numeric

This question already has an answer here: Remove NA values from a vector 6 answers I have a vector which stores over 1000 values. The first 50 values are NAs, how can I get rid of it? c(NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, NA, 1.5741, 1.583, 1.605, 1.633, 1.6465, 1.6475, 1.6329, 1.6413, 1.685, 1.692, 1.7087, 1.7055, 1.6985, 1.6807, 1.6745, 1.673, 1.6625, 1.6805, 1.689, 1.667, 1.684, 1.6675, 1.6867, 1.6688, 1.6643, 1.6685, 1.7025, 1.737,

This question already has an answer here: Is there a way to have a masked numeric input field? 1 answer I'm aware of this: <input type="tel"> and I'm aware of this: <input type="password"> But I would like to use both. I want the numeric keypad to come up on iOS (specifically) but hide each character after it's typed. Is something like this possible? <input type="tel|password"> For iOS you can set the input to type "password" and still trigger the numeric-keyboard using the HTML5-Attribute "pattern": <input type="password" pattern="[0-9]*" ... /> From the Apple-Documentation : To display a

I've created a class that can be parameterised by anything that can be converted to Numeric class Complex[T <% Numeric[T]] (val real : T, val imag : T) { //... complex number methods ... } Then elsewhere in the code I try: var myComplex = new Complex(0, 1) This raises a compilation error because (surprisingly) there's no implicit conversion between Int and Numeric[Int] or even between Int and Integral[Int]. Am I missing something? Is there an implicit conversion somewhere I'm not seeing? There's an implicit object called IntIsIntegral defined in Numeric.scala. I've tried using this to create

I am looking for an extended precision floating point library with the following features: fixed data type size (i.e. the extended precision float takes a fixed amount of memory) no initialization required for variables specify size of both mantissa and exponent C/C++ interface support for really large floats > 10^10000 The closest I could found is the HPA library by Ivano Primi. The only problem with this library is that I cannot extend the exponent (it is fixed with 15 bits). It allows me various choices for the mantissa, but the largest representable number is always limited to 10^4932.

I have a whole column of numbers that include dot separators at the thousands and comma instead of dot as an dismal separator. When I try to create a numeric column out of them, I lose all data. var1 <- c("50,0", "72,0", "960,0", "1.920,0", "50,0", "50,0", "960,0") df <- cbind(var1, var2 = as.numeric(gsub(".", "", as.character(var1)))) and wound up with: var1 var2 [1,] "50,0" NA [2,] "72,0" NA [3,] "960,0" NA [4,] "1.920,0" NA [5,] "50,0" NA [6,] "50,0" NA [7,] "960,0" NA What am I doing wrong? You need to escape the "." in your regular expression, and you need to replace the commas with a "."

I wonder, how can I create a numeric zero-length vector in R? If you read the help for vector (or numeric or logical or character or integer or double , 'raw' or complex etc ) then you will see that they all have a length (or length.out argument which defaults to 0 Therefore numeric() logical() character() integer() double() raw() complex() vector('numeric') vector('character') vector('integer') vector('double') vector('raw') vector('complex') All return 0 length vectors of the appropriate atomic modes. # the following will also return objects with length 0 list() expression() vector('list')

I have a data frame taken from a .csv-file which contains numeric and character values. I want to convert this data frame into a matrix. All containing information is numbers (the non-number-rows I deleted), so it should be possible to convert the data frame into a numeric matrix. However, I do get a character matrix. I found the only way to solve this is to use as.numeric for each and every row, but this is quite time-consuming. I am quite sure there is a way to do this with some kind of if(i in 1:n) -form, but I cannot figure out how it might work. Or is the only way really to already start