modulus | 易学教程

Why is operator% referred to as the “modulus” operator instead of the “remainder” operator?

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问题 Today at work I had an interesting discussion with one of my coworkers. He was surprised when he had the following happen to him: assert(-1 % 10 == -1) //Expecting 9 So when he came to ask me about it, I told him "well, that makes sense. When you divide -1 by 10, you get 0 with -1 remaining. His argument however was that the modulus operator is supposed to hold true to the "always positive" model. I did a little research and found that the modulus he was referring to looks like this: Let q be

A clever homebrew modulus implementation

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问题 I'm programming a PLC with some legacy software (RSLogix 500, don't ask) and it does not natively support a modulus operation, but I need one. I do not have access to: modulus, integer division, local variables, a truncate operation (though I can hack it with rounding). Furthermore, all variables available to me are laid out in tables sorted by data type. Finally, it should work for floating point decimals, for example 12345.678 MOD 10000 = 2345.678 . If we make our equation: dividend /

Split down a number in seconds to days, hours, minutes, and seconds?

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问题 I've heard that it's possible to accomplish this using the modulus % operator present in most programming languages. The real question is, how? I'm unfamiliar with how modulus works, so I've had difficulties using it in the past. Given the present time here in seconds since 1970, 1307758473.484 , how can I calculate how many years that is, days that is, hours that is, and minutes that is using modulus? I'm essentially looking to format it like this: "5 years, 10 days, 12 hours, 7 minutes, and

A clever homebrew modulus implementation

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I'm programming a PLC with some legacy software (RSLogix 500, don't ask) and it does not natively support a modulus operation, but I need one. I do not have access to: modulus, integer division, local variables, a truncate operation (though I can hack it with rounding). Furthermore, all variables available to me are laid out in tables sorted by data type. Finally, it should work for floating point decimals, for example 12345.678 MOD 10000 = 2345.678 . If we make our equation: dividend / divisor = integer quotient, remainder There are two obvious implementations. Implementation 1: Perform

checking if a number is divisible by 6 PHP

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问题 I want to check if a number is divisible by 6 and if not I need to increase it until it becomes divisible. how can I do that ? 回答1: if ($number % 6 != 0) { $number += 6 - ($number % 6); } The modulus operator gives the remainder of the division, so $number % 6 is the amount left over when dividing by 6. This will be faster than doing a loop and continually rechecking. If decreasing is acceptable then this is even faster: $number -= $number % 6; 回答2: if ($variable % 6 == 0) { echo 'This number

Split down a number in seconds to days, hours, minutes, and seconds?

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I've heard that it's possible to accomplish this using the modulus % operator present in most programming languages. The real question is, how? I'm unfamiliar with how modulus works, so I've had difficulties using it in the past. Given the present time here in seconds since 1970, 1307758473.484 , how can I calculate how many years that is, days that is, hours that is, and minutes that is using modulus? I'm essentially looking to format it like this: "5 years, 10 days, 12 hours, 7 minutes, and 18.56 seconds". How would I do this? I'm really interested in learning the logic behind this and not

checking if a number is divisible by 6 PHP

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I want to check if a number is divisible by 6 and if not I need to increase it until it becomes divisible. how can I do that ? ZoFreX if ($number % 6 != 0) { $number += 6 - ($number % 6); } The modulus operator gives the remainder of the division, so $number % 6 is the amount left over when dividing by 6. This will be faster than doing a loop and continually rechecking. If decreasing is acceptable then this is even faster: $number -= $number % 6; if ($variable % 6 == 0) { echo 'This number is divisible by 6.'; }: Make divisible by 6: $variable += (6 - ($variable % 6)) % 6; // faster than while

Please explain why 17 % 40 = 17

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I am new to Java, actually programming in general. I understand that the modulus operator (%) returns the remainder of two numbers, however, I do not understand why 17 % 40 = 17. I understand that 40 % 17 = 6, and 17 % 5 = 2, and 40 % 5 = 0. I get the gist of what value is returned as the remainder. But 17 % 40 = 17 has me stumped. The only rationalization I can devise is that since the remainder is less than 1 the total value 17 is returned, why not 0? Please help to explain this enigma to me. When you divide 17/40, quotient is 0 and the remainder is 17. The modulo operator ( % ) returns the

Detect each 4 using modulus php

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问题 I am trying to detect each 4th post to insert extra code in my layout in wordpress using modulus method but I just cant get it. Here is a short example of mine: <?php if (have_posts()) : ?> <?php $count=0;?> <?php while (have_posts()) : the_post(); ?> <div class="column">  </div> <?php if ($count % 4 == 0){ echo '<div class="clear"></div>'; } $count++; ?> <?php endwhile; ?> <?php endif; ?> all that is inside the while loop. What am I doing wrong? Thank you. 回答1: You need to

How to sort an array of odd numbers in ascending order, but keep even numbers at their position?

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I want to sort only odd numbers without moving even numbers. For example, when I write : sortArray([5, 3, 2, 8, 1, 4]) The expected result is : [1, 3, 2, 8, 5, 4] I am new to JavaScript and I came across a challenge on the Internet that has me perplexed. I normally wouldn't post asking for a solution on the Internet, BUT I have tried for hours and I would like to learn this concept in JavaScript. The challenge states : You have an array of numbers. Your task is to sort ascending odd numbers but even numbers must be on their places. Zero isn't an odd number and you don't need to move it. If you