ===

问题 I am working with JavaScript and I use a setTimeout function in order to count up. Here is my code... <button id="star">Start</button> <p id="time">0</p> var timeEl = 0; function start() { time(); } function time() { setTimeout(function() { timeEl = timeEl + .1; timeEnd = timeEl.toFixed(1); document.getElementById("time").innerHTML = timeEnd; time(); }, 100); } var el = document.getElementById("star"); el.addEventListener("click", star, false); How do I get my setTimeout function to start on

问题 I am working with JavaScript and I use a setTimeout function in order to count up. Here is my code... <button id="star">Start</button> <p id="time">0</p> var timeEl = 0; function start() { time(); } function time() { setTimeout(function() { timeEl = timeEl + .1; timeEnd = timeEl.toFixed(1); document.getElementById("time").innerHTML = timeEnd; time(); }, 100); } var el = document.getElementById("star"); el.addEventListener("click", star, false); How do I get my setTimeout function to start on