pythonw

Why does my program work with a .py extension but not with a .pyw extension?

旧巷老猫 提交于 2019-12-01 17:53:41
I have a script that converts Google Earth .kml / .kmz files to shapefiles with a simple GUI interface written in Tkinter. My problem is that it works fine with a .py extension, but when saved out with a .pyw extension it stalls while reading my .kml files. There are no error messages and it doesn't crash. The GUI launches OK, etc, but it just stops and always at about the same place. I'm using Python 2.5, and had the same results with Python 2.7. Any ideas what could cause this? .pyw files are run differently than .py files -- they are associated with a different interpreter, pythonw.exe

.pyw and pythonw does not run under Windows 7

馋奶兔 提交于 2019-11-27 13:42:15
问题 Running a simple .py or .pyw python file causes python.exe to show up under Task Manager. python myApp.py python myApp.pyw However when we try to run it without using the console, the script does not appear to run, nor does python.exe or pythonw.exe appears under Task Manager pythonw myApp.pyw pythonw myApp.py How do we troubleshoot the problem? The system is running Python 2.7.8 x64. 回答1: tl;dr To troubleshoot , use output redirection on invocation: pythonw myApp.py 1>stdout.txt 2>stderr.txt

How to avoid console window with .pyw file containing os.system call?

天涯浪子 提交于 2019-11-27 01:52:43
If I save my code files as .pyw , no console window appears - which is what I want - but if the code includes a call to os.system , I still get a pesky console window. I assume it's caused by the call to os.system . Is there a way to execute other files from within my .pyw script without raising the console window at all? robince You could try using the subprocess module ( subprocess.Popen , subprocess.call or whatever) with the argument shell=True if you want to avoid starting a console window. You should use subprocess.Popen class passing as startupinfo parameter's value instance of

Running a process in pythonw with Popen without a console

|▌冷眼眸甩不掉的悲伤 提交于 2019-11-26 13:36:02
I have a program with a GUI that runs an external program through a Popen call: p = subprocess.Popen("<commands>" , stdout=subprocess.PIPE , stderr=subprocess.PIPE , cwd=os.getcwd()) p.communicate() But a console pops up, regardless of what I do (I've also tried passing it NUL for the file handle). Is there any way to do that without getting the binary I call to free its console? From here : import subprocess def launchWithoutConsole(command, args): """Launches 'command' windowless and waits until finished""" startupinfo = subprocess.STARTUPINFO() startupinfo.dwFlags |= subprocess.STARTF

How to avoid console window with .pyw file containing os.system call?

烂漫一生 提交于 2019-11-26 12:29:02
问题 If I save my code files as .pyw , no console window appears - which is what I want - but if the code includes a call to os.system , I still get a pesky console window. I assume it\'s caused by the call to os.system . Is there a way to execute other files from within my .pyw script without raising the console window at all? 回答1: You could try using the subprocess module ( subprocess.Popen , subprocess.call or whatever) with the argument shell=True if you want to avoid starting a console window

Running a process in pythonw with Popen without a console

允我心安 提交于 2019-11-26 02:57:30
问题 I have a program with a GUI that runs an external program through a Popen call: p = subprocess.Popen(\"<commands>\" , stdout=subprocess.PIPE , stderr=subprocess.PIPE , cwd=os.getcwd()) p.communicate() But a console pops up, regardless of what I do (I\'ve also tried passing it NUL for the file handle). Is there any way to do that without getting the binary I call to free its console? 回答1: From here: import subprocess def launchWithoutConsole(command, args): """Launches 'command' windowless and