readxml

How to read XML file in JMeter?

由 筅森魡賤 提交于 2019-12-21 20:18:27
问题 I have tried: //${__FileToString(C:\\QC\\qa\\Testlink\\Jmeter\\Expected\\test.xml,ASCII,${xmlFile})}; Found error message : org.apache.jorphan.util.JMeterException: Error invoking bsh method: eval In file: inline evaluation of: ``//<?xml version="1.0" encoding="UTF-8"?> <feed xmlns="http://www.w3.org/2005/At . . . '' Encountered "<" at line 2, column 1. also, I tried with ${__StringFromFile} and got the same error message and even with beanshell script that is: import org.apache.jmeter

Check if table exists with if statement in C#?

由 末鹿安然 提交于 2019-12-14 00:48:29
问题 I try to put up an if statement to check if a table is already created. I only want to create one table, but as it is now I create a table every time I click the button to store the info. Any suggestions? DataTable dt; private void InitDataTable() { if () { } dt = new DataTable(); DataSet ds = new DataSet(); ds.ReadXml("gjesteInfo.xml"); ds.Tables.Add(dt); DataColumn dc1 = new DataColumn("Fullt navn"); DataColumn dc2 = new DataColumn("Start dato"); DataColumn dc3 = new DataColumn("Antall

Edit XML Doc Whenever there is a input to change it

由 安稳与你 提交于 2019-12-12 03:52:14
问题 public void ModifyXML(string inputAsset, string test, string version) { File.Create(Constants.XMLDoc).Close(); XmlReader xReader = XmlReader.Create(xmlDoc); while (!xReader.EOF) { if (xReader.Name != "Asset") { xReader.ReadToFollowing("Asset"); } //If we have not reached the end of the file if (!xReader.EOF) { XElement asset = (XElement)XElement.ReadFrom(xReader); string branchName = (string)asset.Attribute("Name"); if (branchName == inputAsset) { } } } } Hello guys so I'm currently trying to

how can I read an xml attribute using readXML? how does dataset.readxml translate into tables?

由 半腔热情 提交于 2019-12-09 03:43:29
问题 I just want to know how does the table resulting from readXML look like, say if the xml file looks like this: <item attr="some attribute"> <descirption>anything</description> </item> I can reference tables directly by the Tables collection like this: ds.ReadXml(xml); ... ds.Tables[i] then I can access rows and columns using the rows collection: ds.Tables[3].Rows[i].ItemArray(j); but how can I access an "attribute" of any xml node? 回答1: It's in the Row. I fixed your xml a bit :) var xml = "

How to read XML file in JMeter?

由 筅森魡賤 提交于 2019-12-04 13:46:11
I have tried: //${__FileToString(C:\\QC\\qa\\Testlink\\Jmeter\\Expected\\test.xml,ASCII,${xmlFile})}; Found error message : org.apache.jorphan.util.JMeterException: Error invoking bsh method: eval In file: inline evaluation of: ``//<?xml version="1.0" encoding="UTF-8"?> <feed xmlns="http://www.w3.org/2005/At . . . '' Encountered "<" at line 2, column 1. also, I tried with ${__StringFromFile} and got the same error message and even with beanshell script that is: import org.apache.jmeter.services.FileServer; //Open the file FileInputStream fstream = new FileInputStream("C://QC//qa//Testlink/

Reading XML to a Dictionary

由 生来就可爱ヽ(ⅴ＜●) 提交于 2019-12-03 17:20:00
问题 I need to read an XML file to a dictionary. I read few guides and I only got confused from weird words that I don't understand (such as nodes, XML validation etc.). So, could you please walk me through? I have an XML file which is written in this format: <database> <def number="1" name="one"/> <def number="2" name="two"/> </database> As mentioned, I want to store it in a dictionary. How would I go about that? 回答1: var data = XElement.Parse(xml) .Elements("def") .ToDictionary( el => (int)el

how can I read an xml attribute using readXML? how does dataset.readxml translate into tables?

由 无人久伴 提交于 2019-12-02 00:52:27
I just want to know how does the table resulting from readXML look like, say if the xml file looks like this: <item attr="some attribute"> <descirption>anything</description> </item> I can reference tables directly by the Tables collection like this: ds.ReadXml(xml); ... ds.Tables[i] then I can access rows and columns using the rows collection: ds.Tables[3].Rows[i].ItemArray(j); but how can I access an "attribute" of any xml node? It's in the Row. I fixed your xml a bit :) var xml = "<item attr=\"some attribute\"><description>anything</description></item>"; var ds = new DataSet(); ds.ReadXml(

Java SAX tutorial

由 空扰寡人 提交于 2019-11-28 19:08:26
Java SAX tutorial shows how to use Java SAX API to read and validate XML documents. SAX SAX (Simple API for XML) is an event-driven algorithm for parsing XML documents. SAX is an alternative to the Document Object Model (DOM). Where the DOM reads the whole document to operate on XML, SAX parsers read XML node by node, issuing parsing events while making a step through the input stream. SAX processes documents state-independently (the handling of an element does not depend on the elements that came before). SAX parsers are read-only. SAX parsers are faster and require less memory. On the other

File path or file location for Java - new file()

由 陌路散爱 提交于 2019-11-28 12:07:30
I have the following structure for my project. In Eclipse: myPorjectName src com.example.myproject a.java com.example.myproject.data b.xml In a.java , I want to read b.xml file. How can I do that? Specifically, in a.java , I used the following code: DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder(); Document doc = docBuilder.parse (new File("data/b.xml")); This code cannot find b.xml . However, if I change the path to src/com/example/myproject/data/b.xml then it works. The current location seems

File path or file location for Java - new file()

由 橙三吉。 提交于 2019-11-27 06:04:16
问题 I have the following structure for my project. In Eclipse: myPorjectName src com.example.myproject a.java com.example.myproject.data b.xml In a.java , I want to read b.xml file. How can I do that? Specifically, in a.java , I used the following code: DocumentBuilderFactory docBuilderFactory = DocumentBuilderFactory.newInstance(); DocumentBuilder docBuilder = docBuilderFactory.newDocumentBuilder(); Document doc = docBuilder.parse (new File("data/b.xml")); This code cannot find b.xml . However,
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