random

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 18 days ago . Improve this question I need help with random name picker in multiple textboxes in c# framwork. Can someone help me with how I can get started? How to think? I would appreciate the help! 回答1: You can call Enumerable.OfType<TResult>(IEnumerable) Method to get the list of all

问题 I have some python program let's say 'Test.py' it has a class and inside this in the init I have to introduce three random variables. import math class Vector(): def __init__(self,vx,vy,vz): self.x=vx self.y=vy self.z=vz def norm(self): xx=self.x**2 yy=self.y**2 zz=self.z**2 return math.sqrt(xx+yy+zz) Now I made a run file 'Testrun.py' which calls this file and then for each dataset it produces one result import math import numpy as np from Desktop import Test def random_range(n, min, max):

问题 I want to generate random numbers from chi-square distribution with 3 degrees of freedom but shifted to the left . I mean the shifted distribution function f(x-a) a is the amount of shifting. in r it is said the non centrality parameter must be non negative. 回答1: Let's look at the Chi-square distribution with 3 degrees of freedom: x_vals <- seq(0, 10, 0.1) plot(x_vals, dchisq(x_vals, 3), type = "l", main = "Chi Squared distribution of x with 3 DOF") Now let's shift it to the left by a

问题 I want to generate random numbers from chi-square distribution with 3 degrees of freedom but shifted to the left . I mean the shifted distribution function f(x-a) a is the amount of shifting. in r it is said the non centrality parameter must be non negative. 回答1: Let's look at the Chi-square distribution with 3 degrees of freedom: x_vals <- seq(0, 10, 0.1) plot(x_vals, dchisq(x_vals, 3), type = "l", main = "Chi Squared distribution of x with 3 DOF") Now let's shift it to the left by a

问题 I have a few rooms which are placed randomly so I have to check if a room is overlapping. The rooms have a size of 10x10 and are for test reasons placed exactly side by side (they don't overlap in the scene). The Floor is a Transform which consists out of 1 or more Transforms (in this case out of one square but for other forms it it could be 2 or more). To check if they are overlapping I have this function which doesn't work. Debug log is always something between 3 and 61.. public bool

问题 I want to generate a list of say length 10000 from two items ('yes','no'). And the code I haev does that. The problem is, it generates ~50% yes and 50% no. How can I modify this code so that I can set the percentage of time it selects yes. Suppose i want yes like 36.7% of the time. And then it should select the remaining 'no' the remaining 63.3% time. Code is below: import random category = ('yes','no') length_of_field = 10000 print(length_of_field) print(type(category)) category_attribute =

问题 How can I make javascript randomly choose between two buttons to click? var $1Button = $('#1'), $2Button = $('#2'); function startQuiz(){ $1Button.trigger('click'); } 回答1: An easy way to handle this situation is to place your two buttons in an array and pick a random index in that array to trigger the click. As an added bonus, the code will easily expand to more than two buttons. var $buttons = [$('#1'), $('#2')]; function startQuiz(){ var buttonIndex = Math.floor(Math.random() * $buttons

问题 How can I make javascript randomly choose between two buttons to click? var $1Button = $('#1'), $2Button = $('#2'); function startQuiz(){ $1Button.trigger('click'); } 回答1: An easy way to handle this situation is to place your two buttons in an array and pick a random index in that array to trigger the click. As an added bonus, the code will easily expand to more than two buttons. var $buttons = [$('#1'), $('#2')]; function startQuiz(){ var buttonIndex = Math.floor(Math.random() * $buttons

问题 I wrote this code for my homework: import random score=[] random.seed(1) for i in range(0,100): score.append(random.randrange(0,21)) for k in range(20, -1, -1): print("Who get %2d score in test? : "%(k), end='') while score.count(k)!=0: j = score.index(k) print("%3s" % (j), end=" ") score.remove(k) score.insert(j,25) print("\n") I ran it on my computer many times and the results were the same. Ironically, in other computers, the results are different from my computer, but also also getting

问题 Here is a sample string: {three / fifteen / one hundred} this is the first random number, and this is the second, {two / four} From the brackets, I need to return a random value for example: One hundred is the first random number, and this is the second, two My code: function RandElement($str) { preg_match_all('/{([^}]+)}/', $str, $matches); return print_r($matches[0]); } $str = "{three/fifteen/one hundred} this is the first random number, and this is the second, {two/four}"; RandElement($str