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问题 I'm trying to send simple push notifications with pushbullet just through using the email and sending those to the linked account to avoid needing account data. (see reference here: https://docs.pushbullet.com/#pushes) Therefore I'm using a non cURL-method in php that I (not only) found here: How do I send a POST request with PHP? Unfortunately I get back an error as following: <br /> <b>Warning</b>: file_get_contents(https://api.pushbullet.com/v2/pushes): failed to open stream: HTTP request

问题 I'm trying to send simple push notifications with pushbullet just through using the email and sending those to the linked account to avoid needing account data. (see reference here: https://docs.pushbullet.com/#pushes) Therefore I'm using a non cURL-method in php that I (not only) found here: How do I send a POST request with PHP? Unfortunately I get back an error as following: <br /> <b>Warning</b>: file_get_contents(https://api.pushbullet.com/v2/pushes): failed to open stream: HTTP request

问题 I need to test the following method with out altering the method itself. The method makes a POST method to a server. But I need to make a test case that's independent from the server. I tested a similar method before redirecting it to a local file. But that for that I was giving protocol as file, hostname as localhost and port as -1. My problem is that this method does a post and casts to HttpURLConnection and wr = new DataOutputStream(conn.getOutputStream()); wont work on an local txt file

问题 I want to create a form on my site that when a user submits, it posts their data to a particular Spreadsheet in my Google Drive. How can I do this with Google App Scripts? sample form <form method='post' action='https://script.google.com/macros/s/xxxx.....'> Favorite Color <input type='text' value='' name='color' /> Favorite Ice Cream Flavor <input type='text' value='' name='flavor' /> <input type='button' value='submit' /> </form> so that when I hit submit it creates a record in a Google

问题 So ultimately, what I'm doing is trying to upload and post multiple files to a Django backend using AngularJS. I can post a single file, but it seems like when a FileList object is put in the $http.post data field, the backend no longer detects any files in the POST request. Here's what the html looks like: <form enctype="multipart/form-data" action="upload" method="POST"> <div class="form-group"> <span class="btn btn-info btn-file"> <i class="glyphicon glyphicon-file"></i> Browse <input

问题 I have an URL which is to be used for getting post data after pasting and pressing enter in the browser. My link is : http://vtrails.us/mixtape-builder/?song_urls=http://vtrails.us/wp-content/uploads/2015/12/mpthreetest.mp3&song_artist=ganja <?php if(isset($_POST['song_urls']) && !empty($_POST['song_urls'])){ $song_url = $_POST['song_urls']; $song_artist = $_POST['song_artist']; } echo $song_url; echo $song_artist; ?> But i am not getting any of them.So what can i do now? 回答1: If you use $

问题 I have an URL which is to be used for getting post data after pasting and pressing enter in the browser. My link is : http://vtrails.us/mixtape-builder/?song_urls=http://vtrails.us/wp-content/uploads/2015/12/mpthreetest.mp3&song_artist=ganja <?php if(isset($_POST['song_urls']) && !empty($_POST['song_urls'])){ $song_url = $_POST['song_urls']; $song_artist = $_POST['song_artist']; } echo $song_url; echo $song_artist; ?> But i am not getting any of them.So what can i do now? 回答1: If you use $

问题 To reproduce the error, simply upload a file(s) to any POST routes in Laravel that exceeds the post_max_size in your php.ini configuration. My goal is to simply catch the error so I can inform the user that the file(s) he uploaded is too large. Say: public function postUploadAvatar(Request $request) try { // Do something with $request->get('avatar') // Maybe validate file, store, whatever. } catch (PostTooLargeException $e) { return 'File too large!'; } } The above code is in standard Laravel

问题 I have a form which contains some unique input fields and some others with duplicate names, like this: <form method="post"> Title: <input type="text" name="title" /><br /> Content: <input type="text" name="content" /><br /> Name: <input type="text" name="name" /><br /> Email: <input type="text" name="email" /><br /> Name: <input type="text" name="name" /><br /> Email: <input type="text" name="email" /><br /> Name: <input type="text" name="name" /><br /> Email: <input type="text" name="email"

问题 I have a form : <form:form modelAttribute="zgImport" action="${importAfterValidationUsers}" method="POST" name="ImportForm" > in which I display csv content (one line per user). My controller method get the object : public void importAfterValidationUsers(@ModelAttribute ("zgImport") ZgImport zgImport, ActionRequest request, ActionResponse response) { Problem is : if I have many lines (more than 670) the object "zgImport" that I get in my controller is not fully filed, I miss some data. Is