process-elevation

Set app to require elevation?

 ̄綄美尐妖づ 提交于 2019-11-28 13:57:25
I'm working on the bootstrap application of a new installer for some of our products. So far, I've been relying on two things that I read about somewhere: Applications whose name contains "setup" or "install" will run elevated by default. Applications that run elevated will launch other applications in elevated mode. Recent testing has found that one or both of these statements is false, because one of the applications that I'm launching is a third party installer that requires elevation, and it's failing because of the elevation requirement. How do I set my application to require elevation? I

How to Start a Process Unelevated

|▌冷眼眸甩不掉的悲伤 提交于 2019-11-27 14:14:35
My app runs as requestedExecutionLevel set to highestAvailable . How do I run a process unelevated? I tried the following but it didn't work: Process.Start(new ProcessStartInfo {FileName = "foo.exe", Verb = "open"}) I have tried the following trust levels to start my process using Win32 API but none of them work correctly: 0 1260: This program is blocked by group policy. For more information, contact your system administrator. 0x1000 The application was unable to start correctly (0xc0000142). Click OK to close the application. 0x10000 Process starts then hangs 0x20000 All options are not

How to Start a Process Unelevated

老子叫甜甜 提交于 2019-11-26 14:18:00
问题 My app runs as requestedExecutionLevel set to highestAvailable . How do I run a process unelevated? I tried the following but it didn't work: Process.Start(new ProcessStartInfo {FileName = "foo.exe", Verb = "open"}) I have tried the following trust levels to start my process using Win32 API but none of them work correctly: 0 1260: This program is blocked by group policy. For more information, contact your system administrator. 0x1000 The application was unable to start correctly (0xc0000142).

Elevating process privilege programmatically?

让人想犯罪 __ 提交于 2019-11-25 22:57:42
问题 I\'m trying to install a service using InstallUtil.exe but invoked through Process.Start . Here\'s the code: ProcessStartInfo startInfo = new ProcessStartInfo (m_strInstallUtil, strExePath); System.Diagnostics.Process.Start (startInfo); where m_strInstallUtil is the fully qualified path and exe to \"InstallUtil.exe\" and strExePath is the fully qualified path/name to my service. Running the command line syntax from an elevated command prompt works; running from my app (using the above code)