jquery-forms-plugin

Initialize jQuery validate() function on multiple dynamically added forms

冷暖自知 提交于 2019-12-02 11:41:35
It is has been suggested that it is best to initialize a $('#form').validate({}) function on page load rather than on a click event: jquery.form/validate plugin only allow submit if input is changed I'm wondering how to do this for multiple dynamically added forms without wrapping the $('#form').validate({}) function inside of a on('click', 'input[type="submit"]', function. Take this code for example: var id="some identifier for the specific form that is submitted"; `$('#form'+id).validate({})` How does this unique identifier, id , which is required to distinguish each form get created in the

JQuery Ajax Form and Dynamically created form elements not submitting

淺唱寂寞╮ 提交于 2019-12-01 20:08:52
I'm writing a form that has some text input elements loaded dynamically when a select list is changed. The problem is that when I submit the form those elements are not sent in the data that is posted to the server. What do I need to do to get those dynamically created elements "into" the form to be submitted? The code is something like this: $("#my_select_id").change(function() { $.ajax({ type: "GET", url: "some-url/" + $("#played_number_game_id").children("option:selected").val(), async: false, dataType: "html", error: function(XMLHttpRequest, status, errorThrown) { alert("oh no!"); alert

JQuery Form Plugin File Upload using POST redirects to POST response

≯℡__Kan透↙ 提交于 2019-12-01 18:49:52
Please help guys, This one is a major BLOCKER! I have a project that uses NodeJS + jQuery Form Plugin + Typescript in which I am trying to do a file upload. After the file upload the server sends a response to the POST message which renders on the screen. The file does get uploaded successfully and completely before the POST response renders on the screen. I expect the POST response to call the "success" function instead of having the page redirected to show the JSON response. Here's the code: $(new ID().setAsRoot().selectId()).append( "<form id=\"fileUploadForm\" accept-charset=\"utf-8\"

jquery getResponseHeader always returns 'undefined'?

让人想犯罪 __ 提交于 2019-12-01 02:32:04
I have a a form that I am submitting via ajax. I am using the jquery form plugin. What I am trying to do is get the 'Location' header which is returned from my server. I can see it in firebug. But whenever I call the getResponseHeader() function in my success callback, it always returns 'undefined'.. Code: form.ajaxForm({ dataType: 'xml', data: {format: 'xml'}, resetForm: true, success: function(xml,status,xhr){ var location = xhr.getResponseHeader('Location'); alert(location); }); location is undefined. But I can see the 'Location' header in firebug. What am I missing? Even if I call

jquery trigger: how can I trigger the browse file in the input when I click on a text link?

▼魔方 西西 提交于 2019-12-01 00:33:52
问题 Following up on this post, I have another issuer - how can I trigger the browse file in the input when I click on a text link? Basically I want to hide the form but it will be triggered when you click on the upload text link. <a href="#" class="upload">upload</a> <form action="upload.php" method="post" enctype="multipart/form-data" id="myForm" style="display:none;"> <input type="file" multiple="multiple" name="file[]" /> <input type="submit" name="upload" value="Submit"/> </form> <div id=

How can I avoid calling jquery twice

喜欢而已 提交于 2019-11-30 22:52:45
I am using Jquery Form Plugin to submit my form. The head tag of my html file looks like following <script type="text/javascript" src="js/jquery-1.7.1.min.js"></script> then 10 other javascript files AND Then <script type="text/javascript" src="js/jquery-1.7.1.min.js"></script> <script type="text/javascript" src="js/jquery.form.js"> <script type="text/javascript"> $(document).ready(function() { var options = { success: showResponse }; $('#myForm').ajaxForm(options); }); </script> To see the actual picture of my code please check this http://jsfiddle.net/Xfrms/1/ The problem is even though I

How can I avoid calling jquery twice

北战南征 提交于 2019-11-30 17:55:20
问题 I am using Jquery Form Plugin to submit my form. The head tag of my html file looks like following <script type="text/javascript" src="js/jquery-1.7.1.min.js"></script> then 10 other javascript files AND Then <script type="text/javascript" src="js/jquery-1.7.1.min.js"></script> <script type="text/javascript" src="js/jquery.form.js"> <script type="text/javascript"> $(document).ready(function() { var options = { success: showResponse }; $('#myForm').ajaxForm(options); }); </script> To see the

Uploading a file and passing a additional parameter with multer

妖精的绣舞 提交于 2019-11-30 14:34:40
I am using the jQuery Form Plugin and multer to upload files to my server. This works just fine, but I am trying to pass an additional parameter, which will determine where exactly the file will be saved. I have following code, which I would like to extend to behave as stated: HTML <form id="uploadForm" enctype="multipart/form-data" action="/files" method="post"> <input type="file" id="userFile" name="userFile"/> <input type="text" hidden id="savePath" name="savePath" value="path"/> </form> Client JS uploadForm.submit(function() { $(this).ajaxSubmit({ error: function(xhr) { console.log('Error:

ASP.NET WEBAPI file upload, issues with IE9

♀尐吖头ヾ 提交于 2019-11-30 05:53:37
I have created a file upload method using ASP.NET WEBAPI, below the code: [DataContract] public class FileDesc { [DataMember] public string name { get; set; } [DataMember] public string url { get; set; } [DataMember] public long size { get; set; } [DataMember] public string UniqueFileName { get; set; } [DataMember] public int id { get; set; } [DataMember] public DateTime modifiedon { get; set; } [DataMember] public string description { get; set; } public FileDesc(string rootUrl, FileInfo f,int pId, string aFileName) { id = pId; name = aFileName; UniqueFileName = f.Name; url = rootUrl + "/Files

jquery form plugin, no error handling

送分小仙女□ 提交于 2019-11-29 23:09:58
It seems that there are no error handling facility in the Jquery.Form plugin, which is very frustrating. Even though the documentation says we can use the $.ajax options, I still cannot make use of the 'error' option when the server returns an error, especially the 500 and 400 series. Is it that this plugin cannot handle any error at all from the server or is it a bug, etc? Can someone please tell me how I can handle errors (400, 500, etc) with this plugin? I need your help... All I want is a simple error handling... Thank you. $("#uploadingImg").hide(); var options = {//Define ajax options