operator-precedence

Why does (1 == 2 != 3) evaluate to False in Python?

二次信任 提交于 2020-08-24 06:05:15
问题 Why does (1 == 2 != 3) evaluate to False in Python, while both ((1 == 2) != 3) and (1 == (2 != 3)) evaluate to True ? What operator precedence is used here? 回答1: This is due to the operators chaining phenomenon. The Pydoc explains it as : Comparisons can be chained arbitrarily, e.g., x < y <= z is equivalent to x < y and y <= z , except that y is evaluated only once (but in both cases z is not evaluated at all when x < y is found to be false). And if you look at the precedence of the == and !

Why does (1 == 2 != 3) evaluate to False in Python?

南楼画角 提交于 2020-08-24 06:03:26
问题 Why does (1 == 2 != 3) evaluate to False in Python, while both ((1 == 2) != 3) and (1 == (2 != 3)) evaluate to True ? What operator precedence is used here? 回答1: This is due to the operators chaining phenomenon. The Pydoc explains it as : Comparisons can be chained arbitrarily, e.g., x < y <= z is equivalent to x < y and y <= z , except that y is evaluated only once (but in both cases z is not evaluated at all when x < y is found to be false). And if you look at the precedence of the == and !

Command grouping (&&, ||, …)

江枫思渺然 提交于 2020-08-19 04:20:52
问题 We are currently in the /home/student/ directory. We execute the following commands: pwd; (ls) || { cd .. && ls student/; } && cd student || cd / && cd ; The commands that are executed are: pwd, ls, cd student, cd /, cd Here is what I think: pwd is executed, because it's the first command (ls) is executed in a subshell, because the commands are seperated with ";" the code on the right of || isn't executed, since the code on the left of || was executed So far everything clear, I guess. But I

Command grouping (&&, ||, …)

旧时模样 提交于 2020-08-19 04:19:27
问题 We are currently in the /home/student/ directory. We execute the following commands: pwd; (ls) || { cd .. && ls student/; } && cd student || cd / && cd ; The commands that are executed are: pwd, ls, cd student, cd /, cd Here is what I think: pwd is executed, because it's the first command (ls) is executed in a subshell, because the commands are seperated with ";" the code on the right of || isn't executed, since the code on the left of || was executed So far everything clear, I guess. But I

Chained ostream internal behavior and their results on MSVC (versus Clang)

久未见 提交于 2020-07-09 05:18:16
问题 An issue of streams, internal string, and operation ordering with MSVC versus GCC / Clang Hello everyone, I just recently began to work more seriously with MSVC for a cross-platform project of mine, and while testing outputs via chained STD stream ( ie. a succession of obj.foo() << endl << obj.bar() << endl << [..etc] ) I came across a behavior when using internally updated string neither did I expected nor had encountered on Linux with GCC or Clang . Compiler versions were GCC 7.5, Clang 11

Chained ostream internal behavior and their results on MSVC (versus Clang)

我怕爱的太早我们不能终老 提交于 2020-07-09 05:16:41
问题 An issue of streams, internal string, and operation ordering with MSVC versus GCC / Clang Hello everyone, I just recently began to work more seriously with MSVC for a cross-platform project of mine, and while testing outputs via chained STD stream ( ie. a succession of obj.foo() << endl << obj.bar() << endl << [..etc] ) I came across a behavior when using internally updated string neither did I expected nor had encountered on Linux with GCC or Clang . Compiler versions were GCC 7.5, Clang 11

Left to right application of operations on a list in python3

。_饼干妹妹 提交于 2020-06-25 09:51:12
问题 Is there any possible way to achieve a non-lazy left to right invocation of operations on a list in python ? e.g. scala val a = ((1 to 50) .map(_ * 4) .filter( _ <= 170) .filter(_.toString.length == 2) .filter (_ % 20 == 0) .zipWithIndex .map{ case(x,n) => s"Result[$n]=$x"} .mkString(" .. ")) a: String = Result[0]=20 .. Result[1]=40 .. Result[2]=60 .. Result[3]=80 While I realize many folks will not prefer the above syntax, I like the ability to move left to right and add arbitrary operations

Operator precedence in regular expressions

生来就可爱ヽ(ⅴ<●) 提交于 2020-06-24 08:34:27
问题 What is the default operator precedence in Oracle's regular expressions when they don't contain parentheses? For example, given H|ha+ would it be evaluated as H|h and then concatenated to a as in ((H|h)a) , or would the H be alternated with ha as in (H|(ha)) ? Also, when does the + kick in, etc.? 回答1: Given the Oracle doc: Table 4-2 lists the list of metacharacters supported for use in regular expressions passed to SQL regular expression functions and conditions. These metacharacters conform