jar

问题 I use this code in pom.xml to create a jar file. <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-jar-plugin</artifactId> <configuration> <excludes> <exclude>**/log4j.properties</exclude> </excludes> <archive> <manifest> <mainClass>test.LeanFTest</mainClass> </manifest> </archive> </configuration> </plugin> I got error message: Deployment failed: repository element was not specified in the POM inside distribution UPDATE: I added another plugin in pom.xml. <plugin>

问题 I use this code in pom.xml to create a jar file. <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-jar-plugin</artifactId> <configuration> <excludes> <exclude>**/log4j.properties</exclude> </excludes> <archive> <manifest> <mainClass>test.LeanFTest</mainClass> </manifest> </archive> </configuration> </plugin> I got error message: Deployment failed: repository element was not specified in the POM inside distribution UPDATE: I added another plugin in pom.xml. <plugin>

问题 I use this code in pom.xml to create a jar file. <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-jar-plugin</artifactId> <configuration> <excludes> <exclude>**/log4j.properties</exclude> </excludes> <archive> <manifest> <mainClass>test.LeanFTest</mainClass> </manifest> </archive> </configuration> </plugin> I got error message: Deployment failed: repository element was not specified in the POM inside distribution UPDATE: I added another plugin in pom.xml. <plugin>

问题 I've created what I'm pretty sure is a modular jar file. But if possible, I'd like to double check. Given a jar file, is there a way to determine what modules the compiler would find within it? 回答1: The alternative is to use the jar --describe-module ( -d for short), e.g.: jar --file=myjar.jar --describe-module 回答2: You can list the modules within the jar using the following java tool command:- java -p yourModular.jar --list-modules Edit : You shall preferably make use of the jar command lin

问题 I want to add an alternate entry point to my Spring-Boot application. I would prefer to keep this as a fat jar. Is this possible? According to their documentation, the property loader.main specifies the name of the main class to launch. I tried java -jar MyJar.jar --loader.main=com.mycompany.AlternateMain but the start-class specified in my pom.xml was still run (and if I remove this from the pom.xml then I error during the packaging). Alternatively, I tried java -cp MyJar.jar com.mycompany

问题 I want to add an alternate entry point to my Spring-Boot application. I would prefer to keep this as a fat jar. Is this possible? According to their documentation, the property loader.main specifies the name of the main class to launch. I tried java -jar MyJar.jar --loader.main=com.mycompany.AlternateMain but the start-class specified in my pom.xml was still run (and if I remove this from the pom.xml then I error during the packaging). Alternatively, I tried java -cp MyJar.jar com.mycompany

问题 I want to add an alternate entry point to my Spring-Boot application. I would prefer to keep this as a fat jar. Is this possible? According to their documentation, the property loader.main specifies the name of the main class to launch. I tried java -jar MyJar.jar --loader.main=com.mycompany.AlternateMain but the start-class specified in my pom.xml was still run (and if I remove this from the pom.xml then I error during the packaging). Alternatively, I tried java -cp MyJar.jar com.mycompany

问题 I want to add an alternate entry point to my Spring-Boot application. I would prefer to keep this as a fat jar. Is this possible? According to their documentation, the property loader.main specifies the name of the main class to launch. I tried java -jar MyJar.jar --loader.main=com.mycompany.AlternateMain but the start-class specified in my pom.xml was still run (and if I remove this from the pom.xml then I error during the packaging). Alternatively, I tried java -cp MyJar.jar com.mycompany

问题 Closed . This question needs to be more focused. It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post. Closed 7 years ago . Improve this question Let's assume that after a few years of work I would have a 3D game ready, that can be downloaded by millions of people worldwide, it would be a game running on a client-server model. As far as I understand anyone can look at other people's source code if they

问题 I'm learning Cucumber and I'm getting the FeatureParser error java.lang.NoClassDefFoundError: io/cucumber/core/gherkin/FeatureParser I have imported below jar files gherkin-9.2.0.jar cucumber-core-5.2.0.jar cucumber-java-5.2.0.jar cucumber-junit-5.2.0.jar cucumber-jvm-deps-1.0.6.jar cucumber-plugin-5.2.0.jar i have written code like below LoginTestRunner.java package cucumberTests; import org.junit.runner.RunWith; import io.cucumber.junit.Cucumber; import io.cucumber.junit.CucumberOptions;