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问题 I have a Python module that is intended exclusively for running as a script and never as something that should be imported, and I'd like to enforce (and communicate) that intention in my code. What is the best practice for accomplishing this? I can imagine a few options such as wrapping the whole file in if __name__ == '__main__': # All the code in the module or aborting at the start if __name__ != '__main__': exit() # All the code in the module perhaps with a warning if __name__ != '__main__

问题 This program take real life objects and its weights and sorts it based on alphebatical order and then number-wise But the problem is that when I run this app in Eclipse (haven't tried in NetBeans), it runs fine, but when I compile and try to run it in terminal, it doesn't work and comes with error, "could not find main class" Keep in mind my java file and class file are in the same folder, so the directory is not the problem public class testMain { public static void main(String[] args) { /

问题 This question already has answers here : Closed 9 years ago . Possible Duplicate: What are the valid signatures for C's main() function? What are the different valid prototypes of 'main' function? Are there some non-standard prototypes also supported only by a few vendors? 回答1: The C standard (§ 5.1.2.2.1) defines two entry point prototypes: int main(void); or int main(int argc, char **argv); Other than that, every OS has its own additional non-standard entry points. WinMain, etc. 回答2: The

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . Today I suddenly realized that Java never specifies access level for local variables when I try to declare a variable for main method. I also tried to give it a access level modifier, but it doesn't compile. The

问题 It's difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center. Closed 6 years ago . Today I suddenly realized that Java never specifies access level for local variables when I try to declare a variable for main method. I also tried to give it a access level modifier, but it doesn't compile. The

问题 so if I debug my C++ code using eclipse CDT, it appears that it always start the debugging process from the main() function even though there is no breakpoint at the beginning main()... is there a way to have eclipse CDT start to debug from the first breakpoint rather than main()? 回答1: On the menu Run -> Debug Configurations , right click the C/C++ Applications item on the left, and create New configuration. Go to the Debugger tab and uncheck the Stop on startup at checkbox. 来源： https:/

问题 I have the following doubts related a simple command line Java application. So I have this command line application that is started by a main() method defined inside a Main class. As usual this main() method is defined with this signature: public static void main(String[] args) { It's return type is void , and that should mean it doesn't return any value. But when its execution correctly terminates I obtain following message in the IntelliJ console. Disconnected from the target VM, address:

问题 This question already has answers here : main() function doesn't run when running script (5 answers) Closed 3 years ago . I am writing a simple Python program with some functions, one of which is a main() function executes the other functions. However when I run the code below there is no output. Can someone tell me if they see an error in the structure? def print1(): print("this is also a function") def print2(): print("this is a function") def main(): print1() print2() 回答1: You need to call

问题 This question already has answers here : main() function doesn't run when running script (5 answers) Closed 3 years ago . I am writing a simple Python program with some functions, one of which is a main() function executes the other functions. However when I run the code below there is no output. Can someone tell me if they see an error in the structure? def print1(): print("this is also a function") def print2(): print("this is a function") def main(): print1() print2() 回答1: You need to call

问题 Whenever you declare the main method in a class, you always have to do a String array called "args". What's the point? Unless I live under a rock, command line agruments in Java are barely used anymore. And when I try and run this... //this program won't compile public class SomeClass { public static void main(){ System.out.println("This text will never be displayed :("); } } The output shows this in red text: Error: Main method not found in class SomeClass , please define the main method as: