jsonserializer

问题 I'm currently setting-up my application, and i need to manage a json file (that contain some settings) in my windows form. Once you open it, you can easy choose different settings, and once you've done, you can save it (which mean i need to overwrite the existing one json file settings, and replace it with new one! I tried to follow this guide for correctly create my json file! But i met 2 problems: This solution mentioned up, create square brackets (which i don't need!) Seems to create all

问题 I want to add a wrapper which named is determined at runtime, because it depends of the class name (I could use @JsonRootName but I don't want to because I would have to use it on every sub class, which is not efficient). I suppose I should use @JsonSerialize to override the default serializer, but I want that just to create the wrapper; I don't want to serialize the object fields myself (also I am in an abstract class, so I don't even know the fields of the sub class!). I don't care about

来源： https://stackoverflow.com/questions/64059550/system-json-net-deserializing-a-taskt-fails-no-parameterless-constructor

来源： https://stackoverflow.com/questions/64059550/system-json-net-deserializing-a-taskt-fails-no-parameterless-constructor

问题 I have case class case class User ( id: Option[Long] = None, username: String, password: Option[String] = None, ) And here is json serialiser for this case class object User { implicit val userWrites: Writes[User] = ( (JsPath \ "id").write[Option[Long]] and (JsPath \ "username").write[String] and (JsPath \ "password").write[Option[String]] and )(unlift(User.unapply)) } But I don't want to expose password field in api response. How can I achieve it? I use also use this for Slick to read/write

问题 May be, it is not so problematic for you. but i'm trying first time with json serialization. and also read other articles in stackowerflow. I have created Entity Framework data model. then by method get all data from object: private uqsEntities _db = new uqsEntities(); //get all data from table sysMainTableColumns where tableName=paramtableName public List<sysMainTableColumns> getDataAboutMainTable(string tableName) { return (from column in _db.sysMainTableColumns where column.TableName=

问题 May be, it is not so problematic for you. but i'm trying first time with json serialization. and also read other articles in stackowerflow. I have created Entity Framework data model. then by method get all data from object: private uqsEntities _db = new uqsEntities(); //get all data from table sysMainTableColumns where tableName=paramtableName public List<sysMainTableColumns> getDataAboutMainTable(string tableName) { return (from column in _db.sysMainTableColumns where column.TableName=

问题 I have class Menu, it's a self to self with manytoone and onetomany relational. package models; import java.util.*; import javax.persistence.*; import play.db.ebean.*; import play.data.format.*; import play.data.validation.*; import static play.data.validation.Constraints.*; import javax.validation.*; import org.codehaus.jackson.annotate.JsonBackReference; import org.codehaus.jackson.annotate.JsonIgnore; import org.codehaus.jackson.annotate.JsonManagedReference; import com.avaje.ebean.*;

问题 I use Json.Net. When I serialize a Department2 object and WriteJson() is invoked I want it to be recursively invoked with each of the Telephone2 objects like I do in ReadJson() . How do I do that? using System; using Newtonsoft.Json; using Newtonsoft.Json.Linq; public interface ISimpleDatabag { string Databag { get; set; } } [JsonConverter(typeof(JsonDataBagCreationConverter<Department2>))] public class Department2 { public Telephone2[] Phones { get; set; } } [JsonConverter(typeof

问题 I have a django app which was running on 1.4.2 version and working completely fine, but recently i updated it to django 1.6.5 and facing some wierd errors like below Actually i am getting this during user/client registration process in my site functionality Request URL: http://example.com/client/registration/ Django Version: 1.6.5 Exception Type: TypeError Exception Value: <Client: test one> is not JSON serializable Exception Location: /usr/lib/python2.7/json/encoder.py in default, line 184