numeric-limits

I remarked two things: std::numeric_limits<float>::max()+(a small number) gives: std::numeric_limits<float>::max() . std::numeric_limits<float>::max()+(a large number like: std::numeric_limits<float>::max()/3) gives inf. Why this difference? Does 1 or 2 results in an OVERFLOW and thus to an undefined behavior? Edit: Code for testing this: 1. float d = std::numeric_limits<float>::max(); float q = d + 100; cout << "q: " << q << endl; 2. float d = std::numeric_limits<float>::max(); float q = d + (d/3); cout << "q: " << q << endl; Formally, the behavior is undefined. On a machine with IEEE

limits.h specifies limits for non-floating point math types, e.g. INT_MIN and INT_MAX . These values are the most negative and most positive values that you can represent using an int. In float.h , there are definitions for FLT_MIN and FLT_MAX . If you do the following: NSLog(@"%f %f", FLT_MIN, FLT_MAX); You get the following output: FLT_MIN = 0.000000, FLT_MAX = 340282346638528859811704183484516925440.000000 FLT_MAX is equal to a really large number, as you would expect, but why does FLT_MIN equal zero instead of a really large negative number? Nick Forge It's not actually zero, but it might

I have below a simple program: #include <stdio.h> #define INT32_MIN (-0x80000000) int main(void) { long long bal = 0; if(bal < INT32_MIN ) { printf("Failed!!!"); } else { printf("Success!!!"); } return 0; } The condition if(bal < INT32_MIN ) is always true. How is it possible? It works fine if I change the macro to: #define INT32_MIN (-2147483648L) Can anyone point out the issue? Lundin This is quite subtle. Every integer literal in your program has a type. Which type it has is regulated by a table in 6.4.4.1: Suffix Decimal Constant Octal or Hexadecimal Constant none int int long int unsigned

Is there any code to find the maximum value of integer (accordingly to the compiler) in C/C++ like Integer.MaxValue function in java? Gregory Pakosz In C++: #include <limits> then use int imin = std::numeric_limits<int>::min(); // minimum value int imax = std::numeric_limits<int>::max(); std::numeric_limits is a template type which can be instantiated with other types: float fmin = std::numeric_limits<float>::min(); // minimum positive value float fmax = std::numeric_limits<float>::max(); In C: #include <limits.h> then use int imin = INT_MIN; // minimum value int imax = INT_MAX; or #include