jasypt

Unable to login DB using jasypt

做~自己de王妃 提交于 2019-12-25 00:03:39
问题 Hi I am using below maven dependency in my Spring boot application. <dependency> <groupId>com.github.ulisesbocchio</groupId> <artifactId>jasypt-spring-boot-starter</artifactId> <version>1.16</version> </dependency> I am using below command to encrypt my DB password. encrypt input="test" password=test algorithm=PBEWithMD5AndDES In my application.properties, i have below properties, spring.datasource.url=jdbc:sqlserver://localhost:1234;database=TEST_DB spring.datasource.username=test spring

Miffed… Simple Code, but … org.jasypt.exceptions.EncryptionOperationNotPossibleException

末鹿安然 提交于 2019-12-23 06:31:37
问题 I have used this code or something similar time and again within the server code on my web apps, but now I am trying to make a command line utility to work with the maintenance backend. Keep on getting a EncryptionOperationNotPossibleException , but can't see what I'm doing wrong in the code. To test the snippet I've used a real encrypted string to make sure it's not the test input. Anybody out there see where in the code this exception would come from? import org.jasypt.exceptions

Receiving NullPointerException while using Jasypt and Spring Security 3.1

↘锁芯ラ 提交于 2019-12-22 09:16:56
问题 I am trying to configure Jasypt with Spring Security. My configuration file looks like this: jdbc.driver=com.mysql.jdbc.Driver jdbc.url=jdbc:mysql://localhost:8090/sample jdbc.username=ENC(*****) where the *****=the salted username jdbc.password=ENC(*****) where the *****=the salted password My servlet xml contains the proper bean setup in this format: <bean id="propertyPlaceholderConfigurer" class="org.jasypt.spring31.properties.EncryptablePropertyPlaceholderConfigurer"> <constructor-arg ref

Making a Value of an Encrypted Field Unique

不羁岁月 提交于 2019-12-22 01:34:52
问题 A JavaEE application uses Jasypt simple encryptor to encrypt usernames stored in a MySQL database using JPA. As the usernames are encrypted, can't make the username column unique. (Refer to use cases below.) A search can be performed before saving a new username to avoid duplicates, but there is a theoretical possibility of creating multiple users names simultaneously. Encrypt('username','key') = 'EncryptedUsername' Decrypt('EncryptedUsername','key') = 'username' Case 1 - Already in the

SpringBoot+Druid+Nutz+Jasypt整合配置多数据源

天大地大妈咪最大 提交于 2019-12-20 18:51:04
【推荐】2019 Java 开发者跳槽指南.pdf(吐血整理) >>> 一 . 引入依赖 <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-web</artifactId> </dependency> <dependency> <groupId>mysql</groupId> <artifactId>mysql-connector-java</artifactId> <scope>runtime</scope> </dependency> <!-- jdbc驱动依赖 --> <dependency> <groupId>org.springframework.boot</groupId> <artifactId>spring-boot-starter-jdbc</artifactId> </dependency> <!-- https://mvnrepository.com/artifact/com.alibaba/druid-spring-boot-starter --> <dependency> <groupId>com.alibaba</groupId> <artifactId>druid-spring-boot-starter</artifactId

Creating a custom Jasypt PropertySource in Springboot

夙愿已清 提交于 2019-12-18 23:36:44
问题 I'm using Spring Boot to create a simple web application which accesses a database. I'm taking advantage of the autoconfiguration functionality for the DataSource by setting up spring.datasource.* properties in application.properties . That all works brilliantly and was very quick - great work guys @ Spring! My companys policy is that there should be no clear text passwords. Therefore I need to have the sping.datasource.password encrypted. After a bit of digging around I decided to create a

Using Jasypt for password based AES encryption with PBKDF2WithHmacSHA1 key

核能气质少年 提交于 2019-12-14 03:52:11
问题 I'm implementing an encryption mechanism where I work, and the security guy's demands are as follows: Create a 256 bit key using PBKDF2WithHmacSHA512, secret password, 256bit salt and 20000 iterations minimum. Salt should be generated using SecureRandom.getInstance("SHA1PRNG"); Encrypt using AES256 with the derived key. I'm trying to use Jasypt's StandardPBEStringEncryptor class encryptor.setPassword(PASSWORD); encryptor.setAlgorithm("AES/CBC/PKCS5Padding"); encryptor

How to hide the password in the command “java -Djasypt.encryptor.password=somepassword -jar name.jar”

断了今生、忘了曾经 提交于 2019-12-12 10:13:24
问题 I am using Jasypt encryption and specifying the property value within ENC() in the properties file. The decryption password is sent through the command-line argument like this java -Djasypt.encryptor.password=somepassword -jar name.jar . Everything is working fine but the problem is when I search for the running process, it shows the password as well. Is there a way to hide the encryption password as well by read it from somewhere? I thought of using the environment variables but that could

Spring : Use Hibernate types without hibernate.cgf.xml

血红的双手。 提交于 2019-12-12 03:18:50
问题 I am working on a Spring-MVC application which uses Hibernate as an ORM tool. We would like to encrypt some columns and for that I am using Jasypt. Now, for that I have to use the annotation @Type, but it requires that there should be a hibernate.cfg.xml file present. Unfortunately, I am not using hibernate.cfg.xml and my sessionFactory and all other configuration are defined in applicationServletContext.xml and root-context.xml. These are the types I want to use : Filename :

How Do I use Jasypt with springs autowire?

江枫思渺然 提交于 2019-12-12 01:29:13
问题 I have see some solutions for this without the autowire but I am trying to get it to work with with the auto wire. I have been trying this since last week but found no solutions that worked in my case, it may be that I am not implementing it correctly so any help would be great. I have a properties file myprops.properties : Wsdl=someurl UserName=admin UserPassword=ENC(encriptedpassword) and in my servlet.xml file I replaced <context:property-placeholder location="classpath*:myprops.properties