ppp

How to programmatically create a PPTP VPN connection on macOS Sierra/High Sierra?

人盡茶涼 提交于 2020-06-17 14:34:11
问题 Apple removed high-level PPTP support in macOS Sierra from its network configuration system. However, the PPP internals are all still there, including /usr/sbin/pppd and /etc/ppp/ . How can I programmatically initiate a PPTP VPN connection on macOS Sierra / High Sierra using what's left? 回答1: Answer: This method creates a PPTP connection that doesn't send all traffic and doesn't override other DNS providers, meaning it works with multiple simultaneous VPN connections each having different DNS

Fastest cartesian distance (R) from each point in SpatialPointsDataFrame to closest points/lines in 2nd shapefile

核能气质少年 提交于 2020-06-13 11:28:41
问题 I want to know the fastest algorithms for obtaining the cartesian distances between each point in a SpatialPointsDataFrame ( X ) and either (a) the closest point in a second SpatialPointsDataFrame ( Y ), or (b) the closest line segment in a SpatialLinesDataFrame ( Y ). So this is basically 2 questions, with perhaps the same answer. For the lines, I know I can use dist2Line(X,Y, distfun=distGeo) but this is insanely slow. I also tried using nncross , after converting both X and Y to ppp

Fastest cartesian distance (R) from each point in SpatialPointsDataFrame to closest points/lines in 2nd shapefile

房东的猫 提交于 2020-06-13 11:28:13
问题 I want to know the fastest algorithms for obtaining the cartesian distances between each point in a SpatialPointsDataFrame ( X ) and either (a) the closest point in a second SpatialPointsDataFrame ( Y ), or (b) the closest line segment in a SpatialLinesDataFrame ( Y ). So this is basically 2 questions, with perhaps the same answer. For the lines, I know I can use dist2Line(X,Y, distfun=distGeo) but this is insanely slow. I also tried using nncross , after converting both X and Y to ppp

Fastest cartesian distance (R) from each point in SpatialPointsDataFrame to closest points/lines in 2nd shapefile

﹥>﹥吖頭↗ 提交于 2020-06-13 11:28:07
问题 I want to know the fastest algorithms for obtaining the cartesian distances between each point in a SpatialPointsDataFrame ( X ) and either (a) the closest point in a second SpatialPointsDataFrame ( Y ), or (b) the closest line segment in a SpatialLinesDataFrame ( Y ). So this is basically 2 questions, with perhaps the same answer. For the lines, I know I can use dist2Line(X,Y, distfun=distGeo) but this is insanely slow. I also tried using nncross , after converting both X and Y to ppp

Get server IP of PPP VPN in Windows using VBScript or CMD

白昼怎懂夜的黑 提交于 2020-04-17 22:11:15
问题 Is it possible to use VBScript or commandline to grab the server IP of a PPP VPN under Windows? Note this is not VPN dialup server IP. 回答1: You can use VBScript to get the information from WMI. There are plenty of networking scripts here. For example, use the following script to get the IP of a given net adapter. Just be sure to provide your VPN's name instead of the "Local Area Connection 2" string: strComputer = "." Set objWMIService = GetObject(_ "winmgmts:\\" & strComputer & "\root\cimv2"

Get server IP of PPP VPN in Windows using VBScript or CMD

为君一笑 提交于 2020-04-17 22:07:57
问题 Is it possible to use VBScript or commandline to grab the server IP of a PPP VPN under Windows? Note this is not VPN dialup server IP. 回答1: You can use VBScript to get the information from WMI. There are plenty of networking scripts here. For example, use the following script to get the IP of a given net adapter. Just be sure to provide your VPN's name instead of the "Local Area Connection 2" string: strComputer = "." Set objWMIService = GetObject(_ "winmgmts:\\" & strComputer & "\root\cimv2"

Get server IP of PPP VPN in Windows using VBScript or CMD

喜你入骨 提交于 2020-04-17 22:07:02
问题 Is it possible to use VBScript or commandline to grab the server IP of a PPP VPN under Windows? Note this is not VPN dialup server IP. 回答1: You can use VBScript to get the information from WMI. There are plenty of networking scripts here. For example, use the following script to get the IP of a given net adapter. Just be sure to provide your VPN's name instead of the "Local Area Connection 2" string: strComputer = "." Set objWMIService = GetObject(_ "winmgmts:\\" & strComputer & "\root\cimv2"

使用原生js 实现点击消失效果

不打扰是莪最后的温柔 提交于 2020-03-15 21:52:50
JQ版 <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title>菜鸟教程(runoob.com)</title> <script src="https://cdn.staticfile.org/jquery/1.10.2/jquery.min.js"> </script> <script> $(document).ready(function () { $("p").click(function () { $(this).hide(); }); }); </script> </head> <body> <p>如果你点我,我就会消失。</p> <p>继续点我!</p> <p>接着点我!</p> </body> </html> JS版 <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title>菜鸟教程(runoob.com)</title> </head> <body> <p>如果你点我,我就会消失。</p> <p>继续点我!</p> <p>接着点我!</p> <script> // 使用原生js 实现点击消失效果 window.onload = function () { var ppp = document.getElementsByTagName("p")

11 配置PPP PAP认证

戏子无情 提交于 2020-02-23 13:21:31
配置PPP PAP认证 网络拓扑图 1 R42配置(被认证方) 2 R43配置(认证方) 3 VPC44配置 4 VPC45配置 5 验证测试 5.1 按当前配置测试 VPC44 ping VPC45 VPC45 ping VPC44 5.2 将验证方的用户名和密码删除 PS:一定要将Rb上PPP协议清除,不然在连接建立的情况下删除用户名和密码对链路没有影响 R43配置 VPC44 ping VPC45 VPC45 ping VPC44 或 5.3 恢复配置 R43配置 VPC44 ping VPC45 VPC45 ping VPC44 来源: CSDN 作者: wqy1837154675 链接: https://blog.csdn.net/wqy1837154675/article/details/104455923

(扩展)BSGS与高次同余方程

不打扰是莪最后的温柔 提交于 2020-01-30 07:05:46
前言: 今天更BSGS算法。俗称大步小步算法(Big-Step G…-Step),又称拔山盖世、北上广深、 白色狗屎 。 问题: 求解指数同余方程: a x ≡ b ( m o d    p ) a^{x}\equiv b(mod\; p) a x ≡ b ( m o d p ) 的最小自然数解。 BSGS算法: 模板题 这个算法只考虑 g c d ( a , p ) = 1 gcd(a,p)=1 g c d ( a , p ) = 1 的情况。 那么,怎么做呢。 其实做法很简单,就是 枚举 。 先来一种 暴力枚举 。 就是枚举 x x x 从 [ 0 , p − 1 ] [0,p-1] [ 0 , p − 1 ] ,然后检验答案是否正确。 知道欧拉定理的应该知道只要枚举到 φ ( p ) − 1 \varphi(p)-1 φ ( p ) − 1 ,但 p p p 为质数时欧拉函数仍为 p − 1 p-1 p − 1 。 看过 阶与原根 的应该知道只要枚举到 p p p 的阶即可,但算 p p p 的阶仍然要暴力去枚举。 所以这里只要一个一个枚举过去便好。 但是 o ( p ) o(p) o ( p ) 的暴力枚举配不上这么高大上的名字,所以还有优化的余地。 我们可以考虑 折半枚举 。 怎么折半,就是这个算法的精髓了。 我们令 x = k n + i x=kn+i x = k n