invocation

Recursive constructor invocation error can't find solution

扶醉桌前 提交于 2019-12-02 14:24:02
I get the recursive construct overflow invocation error at the four public tuna parts (parts=maybe a class or something else?). It worked on the tutorial but not for me and can't seem to see where public class tuna { private int hour; private int minute; private int second; public tuna() { this(0,0,0); //default } public tuna(int h){ this(h,0,0); //with hours input } public tuna(int h, int m){ this(h,m,0); //with hours and minutes } public tuna(int h, int m, int s){ this(h,m,s); //with hours, minutes and seconds } You're doing a recursive call here: public tuna(int h, int m, int s){ this(h,m,s

Apply/Call method in Javascript: What is the first arguments “this”?

寵の児 提交于 2019-12-02 10:05:03
问题 I am confused about using apply or call method correctly. I know that apply is passing an array to the function and call is passing strings to a function. For example the code below, what does "this"really have to do with the code? if it has nothing to do with this code, then can anyone give me an example when "this" is implementing appropriately? function myFunction(a, b) { return a * b; } myArray = [10,2]; myFunction.apply(this, myArray); 回答1: It's the context for the function. If you have

Apply/Call method in Javascript: What is the first arguments “this”?

倾然丶 夕夏残阳落幕 提交于 2019-12-02 06:46:46
I am confused about using apply or call method correctly. I know that apply is passing an array to the function and call is passing strings to a function. For example the code below, what does "this"really have to do with the code? if it has nothing to do with this code, then can anyone give me an example when "this" is implementing appropriately? function myFunction(a, b) { return a * b; } myArray = [10,2]; myFunction.apply(this, myArray); It's the context for the function. If you have this.something inside the function, it will access that particular property from that context object.

Assuring multicast delegate execution list order in C#?

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-01 05:34:39
After doing some reading I understand that handlers invocation order is the same order as subscribed but it is not guaranteed . So lets say I have : public event MYDEl ev; and subscribers do : ev+=GetPaper; ev+=Print; ev+=EjectPaper; What is the best practice mechanism of preserving +assuring the execution list order ? If it's a field-like event, it will use simple delegate combination as per Delegate.Combine , and that is guaranteed to preserve subscription order. From the docs for the return value: A new delegate with an invocation list that concatenates the invocation lists of a and b in

getUserMedia() in JavaScript normalizes across browsers. Illegal Invocation

江枫思渺然 提交于 2019-12-01 03:18:10
When I try to do the following: var getUserMedia = navigator.getUserMedia || navigator.webkitGetUserMedia || navigator.mozGetUserMedia; // now I try to invoke it with some parameters: getUserMedia(...) // not working! It throws an error "Illegal Invocation" in Chrome. But if I do: navigator.getUserMedia = navigator.getUserMedia || navigator.webkitGetUserMedia || navigator.mozGetUserMedia; // now invoke it with the navigator navigator.getUserMedia(..) // Works I've tried searching a bit, and I read it's a context issue. But I still couldn't understand what's the meaning of that. In the first

How to do dynamic object creation and method invocation in .NET 3.5

房东的猫 提交于 2019-11-30 20:01:58
问题 How does the code looks that would create an object of class: string myClass = "MyClass"; Of the above type, and then call string myMethod = "MyMethod"; On that object? 回答1: Use Type.GetType(string) to get the type object. Use Activator.CreateInstance(Type) to create an instance. Use Type.GetMethod(string) to retrieve a method. Use MethodBase.Invoke(object, object[]) to invoke the method on the object Example, but with no error checking: using System; using System.Reflection; namespace Foo {

Why this kind of function invocation is wrong in JavaScript?

我是研究僧i 提交于 2019-11-28 00:19:16
I'd like to create an anonymous function and then invoke it immediately. 1) This will bring a syntax error. Why? function () { alert("hello"); }(); 2) wrap the function definition with () and it works. (function () { alert("hello"); })(); 3) or, assign the anonymous function to a variable. It works. var dummy = function() { alert("hello"); }(); Why the first way doesn't work? The ECMAScript Language Specification , section 12.4, says: An ExpressionStatement cannot start with the function keyword because that might make it ambiguous with a FunctionDeclaration . So your case 1 is not allowed,

Why are certain function calls termed “illegal invocations” in JavaScript?

99封情书 提交于 2019-11-26 08:09:57
问题 For example, if I do this: var q = document.querySelectorAll; q(\'body\'); I get an \"Illegal invocation\" error in Chrome. I can\'t think of any reason why this is necessary. For one, it\'s not the case with all native code functions. In fact I can do this: var o = Object; // which is a native code function var x = new o(); And everything works just fine. In particular I\'ve discovered this problem when dealing with document and console. Any thoughts? 回答1: It's because you've lost the

Uncaught TypeError: Illegal invocation in javascript

一曲冷凌霜 提交于 2019-11-26 05:17:50
I'm creating a lambda function that executes a second function with a concrete params.This code works in Firefox but not in Chrome, its inspector shows a weird error, Uncaught TypeError: Illegal invocation . What's wrong of my code? var make = function(callback,params){ callback(params); } make(console.log,'it will be accepted!'); The console's log function expects this to refer to the console (internally). Consider this code which replicates your problem: var x = {}; x.func = function(){ if(this !== x){ throw new TypeError('Illegal invocation'); } console.log('Hi!'); }; // Works! x.func();

Uncaught TypeError: Illegal invocation in javascript

纵饮孤独 提交于 2019-11-26 01:54:22
问题 I\'m creating a lambda function that executes a second function with a concrete params.This code works in Firefox but not in Chrome, its inspector shows a weird error, Uncaught TypeError: Illegal invocation . What\'s wrong of my code? var make = function(callback,params){ callback(params); } make(console.log,\'it will be accepted!\'); 回答1: The console's log function expects this to refer to the console (internally). Consider this code which replicates your problem: var x = {}; x.func =