logic

问题 I have this application in Python Tkinter. There is a Python file which is a main menu. When I click an option in the main menu it imports a python file with code that makes a new window (couldn't use Toplevel for the new window for some reasons). So when I close the main menu it should close all the other windows. Here is my code for the main menu: from tkinter import * root = Tk() root.geometry("600x600") def newWindowImport(): import file1 def newWindowImport2(): import file2 newWindow =

问题 I have this application in Python Tkinter. There is a Python file which is a main menu. When I click an option in the main menu it imports a python file with code that makes a new window (couldn't use Toplevel for the new window for some reasons). So when I close the main menu it should close all the other windows. Here is my code for the main menu: from tkinter import * root = Tk() root.geometry("600x600") def newWindowImport(): import file1 def newWindowImport2(): import file2 newWindow =

问题 What's the difference between the following: a = np.array([2,3,4]) b = np.array([2,7,8]) if a.any() == b.all(): print('yes') and a = np.array([2,3,4]) b = np.array([2,7,8]) if a.any() == b.any(): print('yes') In both situations, 'yes' is printed. 回答1: any() and all() are intended for boolean arrays. any() returns True if there's any values that are equal to True in the array. all() returns True if all values in the array are equal to True . For integers/floats the functionality is similar,

问题 I want to print numbers in pattern as below also I need this to print using only one for loop not in if condition inside for loop. If I give s = 7 the output pattern would be 7, 5, 3, 1, 3, 5, 7 If s=6 then output is 6, 4, 2, 4, 6 This is what I tried but not successful. const s = 7, b = 2 for (x = s, d = b; x > 0 && x <= 7; x -= 2) { console.log(x) } I don't want to use any pre-built libraries to achieve this such as Math.abs() 回答1: With ternary operator: const s = 10, b = 2 for (x = s, step

问题 I have an algorithm that computes shapes using geographic coordinates when certain conditions are satisfied. The algorithm outputs a latitude list and a longitude list like seen below. So lat[0] and lon[0] would represent a coordinate pair. I want to create a boolean array in the shape of a latitude and longitude map where the indices would be true if a corresponding coordinate point exists in the algorithm output. I have the original latitude and longitude information from the netcdf file,

问题 I need to make special rules for some data that I have (if a value is <= 0.1 then make it missing it's an error) but I only want to do it for certain categories. My data looks like this Category value A 0.9 A 0.001 A 0.3 B 0.01 B 0.8 C 0.01 C 0.01 C 0.2 C NA I want this Category value A 0.9 A 0.001 A 0.3 B NA B 0.8 C NA C NA C 0.2 C NA My code looks like this: want<- Mydata %>% mutate(value2= if_else(!is.na(value) & value<=0.1 & Category=='B' || !is.na(value) & value<=0.1 & Category=='C', as

问题 I need to make special rules for some data that I have (if a value is <= 0.1 then make it missing it's an error) but I only want to do it for certain categories. My data looks like this Category value A 0.9 A 0.001 A 0.3 B 0.01 B 0.8 C 0.01 C 0.01 C 0.2 C NA I want this Category value A 0.9 A 0.001 A 0.3 B NA B 0.8 C NA C NA C 0.2 C NA My code looks like this: want<- Mydata %>% mutate(value2= if_else(!is.na(value) & value<=0.1 & Category=='B' || !is.na(value) & value<=0.1 & Category=='C', as

问题 I need to make special rules for some data that I have (if a value is <= 0.1 then make it missing it's an error) but I only want to do it for certain categories. My data looks like this Category value A 0.9 A 0.001 A 0.3 B 0.01 B 0.8 C 0.01 C 0.01 C 0.2 C NA I want this Category value A 0.9 A 0.001 A 0.3 B NA B 0.8 C NA C NA C 0.2 C NA My code looks like this: want<- Mydata %>% mutate(value2= if_else(!is.na(value) & value<=0.1 & Category=='B' || !is.na(value) & value<=0.1 & Category=='C', as

来源： https://stackoverflow.com/questions/64742081/predicate-logic-in-coq

来源： https://stackoverflow.com/questions/64742081/predicate-logic-in-coq