java-7

问题 I am getting the following error while deploying a Maven project in WAS 8.5.5. I have installed JDK 1.6 and 1.7 in WAS. Error 500: org.springframework.web.util.NestedServletException: Handler processing failed; nested exception is java.lang.VerifyError: JVMVRFY012 stack shape inconsistent; class=com/xyz/simtools/savings/jaxb/SavingsInput_JAXB_Deserialization_Stub, method=write(ILjava/lang/Object;)V, pc=356 Things I noticed: In Tomcat, it's working fine There was some fix for this in IBM JDK

问题 i am writing a code i am creating a directory with java nio api my segment of code is Path target = Paths.get(""+folder_path+xx[0]); Set<PosixFilePermission> perms = null; if(xx[2].toLowerCase().equals("read")) perms =PosixFilePermissions.fromString("r--------"); if(xx[2].toLowerCase().equals("read/write")) { perms =PosixFilePermissions.fromString("rw-------"); } FileAttribute<Set<PosixFilePermission>> attr = PosixFilePermissions.asFileAttribute(perms); Files.createDirectory(target, attr);

问题 I wish to find out does anyone have problem compiling JDK 7 code with Eclipse? Because currently I only able use JRE 7 in Eclipse to test run but as for trying to use JDK 7 features into my code, it will state it will not support. 回答1: Eclipse 3.8 M1 (Juno) is the earliest stable version to have support for Java 7. Java 7 support will also be available in the upcoming 3.7.1 release. Unfortunately, since Java 7 released after Eclipse 3.7 (Indigo) release, the Java 7 support could not make it

问题 I would like to use dependency injection in a large Java 7 standalone application, but I am not really sure where to start. I have written a small test application: public class Main { @Inject MyInterface myInterface; public static void main( String[] args ) { Main m = new Main(); System.out.println(m.myInterface.getMessage()); } } with an interface: public interface MyInterface { String getMessage(); } and an interface implementation: @Singleton public class MyInterfaceImpl implements

问题 According to The Java Tutorials, in Java SE 7 and later, you can use a String object in the switch statement's expression. String s = ... switch(s){ //do stuff } But is this true? I've installed the JRE and added it to the build path of my Eclipse project, but I'm getting the following compile-time error: Cannot switch on a value of type String. Only convertible int values or enum constants are permitted Also, I think I've got it configured correctly since I was able to use its java.nio.file

问题 What is the difference in the two following declarations of an ArrayList? ArrayList<Integer> nunbers = new ArrayList<Integer>(); vs ArrayList<Integer> nunbers = new ArrayList<>(); Is one of them preferred over the other? 回答1: The second one has its type parameter inferred , which is a new thing in Java 7. <> is called "the diamond". Also note that type inference itself is not new in Java, but the ability to infer it for the generic class being instantiated is new. Compilers from releases

问题 I am looking at the following Stack Overflow answer: How to change Spring's @Scheduled fixedDelay at runtime And in the code there is the following line: schedulerFuture = taskScheduler.schedule(() -> { }, this); I would like to know what the lambda () -> {} means in that code. I need to write it without using lambdas. 回答1: Its a Runnable with an empty run definition. The anonymous class representation of this would be: new Runnable() { @Override public void run() { // could have done

问题 In JavaScript, it is possible to write a self-executing function like this: (function foo() { console.log("bar"); }()); I'm looking to do this in Java. So for example: // This code does not work obviously public static void main(String[] args) { (foo() { System.out.println("bar"); }()); } Is there such a thing? 回答1: That javascript isn't really creating a "self-executing" function. It's defining a function, and then immediately executing it. Java doesn't let you define standalone functions,

问题 Please see the below code sample JavaRDD<String> mapRDD = filteredRecords .map(new Function<String, String>() { @Override public String call(String url) throws Exception { BufferedReader in = null; URL formatURL = new URL((url.replaceAll("\"", "")) .trim()); try { HttpURLConnection con = (HttpURLConnection) formatURL .openConnection(); in = new BufferedReader(new InputStreamReader(con .getInputStream())); return in.readLine(); } finally { if (in != null) { in.close(); } } } }); here url is

问题 In previous versions of Java, I would read a file by creating a buffered reader like this: BufferedReader in = new BufferedReader(new FileReader("file.txt")); In Java 7, I would like to use Files.newBufferedReader, but I need to pass in a charset as well. For example: BufferedReader in = Files.newBufferedReader(Paths.get("file.txt"), Charset.forName("US-ASCII")); Previously, I did not have to worry about charsets when reading plain text files. What charset shall I use? Do you know what