laravel-pagination

Using limit parameter in paginate function

由 你说的曾经没有我的故事 提交于 2020-08-04 08:55:28
问题 Is it possible to use 'limit' parameter in paginate() function? I'm trying this: $users->where(...)->limit(50)->paginate($page) ...and now, if I have 100 users in the database then the response from paginate function will be all 100 users instead of 50 (or number of users defined with limit parameter). So, my question is: is it possible to implement limit parameter when I use paginate function? 回答1: No, it's not possible to limit the query when using pagination. Query pagination uses skip()

Laravel's Illuminate paginator can't find query string

由 孤人 提交于 2020-03-03 11:32:14
问题 I'm working on a old PHP project, that is running in legacy SQL query, which is good but I like to use query builders like Laravel Illuminate SQL package! So i have added all required package dependencies to run Illuminate SQL, and this query builder seems to work fine with pagination! $users = Capsule::table('users')->paginate(1)->toArray(); But, the paginator seems not to be able to listen the query string! For example, by running the above code it would give some properties like, next_page

Laravel infinite scroll for pagination output

由 落花浮王杯 提交于 2020-01-17 05:53:23
问题 I'm new to laravel and I'm working on a project based on laravel version 4.2. I've got some problems with loading more results using scroll instead of default pagination. I know there are jQuery plugins that can help me out in this, but none of them or suggested ways in web could help me out well. so here is my code : laravel model //inside a AdGenerator class public function allAds(){ $allAds = DB::table('infos')->paginate(10); return $allAds; } laravel controller //inside controller $ads =

MySQL error is thrown when laravel pagination is used

由 ⅰ亾dé卋堺 提交于 2019-12-11 04:14:22
问题 I have a database view created and when I use laravel pagination against this view, it throws: SQLSTATE[42000]: Syntax error or access violation: 1140 Mixing of GROUP columns (MIN(),MAX(),COUNT(),...) with no GROUP columns is illegal if there is no GROUP BY clause (SQL: select count(*) as aggregate from `parameter_log_site_detail` where `site_id` = EPE) But this error pops up only in live server. Pagination works fine in local server. DB View: (parameter_log_site_detail) select `t`.`site_id`

Manual Pagination Error - Laravel 5.0

由 ⅰ亾dé卋堺 提交于 2019-12-11 03:43:39
问题 I am getting the following error while passing an array, count(array) and itemsPerPage as arguments. Call to undefined method Illuminate\Pagination\Paginator::make() I tried following with it but cant fix the error. use Illuminate\Pagination\LengthAwarePaginator as Paginator; use Illuminate\Pagination; use Illuminate\Support\Facades\Paginator; use Illuminate\Pagination\Factory; use App\Response; make method is defined in http://laravel.com/api/5.0/Illuminate/Pagination/Environment.html#method

laravel show only next and previous link in pagination

由 …衆ロ難τιáo~ 提交于 2019-12-10 16:33:39
问题 I ma trying to use Laravel Pagination and I only want to show the Previous and Next link with out the number 1 2 3 ... how could I do that? I followed Laravel page : "Simple Pagination" If you are only showing "Next" and "Previous" links in your pagination view, you have the option of using the simplePaginate method to perform a more efficient query. This is useful for larger datasets when you do not require the display of exact page numbers on your view: $someUsers = User::where('votes', '>'

Laravel 5 - Finding the pagination page for a model

由 百般思念 提交于 2019-12-04 23:59:38
问题 I am working on building a basic forum (inspired by laracasts.com/discuss). When a user posts a reply to a thread: I'd like to direct them to the end of the list of paginated replies with their reply's anchor (same behavior as Laracasts). I'd also like to return the user to the correct page when they edit one of their replies. How can I figure out which page a new reply will be posted on ( ?page=x ) and how can I return to the correct page after a reply has been edited? Or, from the main post

Laravel 5 - Finding the pagination page for a model

由 核能气质少年 提交于 2019-12-03 15:14:38
I am working on building a basic forum (inspired by laracasts.com/discuss ). When a user posts a reply to a thread: I'd like to direct them to the end of the list of paginated replies with their reply's anchor (same behavior as Laracasts). I'd also like to return the user to the correct page when they edit one of their replies. How can I figure out which page a new reply will be posted on ( ?page=x ) and how can I return to the correct page after a reply has been edited? Or, from the main post listing, which page the latest reply is on? Here is my current ForumPost model (minus a few unrelated

Eager Loading with Pagination

由 大憨熊 提交于 2019-12-01 13:32:49
问题 I have a a group instance I want to eager load with pagination: public function show(Group $group) { $group = $group->with('members); return$ group } I want to return group with members paginated. 回答1: Use setRelation() and lazy loading: public function show(Group $group) { return $group->setRelation('members', $group->members()->paginate(5)); } 回答2: You can do that but it's not recommended because using paginate for eager loaded relationships generates two repeated queries public function

Laravel Pagination

由 雨燕双飞 提交于 2019-11-30 09:24:52
问题 How can I create a pagination in laravel? My Model Post function comments() { return $this->hasMany('Comment') ->orderBy('created_at', 'desc'); } Comment function posts(){ return $this->belongsTo('Post'); } User function posts(){ return $this->hasMany('Post'); } function comments(){ return $this->hasMany('Comment'); } UserController $user = User::find(1); //this will give me all the user's post and comment details //i know I can do $user = User::paginate(30) to get 30 user per page What I
订阅 laravel-pagination