line-numbers

Does anyone know how I can get the current line number of an System.Xml.XmlReader? I am trying to record where in a file I find Xml elements. Take advantage of the IXmlLineInfo interface supported by an XmlReader : IXmlLineInfo xmlInfo = (IXmlLineInfo)reader; int lineNumber = xmlInfo.LineNumber; Expanding on the IXmlLineInfo interface, the documentation for this is pretty bad; from doing a bit of digging, I can tell you the following: 1) System.Xml.XmlReader is abstract, so you're never going to be dealing with an instance of this, as such, the fact that it doesn't implement IXmlLineInfo isn't

How would one display what line number caused the error and is this even possible with the way that .NET compiles its .exes? If not is there an automated way for Exception.Message to display the sub that crapped out? try { int x = textbox1.Text; } catch(Exception ex) { MessageBox.Show(ex.Message); } Steven A. Lowe Use ex.ToString() to get the full stack trace. You must compile with debugging symbols (.pdb files), even in release mode, to get the line numbers (this is an option in the project build properties). To see the stacktrace for a given Exception, use e.StackTrace If you need more

How can I add line numbers to a range of rows in vim? Not as in ":set nu" - this just displays numbers, but doesn't add them to the file. Luc Hermitte With :%s/^/\=line('.')/ EDIT: to sum up the comments. This command can be tweaked as much as you want. Let's say you want to add numbers in front of lines from a visual selection ( V + move), and you want the numbering to start at 42. :'<,'>s/^/\=(line('.')-line("'<")+42)/ If you want to add a string between the number and the old text from the line, just concatenate (with . in VimL) it to the number-expression: :'<,'>s/^/\=(line('.')-line("'<")

I require help to search a text file (log file) using c# and display the line number and the complete line that contains the search keyword. This is a slight modification from: http://msdn.microsoft.com/en-us/library/aa287535%28VS.71%29.aspx int counter = 0; string line; // Read the file and display it line by line. System.IO.StreamReader file = new System.IO.StreamReader("c:\\test.txt"); while((line = file.ReadLine()) != null) { if ( line.Contains("word") ) { Console.WriteLine (counter.ToString() + ": " + line); } counter++; } file.Close(); Bit late to the game on this one, but happened