ng-init

AngularJS - Accessing ng-init variables from run method

浪尽此生 提交于 2019-12-14 03:49:35
问题 1) I have variables initialized in ng-init Eg - ng-init="password='Mightybear'"; 2) I want to access it from the .run method. Eg - anguar.module("ngApp", []) .run(function() { //Access password here }); Below scenarios I have tried, and did not work - 1) angular.module("ngApp", []) .run(function($rootScope) { console.log($rootScope.password) //undefined!!! }); 2) angular.module("ngApp", []) .run(function($rootScope, $timeout) { $(timeout(function() { console.log($rootScope.password) /

AngularJS: accessing scope variables in $routeProvider

試著忘記壹切 提交于 2019-12-11 02:49:13
问题 I have an angular app on a JSP page that has: ng-init="role='<%=String.valueOf(session.getAttribute("role"))%>'" So the body tag will look like this when the JSP pulls the role attribute from the session: <body ng-app="appName" ng-init="role='roleName'"> I want to access this role variable in the $routeProvider . I tried doing so by passing $scope to the app.config function as such: app.config(['$routeProvider', '$scope', function ($routeProvider, $scope) { $routeProvider .when('somePath' { .

ng-init in ng-repeat shows only the last item in Dygraph

☆樱花仙子☆ 提交于 2019-12-08 06:17:15
问题 I am new to angularJs and trying to implement Listview in it. i am getting a json response after hitting an Api . In that Json i am recieving an array in which i am getting a string of graphdata value.What i am trying is to show that data in every listitem as per the position . I tried a lot and even try to do this through for loop..but i am always getting last value of graphdata that means i am getting last dygraph in every list item. Can any body tell me where i am going worng in code. Here

ng-init in ng-repeat shows only the last item in Dygraph

不问归期 提交于 2019-12-07 09:55:46
I am new to angularJs and trying to implement Listview in it. i am getting a json response after hitting an Api . In that Json i am recieving an array in which i am getting a string of graphdata value.What i am trying is to show that data in every listitem as per the position . I tried a lot and even try to do this through for loop..but i am always getting last value of graphdata that means i am getting last dygraph in every list item. Can any body tell me where i am going worng in code. Here is my code: HTML <ion-list> <div ng-repeat="entry in entries"> <div class="wrap_home"> <ion-item class

AngularJS: How to set a variable inside of a template?

半世苍凉 提交于 2019-12-03 01:48:53
问题 How can I avoid having the {{f = ...}} statement in the third line print out the content of forecast[day.iso] ? I want to avoid using forecast[day.iso].temperature and so on for every iteration. <div ng-repeat="day in forecast_days"> {{$index}} - {{day.iso}} - {{day.name}} {{f = forecast[day.iso]}} Temperature: {{f.temperature}}<br> Humidity: {{f.humidity}}<br> ... </div> 回答1: Use ngInit : https://docs.angularjs.org/api/ng/directive/ngInit <div ng-repeat="day in forecast_days" ng-init="f =

Is there a way to do a ng-hide on a html div?

↘锁芯ラ 提交于 2019-12-02 09:47:58
问题 I am trying to hide my div that has id="crossfade" where there is an ng-click event. 1) Is this possible? 2) What am I doing wrong? <!DOCTYPE html> <html lang="en" ng-app="myContent"> <head> <meta charset="UTF-8"> <title>ShopME Tops</title> <link rel="stylesheet" type="text/css" href="mystyle.css"/> <link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/font- awesome/4.7.0/css/font-awesome.min.css"> <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery

Is there a way to do a ng-hide on a html div?

北城以北 提交于 2019-12-02 07:14:35
I am trying to hide my div that has id="crossfade" where there is an ng-click event. 1) Is this possible? 2) What am I doing wrong? <!DOCTYPE html> <html lang="en" ng-app="myContent"> <head> <meta charset="UTF-8"> <title>ShopME Tops</title> <link rel="stylesheet" type="text/css" href="mystyle.css"/> <link rel="stylesheet" href="https://cdnjs.cloudflare.com/ajax/libs/font- awesome/4.7.0/css/font-awesome.min.css"> <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"> </script> <script type="text/javascript"src="https://ajax.googleapis.com/ajax