list

replacing values of a dataframe column using values of a list and list name in R

*爱你&永不变心* 提交于 2021-02-11 07:00:09
问题 I would like to replace Values inside of a column with a list name conditional upon the values being inside the list values: df <- data.frame(Activity = c("Checking emails", "Playing games", "Reading", "Watching TV", "Watching YouTube", "Watching TV", "Relaxing", "Getting ready", "Working/ studying", "Relaxing")) mylist <-list(Tech_activity = c("Browsing social media", "Checking emails", "Video calling", "On my computer/ PC", "Watching YouTube", "Browsing the internet", "On my phone",

replacing values of a dataframe column using values of a list and list name in R

我是研究僧i 提交于 2021-02-11 06:59:50
问题 I would like to replace Values inside of a column with a list name conditional upon the values being inside the list values: df <- data.frame(Activity = c("Checking emails", "Playing games", "Reading", "Watching TV", "Watching YouTube", "Watching TV", "Relaxing", "Getting ready", "Working/ studying", "Relaxing")) mylist <-list(Tech_activity = c("Browsing social media", "Checking emails", "Video calling", "On my computer/ PC", "Watching YouTube", "Browsing the internet", "On my phone",

Serialize list of strings as an attribute

試著忘記壹切 提交于 2021-02-11 06:31:25
问题 I am working with XML serialization, I am doing good so far. However, I stumbled with a problem and I wish if you guys can help me with it. I have a class as following: public class FrameSection { [XmlAttribute] public string Name { get; set; } [XmlAttribute] public string[] StartSection { get; set; } } When serialized, I got something like that: <FrameSection Name="VAR1" StartSection="First circle Second circle"/> The problem is with deserialization, I got four items rather than two as space

Count occurance of number from given range

☆樱花仙子☆ 提交于 2021-02-11 06:16:47
问题 My objective is to count the frequency of number in num_lst to the range in num_range. And display the output to a dictionary where key is the range, value is the frequencies of numbers within the range from num_lst. I've seen many posts and most are using numpy or pandas to solve it. However I want to find traditional ways to solve this without using np and pd. Can anyone give me the right direction. num_range = [(0.0, 20.0), (20.0, 40.0), (40.0, 60.0), (60.0, 80.0), (80.0, 100.0)] num_lst =

Count occurance of number from given range

橙三吉。 提交于 2021-02-11 06:16:08
问题 My objective is to count the frequency of number in num_lst to the range in num_range. And display the output to a dictionary where key is the range, value is the frequencies of numbers within the range from num_lst. I've seen many posts and most are using numpy or pandas to solve it. However I want to find traditional ways to solve this without using np and pd. Can anyone give me the right direction. num_range = [(0.0, 20.0), (20.0, 40.0), (40.0, 60.0), (60.0, 80.0), (80.0, 100.0)] num_lst =

Looping over list and removing entries in Python

与世无争的帅哥 提交于 2021-02-11 06:10:26
问题 I want to loop over a list in Python and remove particular items. I don't want to make a new list of accepted items, because in my complete example, I want to make a series of refinements to my list. Here is a simple example, in which I try to remove all numbers that are less than 3 in a list. example = [1.,2.,3.,4.,5.,6.] for e in example: if e < 3.: print "Removing:", e example.remove(e) else: print "Accepting:", e print "NAIVE:", example Removing: 1.0 Accepting: 3.0 Accepting: 4.0

Sorting a list of two element tuples numerically and alphabetically

老子叫甜甜 提交于 2021-02-11 05:29:29
问题 I have an assignment in which I must create a list of tuples from a string. I do this by splitting the string with .split(). I then iterate over the list and add the items and the number of repetitions of each item into a dict, like so: for word in s: if word in count_dict: count_dict[word] += 1 else: count_dict[word] = 1 After this I create a list of tuples using: pairs = count_dict.items() Followed by: count_list = [] for pair in pairs: count_list.append(pair) count_list.sort(key=lambda x:

Aligning two lists in python

好久不见. 提交于 2021-02-11 05:14:40
问题 I have a two Lists one with truth values and other containing experimental results and their associated scores. truth = [6, 8, 7, 10] experiment = [(6, 5), (4, 3), (2, 4), (11, 6), (7, 4)] I want to align my experiment and truth values such that maximum truth value align [6, 8, 7, 10] [6, missing, 7, missing] Now I'd like to assign value to missing from the from among subsequences which are not aligned. Here we chose 11 from among (4, 3), (2, 4), (11, 6) since it has the highest score. The

Aligning two lists in python

旧时模样 提交于 2021-02-11 05:05:42
问题 I have a two Lists one with truth values and other containing experimental results and their associated scores. truth = [6, 8, 7, 10] experiment = [(6, 5), (4, 3), (2, 4), (11, 6), (7, 4)] I want to align my experiment and truth values such that maximum truth value align [6, 8, 7, 10] [6, missing, 7, missing] Now I'd like to assign value to missing from the from among subsequences which are not aligned. Here we chose 11 from among (4, 3), (2, 4), (11, 6) since it has the highest score. The

Scheme: Iterative process to reconstruct a list in original order?

别等时光非礼了梦想. 提交于 2021-02-11 04:55:20
问题 My question is: how to write a procedure that utilises tailcall, and that constructs a list not in the reverse order. To show what I mean, here is an example of a very simple procedure that is iterative, and that creates a copy of a list: (define (copy-list ls) (define (iter cp-ls rest-ls) (if (null? rest-ls) cp-ls (iter (cons (car rest-ls) cp-ls) (cdr rest-ls)))) (iter '() ls)) The problem is that, due to the iterative order in which the elements are cons ed together, the returned list ends