modulo

问题 This question already has answers here : What does % do in JavaScript? (9 answers) Closed 3 years ago . I am trying to decipher a piece of JS code (while (obviously) my JS knowledge is null). What is the % operator in the code below? m[p1%2][q1] = 0.0; for(j=q1+1; j <= q2; j++) m[p1%2][j] = m[p1%2][j-1] + 1; 回答1: % is remainder operator. It gives the remainder after division. Quoting from MDN The remainder operator returns the remainder left over when one operand is divided by a second

问题 This question already has answers here : Modulo operator with negative values [duplicate] (3 answers) Closed 6 years ago . Please explain the reason behind the following, as mathematically the correct answer is -2 in both cases: int a=7%-5; //Assigns 2 to a int a=-7%5; //Assigns -2 to a The code is in C. 回答1: 7 / -5 = -1 with remainder 2 , because -1 * -5 + 2 = 5 + 2 = 7 . -7 / 5 = -1 with remainder -2 , because -1 * 5 + (-2) = -5 - 2 = -7 . % in C++ is a remainder operator (which for

问题 I have to find the modulo of division of this numbers: 239^(10^9) and 10^9 + 13 239^(10^9) and 10^9 + 15 ... etc up to 1001; Using only native libraries in c++. How to do that? As you can see, the first number is about 3 billion symbols. I tried finding the length of modulo periods, but they are mush longer, than 10, and even unsigned long long int can't deal with such big numbers (239^10). Also I think that "big numbers" algorithms (storing a number as an array) will not work for me too (500

问题 I have 2 queries that pull 2 different data set from the database first one contains the header for a table so if the total results are 10 then we have 10 headers to the table. the second one will have records each with one value for each column. so if I have 5 records this means 5 x 10(total headers) = 50 records in the second dataset. those 50 records I want to display it in the table. My approach is to display one record at a time but after every 10 records close and open a new for the

问题 We know that sum of n terms in a Geometric Progression is given by Sn = a1(1-r^n)/(1-r) if the series is of the form a1, a1*r, a1*r^2, a1*r^3....a1*r^n. Now i have modified geometric progression where series is of the form a1, (a1*r) mod p , (a1*r^2) mod p, (a1*r^3) mod p.....(a1*r^n)mod p where a1 is the initial term, p is prime number and r is common ratio. Nth term of this series is given by: (a1 * r^n-1) mod p. I am trying to get summation formula for above modified GP and struggling very

问题 This question already has answers here : Calculating (a^b)%MOD (6 answers) Closed 4 years ago . I am wondering how to calculate x^y mod z. x and y are very large (can't fit in 64 bit integer) and z will fit 64 bit integer. And one thing don't give answers like x^y mod z is same as (x mod z)^y mod z. 回答1: Here is the standard method, in pseudo-code: function powerMod(b, e, m) x := 1 while e > 0 if e % 2 == 1 x := (b * x) % m e := e - 1 else b := (b * b) % m e := e / 2 return x The algorithm is

问题 I'm writing a program that finds perfect numbers . Having read about these perfect numbers I came across a list of them: List of perfect numbers. At the moment the output is: 28 // perfect 496 // perfect 8128 // perfect 130816 // not perfect 2096128 // not perfect 33550336 // perfect I decided to create array and put it with numbers, which divide the number wholly (without the rest). So I will be able to verify if it is a perfect number or not by adding all elements of the array. But app

问题 So I made a program to do modulo division in Ruby, using a module: module Moddiv def Moddiv.testfor(op1, op2) return op1 % op2 end end Program: require 'mdivmod' print("Enter the first number: ") gets chomp firstnum = $_ print("Enter the second number: ") gets chomp puts secondnum = $_ puts "The remainder of 70/6 is " + Moddiv.testfor(firstnum,secondnum).to_s When I run it with two numbers, say 70 and 6, I get 70 as the output! Why is this happening? 回答1: It's because firstnum and secondnum

问题 For a homework assignment, I need to return the remainder after dividing num1 by num2 WITHOUT using the built-in modulo (%) operator. I'm able to get most tests to pass with the following code, but I'm stuck on how to account for -/+ signs of the given numbers. I need to carry over whichever sign is on num1, and also return a positive number if the num2 is negative - it's blowing my mind how to do this... :) Any clarity would be greatly appreciated! I'm not exactly looking for the straight up

问题 I'm trying to convert an integer to a string right now, and I'm having a problem. I've gotten the code written and working for the most part, but it has a small flaw when carrying to the next place. It's hard to describe, so I'll give you an example. Using base 26 with a character set consisting of the lowercase alphabet: 0 = "a" 1 = "b" 2 = "c" ... 25 = "z" 26 = "ba" (This should equal "aa") It seems to skip the character at the zero place in the character set in certain situations. The