json-simple

How to modify the value of a particular field in a JSON file using json-simple, after parcing the JSON file

做~自己de王妃 提交于 2020-07-08 03:15:09
问题 I need to modify a particular value of a key in my json file, it is a nested JSON file and i have traversed till that key value pair but i'm not able to modify the value and don't know how to write back to the json. Using json-simple to parse the JSON This is the JSON file: { "entity": { "id": "ppr20193060018", "data": { "relationships": { "productpresentationtolot": [ { "id": "", "relTo": { "id": "", "data": { "attributes": { "rmsitemid": { "values": [ { "source": "internal", "locale": "en

How to modify the value of a particular field in a JSON file using json-simple, after parcing the JSON file

风流意气都作罢 提交于 2020-07-08 03:12:43
问题 I need to modify a particular value of a key in my json file, it is a nested JSON file and i have traversed till that key value pair but i'm not able to modify the value and don't know how to write back to the json. Using json-simple to parse the JSON This is the JSON file: { "entity": { "id": "ppr20193060018", "data": { "relationships": { "productpresentationtolot": [ { "id": "", "relTo": { "id": "", "data": { "attributes": { "rmsitemid": { "values": [ { "source": "internal", "locale": "en

How can I get multiple json data from json file one by one?

﹥>﹥吖頭↗ 提交于 2020-05-17 07:06:43
问题 I am trying to get specific value from json file. Here is my json file. { "set_with_ratio": { "tweaks_es": "7", "ratio": { "brand_defined_sets_ratio": { "default": { "desktop": { "16": "85", "11": "95", "19": "10", "12": { "2": "50" } } }, "rentals": { "desktop": { "16": "75", "11": "45", "12": { "2": "10" } } } } } } } how can I get data for x.set_with_ratio.ratio.brand_defined_sets_ratio.default.desktop.11 this json path. I am trying this code in Java. JSONParser jsonParser = new JSONParser

Decode JSON with Java

本秂侑毒 提交于 2020-01-06 13:28:46
问题 I am trying to decode JSON data with Java. I found a library at the following link: http://code.google.com/p/json-simple/wiki/DecodingExamples I have included the .jar file in the build path in my eclipse project, which added the library under "Referenced Libraries". But when I try to use the library as shown in the first example in the link above, the type is not found. String s="[0,{\"1\":{\"2\":{\"3\":{\"4\":[5,{\"6\":7}]}}}}]"; Object obj=JSONValue.parse(s); // Error: JSONValue cannot be

JSON: “Unexpected character (<) at position 0”

纵然是瞬间 提交于 2020-01-02 18:17:21
问题 Here's the twitch.tv api request to get channel summary: http://api.justin.tv/api/streams/summary.json?channel=mychannel . If I post it via browser, I get correct results. But programmatically I receive an exception during result parsing. I use apache HttpClient to send requests and receive responses. And JSON-Simple to parse JSON content. This is how I try to get JSON from response according to api: HttpClient httpClient = HttpClients.createDefault(); HttpGet getRequest = new HttpGet(new URL

How to tell if return is JSONObject or JSONArray with JSON-simple (Java)?

北城以北 提交于 2020-01-01 09:09:41
问题 I am hitting a service and sometimes getting back something like this: { "param1": "value1", "param2": "value2" } and sometimes getting return like this: [{ "param1": "value1", "param2": "value2" },{ "param1": "value1", "param2": "value2" }] How do I tell which I'm getting? Both of them evaluate to a String when I do getClass() but if I try to do this: json = (JSONObject) new JSONParser().parse(result); on the second case I get an exception org.json.simple.JSONArray cannot be cast to org.json

How can I cast a JSONObject to a custom Java class?

我只是一个虾纸丫 提交于 2020-01-01 07:56:14
问题 In Java (using json-simple) I have successfully parsed a JSON string which was created in JavaScript using JSON.stringify. It looks like this: {"teq":14567,"ver":1,"rev":1234,"cop":15678} This string is storing the state of a custom JavaScript object which I now wish to re-constitute as a pure Java class. Its not going well - first foray into Java coming from a C# background. :-p The object is currently in the form of a org.json.simple.JSONObject since that is what json-simple made from the

Casting JSONArray to Iterable<JSONObject> - Kotlin

試著忘記壹切 提交于 2019-12-23 22:56:55
问题 I am using Json-Simple in Kotlin. In what situations could this cast: val jsonObjectIterable = jsonArray as Iterable<JSONObject> Become dangerous? jsonArray is a JSONArray object. 回答1: You can cast it successfully, since JSONArray is-A Iterable . but it can't make sure each element in JSONArray is a JSONObject. The JSONArray is a raw type List , which means it can adding anything, for example: val jsonArray = JSONArray() jsonArray.add("string") jsonArray.add(JSONArray()) When the code

How to parse from JSON to Map with Json-Simple and retain key order

╄→尐↘猪︶ㄣ 提交于 2019-12-18 17:30:16
问题 I'm using Json-Simple to write a config file using JSon-Simple lib, but I'm having problems converting the json string to map. Debugging I have found that parse method returns an object that is a Map! but when I try to cast directly to a LinkedMap I get a ClassCastException: String json = aceptaDefault(); JSONParser parser = new JSONParser(); Object obj = parser.parse(json); LinkedHashMap map = (LinkedHashMap)obj; 回答1: You can't just cast a Map to a LinkedHashMap unless you know the

Pretty-Print JSON in Java

[亡魂溺海] 提交于 2019-12-16 22:14:23
问题 I'm using json-simple and I need to pretty-print JSON data (make it more human readable). I haven't been able to find this functionality within that library. How is this commonly achieved? 回答1: GSON can do this in a nice way: Gson gson = new GsonBuilder().setPrettyPrinting().create(); JsonParser jp = new JsonParser(); JsonElement je = jp.parse(uglyJSONString); String prettyJsonString = gson.toJson(je); 回答2: I used org.json built-in methods to pretty-print the data. JSONObject json = new