rank

within group sorts in mysql

半城伤御伤魂 提交于 2020-01-04 15:19:29
问题 I have a panel data set: that is, times , ids , and values . I would like to do a ranking based on value for each date. I can achieve the sort very simply by running: select * from tbl order by date, value The issue I have is once the table is sorted in this way, how do I retrieve the row number of each group (that is, for each date I would like there to be a column called ranking that goes from 1 to N). Example: Input: Date, ID, Value d1, id1, 2 d1, id2, 1 d2, id1, 10 d2, id2, 11 Output:

Align Ranks in Graphviz

℡╲_俬逩灬. 提交于 2020-01-04 14:16:25
问题 This is a follow-up question to How can I achieve strict reverse ranking of graphviz dot?, but a little easier. This graph is contrived, but demonstrates the problem: digraph nfa { A -> B B -> C C -> D D -> E A -> F F -> E } Nodes B and F are the same rank, but they are not displayed at the same rank. How can achieve this? 回答1: I used subgraphs with rank = same , and manually computed the ranks and grouped them in said subgraphs. digraph { { rank = same; A } { rank = same; B; F } { rank =

Excel creating multiply conditions ranking

淺唱寂寞╮ 提交于 2020-01-04 09:08:16
问题 I am trying to make a conditional ranking in this chart: On the right you can see the total score and ranking from the Match 1,2,3 (sum) on line A and C I have a tie score (3 points and both ranked at 2nd place), I'd like to to add a 2nd and 3rd conditions to determinate the final ranking. If there is a tie in score (both are in same ranking), then to determine who is 2nd and who is 3rd place I want to use the values from the XX's column first. The higher value will win the 2nd place and in a

Using the Rank Function In Excel

谁说胖子不能爱 提交于 2020-01-04 07:09:20
问题 Sorry if this has been answered and I feel it may have but I am struggling to find an answer that helps me to the point of success. I have a basic spreadsheet for time trial results. The spreadsheet is for both men and women. Basically, points are awarded for the quickest times throughout the entire competitors on 30 second intervals which is fine (Cloumn N)...(I have managed this) My question is - On top of this the top 7 men in ranked position is awarded additional bonus points and the top

Adding a rank value to my MySQL table

空扰寡人 提交于 2020-01-03 16:54:35
问题 I have a fixed table that will not change. I have over 80,000 rows. CREATE TABLE `word_list_master` ( `id` int(11) unsigned NOT NULL AUTO_INCREMENT, `word` varchar(64) NOT NULL, `created` int(11) NOT NULL, `frequency` int(11) NOT NULL, `number_of_files` int(11) NOT NULL, `combined_frequency` bigint(24) NOT NULL, PRIMARY KEY (`id`) ) I want to create a 7th column 'rank' that will determine the rank of the rows ordered by the combined_frequency column. I am doing this to reduce overhead when

Lucene: exact matches aren't shown first

…衆ロ難τιáo~ 提交于 2020-01-03 05:49:07
问题 I am using the demo IndexFiles and SearchFiles classes to index and search which are in org.apache.lucene.demo packet. My issue is when I use a query that contains more than a word, I am not getting results that have the exact match. For instance: Enter query: "natural language" Searching for: "natural language" 298 total matching documents 1. download\researchers.uq.edu.au\fields-of-research\natural-language-processing .txt 2. download\researchers.uq.edu.au\research-project\16267.txt 3.

Oracle SQL - How to get distinct rows using RANK() or DENSE_RANK() or ROW_NUMBER() analytic function?

核能气质少年 提交于 2020-01-01 06:13:44
问题 I am looking to get the top 3 distinct salaries of each department. I was able to do it either using RANK() or DENSE_RANK() or ROW_NUMBER() but my table is having some records with same salaries. Mentioned below is my query and its result. The top 3 salaries of Dept 20 should be 6000, 3000, 2975. But there are 2 employees with salary 3000 and both of them have rank 2. So it is giving me 4 records for this department (1 for rank 1, 2 records for rank2 and 1 record for rank3). Please suggest

R - extracting value by rank

空扰寡人 提交于 2019-12-31 04:35:05
问题 Suppose I have a data frame that I have ordered according to the Value column and now looks something like this: Name Value A 2 B 2 C 5 D 5 E 10 F 12 I am writing a function where one argument is a rank (e.g. rank=2) and I want the output to be the corresponding name (e.g. C & D). Any ties should be ranked equally. I would really appreciate any guidance as I've tried multiple ways of accomplishing this and keep getting errors of some sort. 回答1: We can convert the Value as factor and then

How to reorder arbitrary integer vector to be in increasing order

守給你的承諾、 提交于 2019-12-25 06:48:02
问题 This question is a follow-up of this question. Let's say I have a large data.frame, df , with columns u, v . I'd like to number the observed variable-interactions of u, v in increasing order , i.e. the order in which they were seen when traversing the data.frame from top to bottom. Note: Assume df has some existing ordering so it's not ok to temporarily reorder it. The code shown at the bottom of this post works well, except that the result vector returned is not in increasing order. That is,

Ranking rows in R

房东的猫 提交于 2019-12-25 03:35:31
问题 I have a dataset of values that has multiple columns (for different sites) and rows (for different days) that I am trying to rank for each day using R. I would like the rank the data for each column (site) from the total number of sites within one day (so ranking based on each row). It would be possible to do in Excel, but would obviously take a long time. Below is a [much smaller] example of what i'm trying to achieve: date - site1 - site2 - site3 - site4 1/1/00 - 24 - 33 - 10 - 13 2/1/00 -