mkdir

Possible Duplicate: How to create directories recursively in ruby? In Ruby, how could I do: mkdir -p cool/beans Here's what I came up with: Dir.mkdir('cool') unless File.directory?('cool') cool_beans_path = File.join('cool', 'beans') Dir.mkdir(cool_beans_path) unless File.directory?(cool_beans_path) But, isn't there a better way? I know I could do: system('mkdir', '-p', File.join('cool', 'beans')) But, that's not platform independent, is it? Like, it works on Mac but not on Windows, right? require 'fileutils' FileUtils.mkdir_p 'cool/beans' 来源： https://stackoverflow.com/questions/11463343/does

I am trying to create a set of nested directories from a Go executable such as 'dir1/dir2/dir3'. I have succeeded in creating a single directory with this line: os.Mkdir("." + string(filepath.Separator) + c.Args().First(),0777); However, I have no idea how to approach creating a predetermined nested set of directories inside of that directory. ANisus os.Mkdir is used to create a single directory. To create a folder path, instead try using: os.MkdirAll(folderPath, os.ModePerm) Go documentation func MkdirAll(path string, perm FileMode) error MkdirAll creates a directory named path, along with

How to make directory within directory by php loop? Example: http://site_name/a/b/c/d First create a then b within a then c within b then .... Problem is here a,b,c,d all the folders created in root directory not one within one. Here is my code - <?php $url = "http://site_name/a/b/c/d"; $details1 = parse_url(dirname($url)); $base_url = $details1['scheme'] . "//" . $details1['host'] . "/"; if ($details1['host'] == 'localhost') { $path_init = 2; }else { $path_init = 1; } $paths = explode("/", $details1['path']); for ($i = $path_init; $i < count($paths); $i++) { $new_dir = ''; $base_url = $base

i am trying to create folders from within php. Whenever i use the mkdir function with permission 0777 i get a read-only folder. I want this folder to be read & write. The parent folder ( drive/ ) is fully writable and readable for every user. This is what i use: mkdir(ABSPATH . 'drive/' . $folderName, 0777); I have also tried to use it without any additional paramaters: mkdir(ABSPATH . 'drive/' . $folderName); Any ideas why this is and how to fix this so that i can generate folders that has write access? In a shared environment, mkdir fails to set the permissions properly. A workaround is to

I'm having trouble creating a folder and writing into it. if(file_exists("helloFolder") || is_dir("helloFolder")){ echo "folder already exists"; } else { echo "no folder, creating"; mkdir("helloFolder", 0755); } This returns "no folder, creating" even when the folder already exists. Then I get this error: Warning: mkdir() [function.mkdir]: No such file or directory in script.php on line 18 Warning: file_put_contents(/filename.txt) [function.file-put-contents]: failed to open stream: Permission denied in script.php on line 58 What is very strange is that I call three separate scripts that do

I am trying to make a dir using a php in english and it's working. But when i try in hebrew, it creats the folder in gibrish like so: ׳”׳•׳¨׳“׳”| ׳׳©׳—׳§ ׳©׳•׳׳˜ how can i fix it? thanks PHP has some Unicode support when dealing with strings, but internally PHP's string type is single-byte and does not support multibyte encodings. If you save your PHP file in UTF-8 format, you can output strings in UTF-8 with the proper HTTP encodings, but many of PHP's functions don't support multi-byte strings. There are some that do, but still most that do not. I looked around in the PHP source and most of

I'm trying to get an expansion command to work with runtime.exec, but the braces are being interpreted as literals rather than being expanded. Here's what I'm trying to do: String command = "mkdir -p Foldername{1,2,3}/InnerFolder"; Runtime.getRuntime().exec( new String[] { "sh", "-c", command } ); Unfortunately, that gives me a single folder in my current directory named "Foldername{1,2,3}" instead of "Foldername1", "Foldername2", and "Foldername3". Does anyone know of a way to prevent the braces from being interpreted as literals? Mateusz You're trying to use Bash wildcards. They are