latitude-longitude

Convert x,y to latitiude and longitude

无人久伴 提交于 2020-05-17 07:45:11
问题 If I have a map image where: The latitude and longitude of the upper left corner (x=0, y=0) are known The width and height of the image is known Zoom (z-axis) is known. Can we compute the latitude and longitude for other coordinates in the image? For example, in the following image if I want to compute the lat/lon values for the white ploygon (where the coordinates (x,y) are known) 回答1: So given the information and the shape of the image, (see previous question): import numpy as np top_left =

Searching a MySQL database for values serving the input lat/long

隐身守侯 提交于 2020-05-17 07:03:07
问题 This question is different from regular mysql lat/long, radius based data fetching I want to search a mysql database table which contains following columns for example- ID Items lat long serving_radius(in km) 1 Item1 26.120888 85.364723 2 2 Item2 26.120888 85.364723 5 3 Item3 25.859800 85.786598 4 4 Item4 26.594900 85.504799 8 Now if a user has lat/long (29.941095/77.812424) wants to know which of these items can be served at his location. Then how i will fetch the result using php & mysql.

out of bounds latitude and longitude values in converted shape file using ggplot

牧云@^-^@ 提交于 2020-05-16 03:22:19
问题 I'm trying to map the Pennyslvania counties using data from the PA Geospatial Data Clearinghouse. I read in the shape file and then convert it to a dataframe like so: setwd(proj_path) dsn <- "Data/PaCounty2019_07/PaCounty2019_07.shp" map <- readOGR(dsn) map_df <- tidy(map) I then plot it like so: ggplot() + geom_path(data = map_df, aes(x = long, y = lat, group = group)) + labs(title = "ggplot map of pa counties") This works, but the lat/long scale is very weird. Latitude goes from -100,000 to

android get current location name

心不动则不痛 提交于 2020-02-21 13:44:58
问题 Hey guys i want get current location with name. I did coding for get current location (lat,lang) how can i show relative place name (ie) 13.006389 - 80.2575 : Adyar,Chennai,India LocationManager locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE); locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, 0, new LocationListener() { public void onStatusChanged(String provider, int status, Bundle extras) { // called when the location provider status

android get current location name

非 Y 不嫁゛ 提交于 2020-02-21 13:44:18
问题 Hey guys i want get current location with name. I did coding for get current location (lat,lang) how can i show relative place name (ie) 13.006389 - 80.2575 : Adyar,Chennai,India LocationManager locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE); locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 0, 0, new LocationListener() { public void onStatusChanged(String provider, int status, Bundle extras) { // called when the location provider status

how to group data by LatLong distance in R

℡╲_俬逩灬. 提交于 2020-02-21 06:55:46
问题 I have a function distance(lat1,lon1, lat2,lon2) that calculates the distance of 2 points. Suppose I have a dataframe with some points and values: n<-c(lon = -1.729219, lat = 29.730836) o<-c(lon = -5.041928, lat = 28.453022) e<-c(lon = -2.700067, lat = 29.198922) s<-c(lon = -5.212864, lat = 28.531739) centro<-matrix(c(n,o,e,s), ncol=2, byrow=TRUE) d<-data.frame(c=centro, amount=c(3.5,3.5,3.5,3.5), count=c(12,12,12,12)) colnames(d)<-c('lon','lat','amount','count') I want to get a a new

how to group data by LatLong distance in R

僤鯓⒐⒋嵵緔 提交于 2020-02-21 06:55:33
问题 I have a function distance(lat1,lon1, lat2,lon2) that calculates the distance of 2 points. Suppose I have a dataframe with some points and values: n<-c(lon = -1.729219, lat = 29.730836) o<-c(lon = -5.041928, lat = 28.453022) e<-c(lon = -2.700067, lat = 29.198922) s<-c(lon = -5.212864, lat = 28.531739) centro<-matrix(c(n,o,e,s), ncol=2, byrow=TRUE) d<-data.frame(c=centro, amount=c(3.5,3.5,3.5,3.5), count=c(12,12,12,12)) colnames(d)<-c('lon','lat','amount','count') I want to get a a new

sorting distance in MySQL PHP [duplicate]

こ雲淡風輕ζ 提交于 2020-02-08 10:18:05
问题 This question already has answers here : Closed 7 years ago . Possible Duplicate: mysql_fetch_array() expects parameter 1 to be resource, boolean given in select My Code: <?php $Sql="SELECT *, (3959 * acos(cos(radians(37)) * cos(radians(44)) * cos(radians(55) - radians(-122)) + sin(radians(37)) * sin(radians(44))) as distance FROM TableName HAVING distance < 25 ORDER BY distance LIMIT 0 , 20"; $result=mysql_query($Sql); while ($row = mysql_fetch_array($result)){ echo $row['Id']; } Error:

Converting Latitude Longitude Coordinates to Image Map Coordinates

做~自己de王妃 提交于 2020-01-30 03:30:36
问题 I'm almost positive this has been answered already; however, unable to find it since XY coordinates are overloaded due to their relative definition. What I am trying to find/figure out is how to take latitude/longitude coordinates (e.g. 12.121212, -12.323232) and convert such so they can be mapped onto a 2-dimensional plane such as a point on an image map. Has anyone solved this issue and know of a script or another SO question that they can point me to? Ideally I'm seeking a solution in

Extracting XML data to php [duplicate]

拜拜、爱过 提交于 2020-01-28 08:41:12
问题 This question already has answers here : How do you parse and process HTML/XML in PHP? (30 answers) Closed 6 years ago . I'm trying to extract data from XML file (http://freegeoip.net/xml/google.com). You can see the content of the file looks something like: <Response> <Ip>74.125.235.3</Ip> <CountryCode>US</CountryCode> <CountryName>United States</CountryName> <RegionCode>CA</RegionCode> <RegionName>California</RegionName> <City>Mountain View</City> <ZipCode>94043</ZipCode> <Latitude>37.4192<