notation

#define LOGI(...) ((void)__android_log_print(ANDROID_LOG_INFO, "native-activity", __VA_ARGS__)) #define LOGW(...) ((void)__android_log_print(ANDROID_LOG_WARN, "native-activity", __VA_ARGS__)) This is definition for these 2 macros; later in the code LOGI and LOGW are used this way LOGI("accelerometer: x=%f y=%f z=%f", event.acceleration.x, event.acceleration.y, event.acceleration.z); and this way LOGW("Unable to eglMakeCurrent"); Since I try to avoid complex macros and #define in general, I can't get what this macro actually means. What is the role for the 3 dots notation here? What does this

I am preparing for an exam where i couldn't understand the convertion of infix notation to polish notation for the below expression: (a–b)/c*(d + e – f / g) Can any one tell step by step how the given expression will be converted to prefix? rajdip Algorithm ConvertInfixtoPrefix Purpose: Convert an infix expression into a prefix expression. Begin // Create operand and operator stacks as empty stacks. Create OperandStack Create OperatorStack // While input expression still remains, read and process the next token. while( not an empty input expression ) read next token from the input expression /

I found this snippet of code in my travels in researching JSON: var array = typeof objArray != 'object' ? JSON.parse(objArray) : objArray; I'm seeing more and more of the ? and : notation. I don't even know what it is called to look it up! Can anyone point me to a good resource for this? (btw, I know what != means). Matt Huggins It's called a Conditional (ternary) Operator . It's essentially a condensed if-else. So this: var array = typeof objArray != 'object' ? JSON.parse(objArray) : objArray; ...is the same as this: var array; if (typeof objArray != 'object') { array = JSON.parse(objArray);