matrix

Efficient Way to Convert Vector of Distances to Distance Object in R (ideally without creating a full distance matrix)

青春壹個敷衍的年華 提交于 2021-02-10 23:39:52
问题 I have a vector of distances which I get from some other procedure and want to convert it to a dist object in the R language . Below I give an example how such a vector looks like : distVector is computed in the same way said other procedure computes the distance vector. Ideally, I would like to transform this vector into a distance matrix ( dist object) without wasting resources. I think I could just transform it to a matrix by copying it as upper triangular and lower triangular matrix,

How to find all the possible permutations of a matrix in R?

喜欢而已 提交于 2021-02-10 23:20:01
问题 I have a matrix, for example, 5x5. [,1] [,2] [,3] [,4] [,5] [1,] 22 -2 -2 -2 2 [2,] -2 22 2 2 2 [3,] -2 2 22 2 2 [4,] -2 2 2 22 2 [5,] 2 2 2 2 22. As you can see, the matrix is symmetric. Above the main diagonal, there are 4+3+2+1=10 positions, and I find via combn all the possible (permutation) matrices, which have (-2) 3 times in these 10 positions. That means 10!/3!*7!=120 matrices. But some of them are equivalent. So,my problem is how to find the non-equivalent matrices from the 120. I am

How to find all the possible permutations of a matrix in R?

天大地大妈咪最大 提交于 2021-02-10 23:19:03
问题 I have a matrix, for example, 5x5. [,1] [,2] [,3] [,4] [,5] [1,] 22 -2 -2 -2 2 [2,] -2 22 2 2 2 [3,] -2 2 22 2 2 [4,] -2 2 2 22 2 [5,] 2 2 2 2 22. As you can see, the matrix is symmetric. Above the main diagonal, there are 4+3+2+1=10 positions, and I find via combn all the possible (permutation) matrices, which have (-2) 3 times in these 10 positions. That means 10!/3!*7!=120 matrices. But some of them are equivalent. So,my problem is how to find the non-equivalent matrices from the 120. I am

Transforming a correlation matrix to a 3 column dataframe in pandas?

陌路散爱 提交于 2021-02-10 22:49:41
问题 I have a correlation matrix like so a b c a 1 0.5 0.3 b 0.5 1 0.7 c 0.3 0.7 1 And I want to transform this into a dataframe where the columns are like this: Letter1 letter2 correlation a a 1 a b 0.5 a c 0.3 b a 0.5 b b 1 . . . . . . Is there a pandas command to allow me to do this? Thanks in advance And a follow up to this, can I assign a value to the letters in Letter1 like so: Value1 Letter1 Value2 letter2 correlation 1 a 1 a 1 1 a 2 b 0.5 1 a 3 c 0.3 2 b 1 a 0.5 2 b 2 b 1 . . . . . . . . .

Transforming a correlation matrix to a 3 column dataframe in pandas?

强颜欢笑 提交于 2021-02-10 22:49:28
问题 I have a correlation matrix like so a b c a 1 0.5 0.3 b 0.5 1 0.7 c 0.3 0.7 1 And I want to transform this into a dataframe where the columns are like this: Letter1 letter2 correlation a a 1 a b 0.5 a c 0.3 b a 0.5 b b 1 . . . . . . Is there a pandas command to allow me to do this? Thanks in advance And a follow up to this, can I assign a value to the letters in Letter1 like so: Value1 Letter1 Value2 letter2 correlation 1 a 1 a 1 1 a 2 b 0.5 1 a 3 c 0.3 2 b 1 a 0.5 2 b 2 b 1 . . . . . . . . .

How to calculate ray in real-world coordinate system from image using projection matrix?

你说的曾经没有我的故事 提交于 2021-02-10 20:38:56
问题 Given n images and a projection matrix for each image, how can i calculate the ray (line) emitted by each pixel of the images, which is intersecting one of the three planes of the real-world coordinate system? The object captured by the camera is at the same position, just the camera's position is different for each image. That's why there is a separate projection matrix for each image. As far as my research suggests, this is the inverse of the 3D to 2D projection. Since information is lost

How to calculate ray in real-world coordinate system from image using projection matrix?

≡放荡痞女 提交于 2021-02-10 20:35:36
问题 Given n images and a projection matrix for each image, how can i calculate the ray (line) emitted by each pixel of the images, which is intersecting one of the three planes of the real-world coordinate system? The object captured by the camera is at the same position, just the camera's position is different for each image. That's why there is a separate projection matrix for each image. As far as my research suggests, this is the inverse of the 3D to 2D projection. Since information is lost

Im making a simple TicTacToe in pyjama but I am running into some errors

ε祈祈猫儿з 提交于 2021-02-10 18:29:23
问题 The draw Board functions has an if statement to see which colour circle it should draw. But when the mouse button is clicked it draws the circle in the right x coordinate but in the opposite y coordinate. Also, the end is a little bit weird I want to display the winner and then wait using time.wait but it waits and then prints the statement for a second. If you could run it, you would understand. I am also looking for general improvements that I could make. import pygame, sys import numpy as

Matlab : Study of the commutator with 2 Fisher matrices

孤街醉人 提交于 2021-02-10 18:20:24
问题 In Matlab, I have to study the eventual existence of common eigenvectors basis between 2 Fisher matrices FISH_sp and FISH_xc of size 7x7 and diagonalisable. I get from my computation the following result: >> x=null(FISH_sp*FISH_xc-FISH_xc*FISH_sp) x = -0.0085 -0.0048 -0.2098 0.9776 -0.0089 -0.0026 0.0109 In this result, It appears that condition to get a common eigenvectors basis on commutator is true. But I need to further examine the mathematics. If one gets a single column vector, then

Matlab : Study of the commutator with 2 Fisher matrices

爷,独闯天下 提交于 2021-02-10 18:19:06
问题 In Matlab, I have to study the eventual existence of common eigenvectors basis between 2 Fisher matrices FISH_sp and FISH_xc of size 7x7 and diagonalisable. I get from my computation the following result: >> x=null(FISH_sp*FISH_xc-FISH_xc*FISH_sp) x = -0.0085 -0.0048 -0.2098 0.9776 -0.0089 -0.0026 0.0109 In this result, It appears that condition to get a common eigenvectors basis on commutator is true. But I need to further examine the mathematics. If one gets a single column vector, then