onsubmit

Display jQuery dialog onSubmit while HTML form is processing

℡╲_俬逩灬. 提交于 2019-12-23 14:03:04
问题 I have an HTML form that allows a user to add an attachment up to X MB. Because connection speeds for users vary, I would like to show a dialog that says something along the lines of "Your request is processing. Do not navigate away from this page. This dialog will close when the form is submitted successfully". Not verbatim but similar. The form posts to itself and is processed with PHP. I am not looking for a progress bar or anything. Just a friendly alert. I have been looking at the jQuery

Fancybox + onsubmit button

删除回忆录丶 提交于 2019-12-23 06:21:07
问题 Anyone know how to fire Fancybox with an iframe onsubmit form? Regards! 回答1: There are too many resources available on basis of Google Search : Fancybox How to Use jQuery FancyBox Plugin I don't know this will solve your issue or not. Please Correct me if I am wrong. Thank you. 来源: https://stackoverflow.com/questions/4878602/fancybox-onsubmit-button

Submitting a form with JQuery Ajax results in multiple requests (and submissions)

限于喜欢 提交于 2019-12-21 02:46:18
问题 I have run into an issue with JQuery form submissions and have found no answers anywhere . If someone could shed some light on this, it would be highly appreciated. The issue: The first time I submit the form, it works fine. But if I submit the same form a second time, it sends 2 requests, 3 requests the third time, and so forth. Script: function postInvokeFunctionForm(functionId){ var formId = "#"+functionId+"-form"; var formUrl = "invokeFunction.html?functionId="+functionId $(formId).submit

onsubmit refresh html form

允我心安 提交于 2019-12-19 05:47:41
问题 I'm trying to use Javascript to submit the form's data. Here's the html. <form onsubmit="post();"> //input fields here </form> Here's the Javascript for the post() function. var post = function() { alert('the form was submitted'); return false; } My issue is that the Javascript runs but the form still processes and refreshes the page.. I put the return false; code in hoping it would stop the form from refreshing. 回答1: You will have to put the return false part after the post() function in the

Testing if value is a function

徘徊边缘 提交于 2019-12-18 10:17:30
问题 I need to test whether the value of a form's onsubmit is a function. The format is typically onsubmit="return valid();" . Is there a way to tell if this is a function, and if it's callable? Using typeof just returns that it's a string, which doesn't help me much. EDIT : Of course, I understand that "return valid();" is a string. I've replace d it down to "valid();", and even "valid()". I want to know if either of those is a function. EDIT : Here's some code, which may help explain my problem:

form's onsubmit with UIWebView

时光怂恿深爱的人放手 提交于 2019-12-13 15:26:51
问题 I have this form: <form id="form1" name="form1" method="post" action="#" onsubmit="window.open('http://www.google.com','Google','width=800,height=500,top=5000,left=6000,status=yes,resizable=yes,scrollbars=yes');"> <input type="submit" name="submit" onclick="doSubmit();" id="submit" value="Submit" /> </form> And the javascript that belongs to it is: <script type="text/javascript"> function doSubmit () { form1.submit(); } </script> When I test it in the native safari app all goes well and the

What is this format for post method for form?

戏子无情 提交于 2019-12-13 05:27:00
问题 I saw this code on the internet, and I'm a little puzzled of what it does, particularly on the onsubmit portion. <form id="generateForm" method="post" action="#" onsubmit="return writeForm(event);"> Am I correct to assume that the onsubmit portion essentially runs writeForm method. The writeForm method then returns some value (ex. string) and then post sends it to where action is pointing to (#). If I'm not mistakent # means it isn't being sent anywhere. On another point, how would I even

react-native call onSubmit() when pressed returnKeyType

偶尔善良 提交于 2019-12-12 16:14:26
问题 I'm new to react-native. I'm struggling on keyboard now. I have TextInput and a button. What I want is that, when user entered input through keyboard, he/she can go to next page with just one click on the return button. So what I simply want is that onSubmit method should be called when user clicks "return" button on keyboard. Is there anyone can help me? 回答1: You can use onSubmitEditing callback of TextInput Example. <TextInput onSubmitEditing={(event) => this.onSubmitHandler(event)} /> You

Using onclick and onsubmit together

大兔子大兔子 提交于 2019-12-12 10:25:00
问题 I want to perform an onclick and onsubmit at the same time, is this possible? Or if this is bad practice how can I merge the two codes to perform both events? I have this piece of code checking a mandatory field on the form tag: onsubmit="return formCheck(this);" I then have this piece of code on the submit button for the same form: onClick="jQuery.facebox({ ajax: (\'wishlist.php?emailme=true&name=\' + this.form.name.value + \'&country=\' + this.form.country.value + \'&email=\' + this.form

jQuery Validation, first validation onsubmit, then next validations onkeyup

独自空忆成欢 提交于 2019-12-12 06:09:51
问题 I have a basic form with a jquery validation bound to it. HTML : <form id="form-subscribe" method="post"> <div class="register_pane_content"> <label>Nom</label> <input placeholder="Votre nom" type="text" id="lastname" name="lastname" value="" class=""/> </div> <div class="register_pane_content"> <label>Prénom</label> <input placeholder="Votre prénom" type="text" id="firstname" name="firstname" value="" class=""/> </div> <div class="register_pane_content "> <label>E-mail</label> <input