move

问题 I'm trying to make Teamviewer like piece of software for fun, which allows one person to view another person's screen and click and all that. Anyway, I have most all of the socket stuff done, but I don't know how to get the mouse clicks to work correctly. Here is the code I found online for moving the mouse programmatically: public static class VirtualMouse { // import the necessary API function so .NET can // marshall parameters appropriately [DllImport("user32.dll")] static extern void

问题 I'm trying to make Teamviewer like piece of software for fun, which allows one person to view another person's screen and click and all that. Anyway, I have most all of the socket stuff done, but I don't know how to get the mouse clicks to work correctly. Here is the code I found online for moving the mouse programmatically: public static class VirtualMouse { // import the necessary API function so .NET can // marshall parameters appropriately [DllImport("user32.dll")] static extern void

问题 I am confused about using std::move() in below code: If I uncomment line at (2) the output would be: 1 2 3 but if I uncomment line at (1) output would be nothing which means that move constructor of std::vector was called! Why do we have to make another call to std::move at (1) to make move constructor of std::vector to be called? What I understood that std::move get the r-value of its parameter so, why we have to get the r-value of r-value at (1)? I think this line _v = rv; at (2) is more

问题 I am confused about using std::move() in below code: If I uncomment line at (2) the output would be: 1 2 3 but if I uncomment line at (1) output would be nothing which means that move constructor of std::vector was called! Why do we have to make another call to std::move at (1) to make move constructor of std::vector to be called? What I understood that std::move get the r-value of its parameter so, why we have to get the r-value of r-value at (1)? I think this line _v = rv; at (2) is more

问题 I am confused about using std::move() in below code: If I uncomment line at (2) the output would be: 1 2 3 but if I uncomment line at (1) output would be nothing which means that move constructor of std::vector was called! Why do we have to make another call to std::move at (1) to make move constructor of std::vector to be called? What I understood that std::move get the r-value of its parameter so, why we have to get the r-value of r-value at (1)? I think this line _v = rv; at (2) is more

问题 I want to store callbacks in a vector or another container in C++11. One way to do so would be to store a vector of std::function. This works well for lambda or std::bind with copyable arguments. However, if there is one non copyable (movable only) argument, it will fail due to the conversion from the lambda/std::bind internal type to the std::function... #include <vector> class NonCopyable { public: NonCopyable() = default; NonCopyable(const NonCopyable &) = delete; NonCopyable(NonCopyable &

问题 I've checked a lot of move constructor/vector/noexcept threads, but I am still unsure what actually happens when things are supposed to go wrong. I can't produce an error when I expect to, so either my little test is wrong, or my understanding of the problem is wrong. I am using a vector of a BufferTrio object, which defines a noexcept(false) move constructor, and deletes every other constructor/assignment operator so that there's nothing to fall back to: BufferTrio(const BufferTrio&) =

问题 I've checked a lot of move constructor/vector/noexcept threads, but I am still unsure what actually happens when things are supposed to go wrong. I can't produce an error when I expect to, so either my little test is wrong, or my understanding of the problem is wrong. I am using a vector of a BufferTrio object, which defines a noexcept(false) move constructor, and deletes every other constructor/assignment operator so that there's nothing to fall back to: BufferTrio(const BufferTrio&) =

问题 I am trying to program movement that is basically like Asteroids where once UP button is pressed you accelerate to a certain speed and then because in space you don't stop and can only slow down by thrusting in opposite direction. On top of that, I would like gravity to be pulling you towards the bottom of the screen. I have this accomplished for the most part but the issue I have is: When I turn around and thrust opposite direction, it doesn't slow down first going backwards before starting

问题 I am trying to program movement that is basically like Asteroids where once UP button is pressed you accelerate to a certain speed and then because in space you don't stop and can only slow down by thrusting in opposite direction. On top of that, I would like gravity to be pulling you towards the bottom of the screen. I have this accomplished for the most part but the issue I have is: When I turn around and thrust opposite direction, it doesn't slow down first going backwards before starting