printf

Why is a number sign-extended when it is cast to an unsigned type?

半世苍凉 提交于 2020-12-26 07:16:07
问题 I was studying how C stores data in memory by bit patterns. However I have confronted some issues when it comes to printf formatting. I have saved a variable as -10 (I do understand two's complement) and another variable as 246 . Those two variables have bit patterns of 11110110 (which is 0xF6 ). I was trying to print out a value using the unsigned int hexadecimal format in printf . char a = -10; unsigned char b = 246; printf("a : %x , b : %x\n" , (unsigned int) a, (unsigned int) b); //a :

How to print out the contents of a PBYTE?

北慕城南 提交于 2020-12-15 05:38:06
问题 I understand PBYTE is unsigned char* from Windows Data Types. I want to be able to print all the contents, either using printf() or cout : PBYTE buffer; ULONG buffersize = NULL; serializeData(data, buffer, buffersize); //this function serializes "data" and stores the data in buffer and updates bufferSize).. Can you help me understand how to print this in C++? 回答1: If you want to print the memory address that buffer is pointing at, then you can do it like this: PBYTE buffer; ULONG buffersize =

How to print out the contents of a PBYTE?

三世轮回 提交于 2020-12-15 05:37:48
问题 I understand PBYTE is unsigned char* from Windows Data Types. I want to be able to print all the contents, either using printf() or cout : PBYTE buffer; ULONG buffersize = NULL; serializeData(data, buffer, buffersize); //this function serializes "data" and stores the data in buffer and updates bufferSize).. Can you help me understand how to print this in C++? 回答1: If you want to print the memory address that buffer is pointing at, then you can do it like this: PBYTE buffer; ULONG buffersize =

Why is the C program giving weird output using Scanf?

我是研究僧i 提交于 2020-12-11 04:56:29
问题 I'm currently learning C programming and I have come across this weird output. // Program will try functionalities of the scanf function #include<stdio.h> #include<stdlib.h> int main(int argc, char const *argv[]) { char array[40]; scanf("Enter your address: %39s",array); //39 + 1/o null character at the end of the character array. printf("The address is : %s", array); return 0; } It should accept input address and output the same. PS C:\Users\G\Documents\C programs> gcc scanff.c -o scanff

Implementing formatted print with the possibility to do nothing when it gets no arguments

你。 提交于 2020-12-09 06:52:32
问题 I want to implement a macro named PRINT which gets zero or more parameters, and does the following: If it gets zero parameters - do nothing. If it gets one or more arguments - act like printf. I succeed in implementing it as you can see in my code below, but only at the cost of calling to printf with an empty string in the case we get zero arguments. Is there a way I can handle the zero arguments case without calling to printf (it's not efficient to print something when you just want to do

Implementing formatted print with the possibility to do nothing when it gets no arguments

自作多情 提交于 2020-12-09 06:51:14
问题 I want to implement a macro named PRINT which gets zero or more parameters, and does the following: If it gets zero parameters - do nothing. If it gets one or more arguments - act like printf. I succeed in implementing it as you can see in my code below, but only at the cost of calling to printf with an empty string in the case we get zero arguments. Is there a way I can handle the zero arguments case without calling to printf (it's not efficient to print something when you just want to do

Implementing formatted print with the possibility to do nothing when it gets no arguments

谁说我不能喝 提交于 2020-12-09 06:50:50
问题 I want to implement a macro named PRINT which gets zero or more parameters, and does the following: If it gets zero parameters - do nothing. If it gets one or more arguments - act like printf. I succeed in implementing it as you can see in my code below, but only at the cost of calling to printf with an empty string in the case we get zero arguments. Is there a way I can handle the zero arguments case without calling to printf (it's not efficient to print something when you just want to do

Implementing formatted print with the possibility to do nothing when it gets no arguments

痞子三分冷 提交于 2020-12-09 06:49:06
问题 I want to implement a macro named PRINT which gets zero or more parameters, and does the following: If it gets zero parameters - do nothing. If it gets one or more arguments - act like printf. I succeed in implementing it as you can see in my code below, but only at the cost of calling to printf with an empty string in the case we get zero arguments. Is there a way I can handle the zero arguments case without calling to printf (it's not efficient to print something when you just want to do

Implementing formatted print with the possibility to do nothing when it gets no arguments

空扰寡人 提交于 2020-12-09 06:48:26
问题 I want to implement a macro named PRINT which gets zero or more parameters, and does the following: If it gets zero parameters - do nothing. If it gets one or more arguments - act like printf. I succeed in implementing it as you can see in my code below, but only at the cost of calling to printf with an empty string in the case we get zero arguments. Is there a way I can handle the zero arguments case without calling to printf (it's not efficient to print something when you just want to do

Implementing formatted print with the possibility to do nothing when it gets no arguments

﹥>﹥吖頭↗ 提交于 2020-12-09 06:47:01
问题 I want to implement a macro named PRINT which gets zero or more parameters, and does the following: If it gets zero parameters - do nothing. If it gets one or more arguments - act like printf. I succeed in implementing it as you can see in my code below, but only at the cost of calling to printf with an empty string in the case we get zero arguments. Is there a way I can handle the zero arguments case without calling to printf (it's not efficient to print something when you just want to do