pyramid

问题 New to python and Pyramid. I have a view that does pagination. How do I json encode it? I get an error "object at 0x2d16d90> is not JSON serializable" when I try this: @view_config(route_name="paginate") def paginate(request): query = DBSession.query(MyTable) page_url = paginate.PageURL_WebOb(request) customers = paginate.Page(query, page=int(request.params.get("page", 1)), items_per_page=25, url=page_url) if "partial" in request.params: # Render the partial list page return render_to

问题 I made a starter (pcreate -s starter myproject) project in Pyramid. How do I make database connection available to my application when needed I looked here: Subscribing Database Conenction. Below is the code: @subscriber(NewRequest) def new_request_subscriber(event): request = event.request settings = request.registry.settings request.db = sqlite3.connect(settings['db']) request.add_finished_callback(close_db_connection) def close_db_connection(request): request.db.close() I am worried about

问题 I am puzzled at why my Python unittest runs perfectly fine without actually updating the database. I can even see the SQL statements from SQLAlchemy and step through the newly created user object's email -- ...INFO sqlalchemy.engine.base.Engine.0x...954c INSERT INTO users (user_id, user_name, email, ...) VALUES (%(user_id)s, %(user_name)s, %(email)s, ...) ...INFO sqlalchemy.engine.base.Engine.0x...954c {'user_id': u'4cfdafe3f46544e1b4ad0c7fccdbe24a', 'email': u'test@example.com', ...} > ...

问题 In a test I am doing in a pyramid application, I am trying to send a translatable text via JSON, but the translation is not working. At the beginning of the file I am importing the translation string function: from pyramid.i18n import TranslationString as _ Then consider the following code: @view_config(route_name='transtest', renderer='json') def transtest_view(request): return { 'myvar': _('temp-test', default='Temporary test', domain='myapp') } But what I get is: {"myvar": "temp-test"}

问题 I need to run some tasks in background of web app (checking the code out, etc) without blocking the views. The twist in typical Queue / Celery scenario is that I have to ensure that the tasks will complete, surviving even web app crash or restart until those tasks complete, whatever their final result. I was thinking about recording parameters for multiprocessing.Pool in a database and starting all the incomplete tasks at webapp restart. It's doable, but I'm wondering if there's a simpler or

问题 On our test servers, we're using the Pyramid debug toolbar, however, it generates http:// links to static content (like its CSS and JavaScript files), while the rest of the content is served over HTTPS. This causes mixed content warnings, and it breaks all functionality. Is there a way to force it to generate HTTPS links? I know it's possible to enable mixed content in Chrome, and this works, but it's not a feasible solution for the entire QA team. 回答1: There might be better/simpler ways to

问题 A bit of background: I am using pyramid framework with SQLAlchemy . My db session is handled by pyramid_tm and ZTE DBSession = scoped_session(sessionmaker(extension=ZopeTransactionExtension())) I have a very complicated database design with lots of model classes, foreign keys, and complex relationships between my models. So while doing some very complicated logic on my Models and deleting, updating , inserting, and moving around objects from relationships in different models I used to get

问题 Environment: Python 3.2.3 (using virtualenv) Pyramid 1.4 pyramid_mongodb scaffold After installing myproject using pyramid_mongodb scaffold I ran python setup.py test -q and it's failing with below errors. running build_ext Traceback (most recent call last): File "setup.py", line 33, in <module> """, File "/usr/lib/python3.2/distutils/core.py", line 148, in setup dist.run_commands() File "/usr/lib/python3.2/distutils/dist.py", line 917, in run_commands self.run_command(cmd) File "/usr/lib

问题 I am trying to alter the Pyramid hello world example so that any request to the Pyramid server serves the same page. i.e. all routes point to the same view. This is what iv got so far: from wsgiref.simple_server import make_server from pyramid.config import Configurator from pyramid.response import Response def hello_world(request): return Response('Hello %(name)s!' % request.matchdict) if __name__ == '__main__': config = Configurator() config.add_route('hello', '/*') config.add_view(hello

问题 I want a user to be able to click a link like this: <a href="/download?file=123">download</a> Have a Pyramid 1.2.7 app handle the view like this @view_config(route_name='download') def download(request): file_id = request.GET['file'] filename = get_filename(file_id) headers = request.response.headers headers['Content-Description'] = 'File Transfer' headers['Content-Type'] = 'application/force-download' headers['Accept-Ranges'] = 'bytes' headers['X-Accel-Redirect'] = ("/path/" + filename + "