operator-arrow-star

Here is a C++ snippet that I found in the documentation of the cpp.react library : auto in = D::MakeVar(0); auto op1 = in ->* [] (int in) { int result = in /* Costly operation #1 */; return result; }; I have never seen the ->* [] notation. First, I thought that it was just a typo, but I also found such an expression in the source code : auto volume = (width,height,depth) ->* [] (int w, int h, int d) { return w * h * d; }; Is this valid C++11 (or C++14)? What does it mean? The only example on the linked page where I see ->* is this: auto in = D::MakeVar(0); auto op1 = in ->* [] (int in) { int

C++ continues to surprise me. Today i found out about the ->* operator. It is overloadable but i have no idea how to invoke it. I manage to overload it in my class but i have no clue how to call it. struct B { int a; }; struct A { typedef int (A::*a_func)(void); B *p; int a,b,c; A() { a=0; } A(int bb) { b=b; c=b; } int operator + (int a) { return 2; } int operator ->* (a_func a) { return 99; } int operator ->* (int a) { return 94; } int operator * (int a) { return 2; } B* operator -> () { return p; } int ff() { return 4; } }; void main() { A a; A*p = &a; a + 2; } edit: Thanks to the answer. To

Yes, I've seen this question and this FAQ (wrong link) this FAQ , but I still don't understand what ->* and .* mean in C++. Those pages provide information about the operators (such as overloading), but don't seem to explain well what they are . What are ->* and .* in C++, and when do you need to use them as compared to -> and . ? Armen Tsirunyan I hope this example will clear things for you //we have a class struct X { void f() {} void g() {} }; typedef void (X::*pointer)(); //ok, let's take a pointer and assign f to it. pointer somePointer = &X::f; //now I want to call somePointer. But for