java-7

how do you account for two possible date formats one with milliseconds and one without when parsing date using simpledateformat? [duplicate]

浪尽此生 提交于 2021-01-29 18:03:36
问题 This question already has answers here : How to parse dates in multiple formats using SimpleDateFormat (12 answers) Java LocalDateTime.parse with millisecond precision but optional microsecond precision (1 answer) How to check validity of Date String? (4 answers) Closed 5 months ago . There can be two different date time formats as shown below. The second variant has milliseconds time. 2020-09-07T16:15:42Z 2020-09-09T11:41:58.5152Z Currently i am using this way to parse the date. Is there a

Fibonacci using Fork Join in Java 7

大兔子大兔子 提交于 2021-01-28 20:21:33
问题 This is a program for Fibonacci using Java 7 ForkJoin . But seems like there is a dead lock. package ForkJoin; import java.time.LocalTime; import java.util.concurrent.ForkJoinPool; import java.util.concurrent.RecursiveTask; import static java.time.temporal.ChronoUnit.MILLIS; class Fibonacci extends RecursiveTask<Integer>{ int num; Fibonacci(int n){ num = n; } @Override protected Integer compute() { if(num <= 1) return num; Fibonacci fib1 = new Fibonacci(num-1); fib1.fork(); Fibonacci fib2 =

Unexpected behavior with Calendar class of Java

两盒软妹~` 提交于 2021-01-28 08:22:49
问题 I have following code to get different parts of current system Date (10-11-2011 for this case). Calendar now = Calendar.getInstance(); String dt = ""+now.get(now.DATE)+"-"+now.get(now.MONTH)+"-"+now.get(now.YEAR); Here, DATE and YEAR fields are giving values as expected but MONTH field is giving unexpected results, firstly I didn't knew that MONTH field starts with zero, so having current month as 11 will give me 10 . Now, if I use now.get(now.MONTH+1) than it returns 46 . And using simply

Java 7 Diamond Operation in method call

与世无争的帅哥 提交于 2021-01-27 02:58:50
问题 This is kind of a follow up question on the discussion: Why doesn't the diamond operator work within a addAll() call in Java 7? From the Java Tutorial, http://docs.oracle.com/javase/tutorial/java/generics/gentypeinference.html Note that the diamond often works in method calls; however, for greater clarity, it is suggested that you use the diamond primarily to initialize a variable where it is declared So, I am a bit confused about the first line. When does diamond work in method calls? A bit

Java 7 Diamond Operation in method call

笑着哭i 提交于 2021-01-27 02:57:12
问题 This is kind of a follow up question on the discussion: Why doesn't the diamond operator work within a addAll() call in Java 7? From the Java Tutorial, http://docs.oracle.com/javase/tutorial/java/generics/gentypeinference.html Note that the diamond often works in method calls; however, for greater clarity, it is suggested that you use the diamond primarily to initialize a variable where it is declared So, I am a bit confused about the first line. When does diamond work in method calls? A bit

Convert Java 8 Lambda Function to Java 7

好久不见. 提交于 2021-01-21 10:27:32
问题 Hey I'm new to coding and I've kind of gotten a hold of Java 8's Lambda functions but I'm trying to convert some of the code I wrote to Java 7 for a project in school and I can't wrap my head around how to make this piece of code identical in functionality but in java 7. Sorry if this is a dumb questions but I can't seem to figure it out. Do I write a custom method and then apply it to the my PriorityQueue. open = new PriorityQueue<>((Object o1, Object o2) -> { Cell c1 = (Cell)o1; Cell c2 =

Maven Fatal alert: protocol_version

半世苍凉 提交于 2020-12-15 05:36:11
问题 I have a problem with Maven. I use as environment Windows 10 Java SE JDK Version 8 update 80 Eclipse Mars 2 with M2Eclipse Maven 3.5.4 I try to use any of the two but the protocol_version error arises. enable TLS 1.2 in the java application. But it does not work. I was looking at this solution: Why am I getting "Received fatal alert: protocol_version" or "peer not authenticated" from Maven Central? but I do not understand how to make the addition of -Dhttps.protocols = TLSv1.2. no where is it

How to get numeric groupid/userid using java7 file attribute apis?

社会主义新天地 提交于 2020-12-02 06:04:21
问题 I can use the following code to get the name of the owner of a file; final PosixFileAttributes basicFileAttributes = Files.readAttributes( path, PosixFileAttributes.class, LinkOption.NOFOLLOW_LINKS ); String ownerName = basicFileAttributes.owner().getName(); But I'm also trying to get hold of the numeric unix id of the user in question. In the debugger I can see it's hiding inside "UnixFileAttributes" (subclass of PosixFileAttributes), but is there any reasonably standard way to get hold of

How to avoid `EC parameters error` using the openjdk:7 Docker image and a Gradle wrapper?

牧云@^-^@ 提交于 2020-08-26 04:48:16
问题 This Dockerfile: FROM openjdk:7 WORKDIR /restdocs/ RUN git clone https://github.com/spring-projects/spring-restdocs.git /restdocs RUN git checkout v1.1.2.RELEASE RUN ./gradlew build built with docker build . -t rest-notes results in the following error: Exception in thread "main" javax.net.ssl.SSLException: java.security.ProviderException: java.security.InvalidKeyException: EC parameters error . What can I do in the Dockerfile to avoid this and make the Gradle wrapper work? 回答1: I was able to

“Javac” doesn't work correctly on Windows 10

纵饮孤独 提交于 2020-08-22 01:56:14
问题 the problem is that I upgraded to Windows 10 and now I'm installing my tools to programming and now that I installed the JDK 7 of Java, when I try to use in the cmd the command: - "javac" The result of this is: "javac" is not recognized as an internal or external command... But I was edited the PATH with the correct link of jdk, because when I use "java", it is ok. Now, I tryed in the console with this command: PATH=%PATH%;"C:\Program Files\Java\jdk1.7.0_79\bin" And when I ejecute this